xpath

问题 I'm trying to scrape all CRD# from the search result from this site https://brokercheck.finra.org/search/genericsearch/list (You'll need to redo the search when you click on the link, just type some random stuff for the Individual search) I'm using driver.find_elements_by_xpath to target all CRD numbers on each result page. However, I've been playing around with the paths for a while but the webdriver still can't pick up the CRDs from the site. I currently have (in Python) crds = driver.find

问题 I have problem when trying to create my Telegram's Instant View template, with this error: Element <img> is not supported in <p>: <img src="mysrc" /> So, I decided to replace tag <p> if has <img> tag with <figure> tag @replace_tag(<figure>): $body//p//img But the result is not showing the image. FYI, the <img> doesn't have attributes except src . Sample code: <p><img src="mysrc"/></p> I have no idea, please help me 回答1: The problem with your code is it replaces the <img> . Like what you've

问题 I have an XPath expression as shown below. if(replace(//p[1]/text(),'H','h') = 'hello') then //p[1]/text() else if(//p[1]/text() = 'world') then //p[2]/text() else 'notFound' I want to display which 'if ' expression worked. e.g //p[1]/text() if first 'if' expression worked. 'If' expression can have nested if, for loops and xpath2.0 functions. I can't find any xpath2.0 library for python. So I tried to convert this Js library to python still I can able to split xpath2.0 expression to lexers

问题 if the browser window is in bg, then this line doesn't work. from selenium import webdriver from selenium.webdriver.common.keys import Keys from selenium.webdriver.common.by import By # available since 2.4.0 from selenium.webdriver.support.ui import WebDriverWait # available since 2.26.0 from selenium.webdriver.support import expected_conditions as EC browser = webdriver.Firefox() browser.get(someWebPage) element = WebDriverWait(browser, 10).until( EC.element_to_be_clickable((By.XPATH, '/

问题 i want to fetch '/' separated node name from a given xml such that only node/tag name are getting fetched instead of node/tag value from a given xml. Suppose if i have below xml : <ns:manageWorkItemRequest> <ns:wiFocus> <act:orderDate>2020-03-16T10:30:56.000Z</act:orderDate> <act:orderItem> <agr:instance> <spec1:customerServiceIdentifier>ETHA15302121</spec1:customerServiceIdentifier> <spec1:instanceCharacteristic> <spec1:action> <spec1:code>Modify</spec1:code> </spec1:action> <spec1

问题 i want to fetch '/' separated node name from a given xml such that only node/tag name are getting fetched instead of node/tag value from a given xml. Suppose if i have below xml : <ns:manageWorkItemRequest> <ns:wiFocus> <act:orderDate>2020-03-16T10:30:56.000Z</act:orderDate> <act:orderItem> <agr:instance> <spec1:customerServiceIdentifier>ETHA15302121</spec1:customerServiceIdentifier> <spec1:instanceCharacteristic> <spec1:action> <spec1:code>Modify</spec1:code> </spec1:action> <spec1

问题 I have the next expression: population = tree.xpath('(//tr/td/b/a[contains(text(), "Population")]/../../following-sibling::td/span/following-sibling::text())[1] or' '//tr/td/b/a[contains(text(), "Population")]/../../following-sibling::td/span/text()) which returns 'True'. If I use "|" instead of 'or', it combines values of the 1st and 2nd paths, like this ['11 061 886', '▼'] . How to make the logic like: If the 1st path exists: get the 1st value elif the 2nd path exists: get the 2nd value

问题 I'm getting this error in ElementTree when I try to run the code below: SyntaxError: cannot use absolute path on element My XML document looks like this: <Scripts> <Script> <StepList> <Step> <StepText> </StepText> <StepText> </StepText> </Step> </StepList> </Script> </Scripts> Code: import xml.etree.ElementTree as ET def search(): root = ET.parse(INPUT_FILE_PATH) for target in root.findall("//Script"): print target.attrib['name'] print target.findall("//StepText") I'm on Python 2.6 on Mac. Am

问题 I have list that does not contain any unique div or class. I want to copy the HTML source code for each row below. I cannot find the class for the row. When I open the 'Edit HTML' I see the following code: <tr style="font-size: 11px"> <td class="center"><a href="/countries/1"><img alt="" src="/assets/flags/flag_1-1db156e1884c1b3d5614b55996cf96cd38843b290c7c43bdd5abbdb944b4075c.gif"></a></td> <td><a href="/employees/9526577">Bernard Aarslev</a></td> <td><a href="/clubs/1200094">Kirslev FC</a><

问题 I want to extract data from a table that is very long. For every row in the table I want to copy a specific HTML code. My HTML source code (which I fully want to extract) looks like: <div class="relative"> <div id="stats9526577" class="dark"></div> <img src="/detaljer-1.gif" onmouseover="view_stats(9526577, 14, 13, 4, 7, 10, 8, 6, 3);"> </div> I tried the python code: data = driver.find_elements_by_xpath('//div[@class="relative"]') How can I print the above HTML source code in python using