timing

I have a table that has an insert trigger on it. If I insert in 6000 records into this table in one insert statement from a stored procedure, will the stored procedure return before the insert trigger completes? Just to make sure that I'm thinking correctly, the trigger should only be called (i know 'called' isn't the right word) once because there was only 1 insert statement, right? My main question is: will the sproc finish even if the trigger hasn't completed? Your insert trigger will run once for the entire insert statement. This is why it is important to use the inserted temporary table

I'm using QueryPerformanceCounter to do some timing in my application. However, after running it for a few days the application seems to stop functioning properly. If I simply restart the application it starts working again. This makes me a believe I have an overflow problem in my timing code. // Author: Ryan M. Geiss // http://www.geisswerks.com/ryan/FAQS/timing.html class timer { public: timer() { QueryPerformanceFrequency(&freq_); QueryPerformanceCounter(&time_); } void tick(double interval) { LARGE_INTEGER t; QueryPerformanceCounter(&t); if (time_.QuadPart != 0) { int ticks_to_wait =

I want to program a simple audio sequencer on the iphone but I can't get accurate timing. The last days I tried all possible audio techniques on the iphone, starting from AudioServicesPlaySystemSound and AVAudioPlayer and OpenAL to AudioQueues. In my last attempt I tried the CocosDenshion sound engine which uses openAL and allows to load sounds into multiple buffers and then play them whenever needed. Here is the basic code: init: int channelGroups[1]; channelGroups[0] = 8; soundEngine = [[CDSoundEngine alloc] init:channelGroups channelGroupTotal:1]; int i=0; for(NSString *soundName in

What is the Python equivalent of Matlab's tic and toc functions ? Eli Bendersky Apart from timeit which ThiefMaster mentioned, a simple way to do it is just (after importing time ): t = time.time() # do stuff elapsed = time.time() - t I have a helper class I like to use: class Timer(object): def __init__(self, name=None): self.name = name def __enter__(self): self.tstart = time.time() def __exit__(self, type, value, traceback): if self.name: print('[%s]' % self.name,) print('Elapsed: %s' % (time.time() - self.tstart)) It can be used as a context manager: with Timer('foo_stuff'): # do some foo

Afternoon all, I am running into an issue where i need to run one function, then after that is finished, run the next, and do this for four functions, i have been at this for a while trying to find the correct syntax to layout my function calls in and cant seem to find anything to address this specific scenario. html: <div id = "putcontenthereafterajax"> </div><!--end putcontenthereafterajax--> <div id = "putfooterhereafterajax"> </div<!--end putfooterhereafterajax--> jquery: $(window).load(function() { function preload(arrayOfImages) { $(arrayOfImages).each(function(){ $('<img/>')[0].src =

.Net has support for high resolution timing using the System.Diagnostics.Stopwatch class. I understand that the specific resolution that this class uses differs depending on the underlying hardware and can be obtained via the static property Stopwatch.Frequency . This frequency appears to be related to CPU frequency and Stopwatch reads this value and stores it in a static class variable within a static initializer/constructor. Hence I'm now wondering if this class will report incorrect timings if the CPU clock changes? e.g. in systems that alter the CPU clock depending system load. MSDN: *The

My exercise: •Calculate the maximum delay possible using three loops @ 1 MHz clock frequency. (Answer 49.94 s) delay: ldi r23,$FF ;Initialise 3rd loop counter loop3: ldi r24,$FF ;Initialise 2nd loop counter loop2: ldi r25,$FF ;Initialise 1st loop counter loop1: dec r25 ;Decrement the 1st loop counter brne loop1 ;and continue to decrement until 1st loop counter = 0 dec r24 ;Decrement the 2nd loop counter brne loop2 ;If the 2nd loop counter is not equal to zero repeat the 1st loop, else continue dec r23 brne loop3 ret ;Return I'm trying to calculate the maximum delay using those 3 loops the

How can I calculate the execution time in the following code: #include <stdio.h> /* Core input/output operations */ #include <stdlib.h> /* Conversions, random numbers, memory allocation, etc. */ #include <math.h> /* Common mathematical functions */ #include <time.h> /* Converting between various date/time formats */ #include <sys/time.h> #define PI 3.1415926535 /* Known vaue of PI */ #define NDARTS 128 /* Number of darts thrown */ double pseudo_random(double a, double b) { double r; /* Random number */ r = ((b - a) * ((double) rand()/(double) RAND_MAX)) + a; return r; } int main (int argc,