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问题 I getting error PHP Notice: Undefined index: price in /home/***/public_html/catalog/view/theme/default/template/checkout/cart.tpl on line 57 What do I have to look up to correct this error. Thank you 54 <div> 55 <?php foreach ($product['option'] as $option) { ?> 56 <?php $option_table[$option['name']] = $option['value']; ?> **57 <?php $option_table_price[$option['price']] = $option['price']; ?>** 58 <?php if($option['name'][0] != 's') { ?> 59 - <small><?php echo $option['name']; ?>: <?php

问题 I have such code: $(e).click(function() { console.log(this.href); location.hash = this.href; }); Here e is a <li> element like this: <li href="#about">About</li> location.hash has onchange listener: $(window).hashchange(function() { if (location.hash=="") location.hash="me"; $(".content").spin(); $(".content").load("http://example.com/inc/"+location.hash.substr(1), function() { $(this).spin(false); }); }); UPD: Problem is not with variable accessing, because console.log prints right value of

问题 I have such code: $(e).click(function() { console.log(this.href); location.hash = this.href; }); Here e is a <li> element like this: <li href="#about">About</li> location.hash has onchange listener: $(window).hashchange(function() { if (location.hash=="") location.hash="me"; $(".content").spin(); $(".content").load("http://example.com/inc/"+location.hash.substr(1), function() { $(this).spin(false); }); }); UPD: Problem is not with variable accessing, because console.log prints right value of

问题 I'm using a script to create additional form rows. It loops the $i number for certain text fields When I run this script, the offset is undefined because it doesn't exsist. I need to use the if(isset()) function, but I am unsure how I would place it in the code. Can anyone help? for ($i=0; $i<100; $i++) { if ($text['length'][$i] == "") $text['length'][$i] = "0"; if ($text['bredth'][$i] == "") $text['bredth'][$i] = "0"; if ($text['height'][$i] == "") $text['height'][$i] = "0"; if ($text[

问题 I'm using laravel ffmpeg to create a thumnail fot the video, but when i run the code, it return me Call to undefined method FFMpeg\FFMpeg::fromDisk() I don't know what happen to this error, i'm follow the instruction in github. here is my code. use FFMpeg\FFMpeg; use FFMpeg\FFProbe; $thumbnail_name = md5($request->video_name).'_thumbnail.jpg'; $thumbnail_path = '/assets/' . $request->video_name; FFMpeg::fromDisk('videos') ->open($export_as) ->getFrameFromSeconds(10) ->export() ->toDisk(

问题 I thought methods such as name and email were default in rails? In my static pages view, in profile.html.erb I have: <% if logged_in? %> <% provide(:title, @user.name) %> <% else %> <% provide(:title, 'Profile')%> <% end %> I put in my static_page_controller def profile @user = User.find_by_remember_token(:remember_token) end When I go to the console User.find_by_remember_token("actualtoken").name returns me the appropriate users name, but :remember_token does not. How do I make :remember

问题 i'm new to programming in Java and android... Here is my question, again not sure if the information I provide is sufficient. What I'm trying to do is create a simple two activity app.... So i have the main activity and a user clicks a button and a new activity is launched that sets a new layout. I've looked at the two following websites: http://developer.android.com/guide/components/fragments.html http://www.vogella.com/articles/Android/article.html#fragments_tutorial Both very useful but

问题 I am newly learning Typescript and I run through a strange behavior, I was trying to declare two variables one null and the other undefined as it is a new feature introduced in Typescript 2.0. let myNullVar :null; let myNullVar2 : undefined; console.log(typeof myNullVar); console.log(typeof myNullVar2); I was expecting to see this output: null undefined But it was: undefined undefined More, when I do this: if(typeof myNullVar === 'null'){ console.log('null'); } else if (typeof myNullVar ===

问题 I'm new to object oriented programming in PHP. I included a class and called it, then, inside this class's constructor I'm calling a private function called handleConnections. For some reason, it's giving me a fatal error (undefined function). Any idea why? The class: class Test { function __construct() { handleConnections(); } private function handleConnections() { //do stuff } } It seems flawless and yet I'm getting this error. If anyone has any clue what might be wrong, please tell me.

问题 When a button is clicked I check if something exists in a localstorage key as such: var a = localStorage.getItem('foo'); if (typeof a != 'undefined') { // Function } but if the key doesn't exists at all, it return null. How can I call if not undefined and not null do function , else return true(?) or continue? 回答1: JavaScript has a concept of falsy values... i.e. 0, null , undefined and an empty string. Because of this, you should be able to just check if a is "truthy" (i.e. not one of the