type-resolution

Error “invalid input syntax for integer” for a non-integer?

故事扮演 提交于 2020-01-11 11:31:51
问题 I am using Python and psycopg2. I am attempting to execute a prepared statement with a list of values as such: cur.callproc(prepared_func, prepared_values) psycopg2.DataError: invalid input syntax for integer: "WwLEA6XZ0V" LINE 1: ... fn_approve_external_lead(ARRAY[1004, 2, 1079412, 'WwLEA6XZ0... The function in Postgres looks as follows: CREATE OR REPLACE FUNCTION fn_approve_external_lead( internal_usrid bigint , ofr_src_id bigint , ofr_ext_id varchar , puuid varchar , paid varchar , p_note

Resolving generic type information with TypeTools

霸气de小男生 提交于 2019-12-12 04:45:38
问题 In the implementation of fromMap below I would like to get the runtime type of the generic type T using TypeTools but I am stuck with a NullPointerException in TypeResolver.resolveRawArguments(MapperImpl.class, getClass()); . How can I achieve this? Mapper.java: import java.util.Map; public interface Mapper<T extends Object, S extends Map<String, Object>> { public S toMap(T obj); public T fromMap(S map); } MapperImpl.java import com.fasterxml.jackson.databind.ObjectMapper; import java.util

C# generic method resolution fails with an ambiguous call error

送分小仙女□ 提交于 2019-12-04 18:03:46
问题 Suppose I have defined two unrelated types and two extension methods with the same signature but different type filters: public class Foo {} public class Bar {} public static class FooExtensions { public static TFoo Frob<TFoo>(this TFoo foo) where TFoo : Foo { } public static TFoo Brob<TFoo>(this TFoo foo) where TFoo : Foo { } } public static class BarExtensions { public static TBar Frob<TBar>(this TBar bar) where TBar : Bar { } } Then when I write new Foo().Frob(); I get an error error

Protecting QML source code from plagiarism

落花浮王杯 提交于 2019-11-27 03:31:36
问题 The goal is to come up with a way to protect your QML code from plagiarism. It is a problem, since the way QML was designed and implemented seems to be inexplicably unprotected in this regard. The only QML types which are somewhat protected are those implemented entirely in C++. Qt resource files don't support any degree of protection even if you compress the resource file, extracting data from it is still fairly trivial to anyone with moderate experience QML files stored on the file system