background-process

问题 basically, I have some code like this: while True: number = int(len(oilrigs)) * 49 number += money time.sleep(1) In front of this I have a start up screen. However because of this while true loop, it blocks it from running the actual start up screen. Instead, it just displays this. So how do you put the code in the background? 回答1: Try multithreading. import threading def background(): while True: number = int(len(oilrigs)) * 49 number += money time.sleep(1) def foreground(): # What you want

问题 I'm writing an app in Swift where a timer counts down, much like a countdown clock. To do this I am using this code in my main logics class: func start() { self.timer = Timer.scheduledTimer(withTimeInterval: 1, repeats: true) { timer in self.run() } } Now every time I close the app, the timer stops and I get this error: BackgroundTask: no background task exists with identifier 1 (0x1), or it may have already been ended. Is there any way to continue the timer running in the background? Or do

问题 I'm writing an app in Swift where a timer counts down, much like a countdown clock. To do this I am using this code in my main logics class: func start() { self.timer = Timer.scheduledTimer(withTimeInterval: 1, repeats: true) { timer in self.run() } } Now every time I close the app, the timer stops and I get this error: BackgroundTask: no background task exists with identifier 1 (0x1), or it may have already been ended. Is there any way to continue the timer running in the background? Or do

问题 PROBLEM I am using Python3 and Kivy2. Regardless I would like a popup to automatically start a time consuming method in the background DESCRIPTION In the script call for the popup when a condition is met. if self.header == "loadbag": messageTitle = "machine status" messageLabel = "work in progress" self.popup(messageTitle, messageLabel) The popup method structure is: def popup(self, boxTitle, boxLabel): # popup for showing the activity self.MessageButtonCancel = "ANNULLA" self.MessageBoxTitle

问题 I have already build a a python app and deployed it using Flask and Python . Here is my Skelton of my code. #app.py @app.route('/', methods=['GET']) def login(): '''login process''' @app.route('/reset-password', methods=['GET']) def reset_password(): '''reset password process''' @app.route('/add-psa', methods=['GET']) def add_user(): '''add user process''' if __name__ == '__main__': app.debug = True app.run(use_reloader=False, threaded=True) Deployed app work fine in the Heroku. But sometime

问题 I have already build a a python app and deployed it using Flask and Python . Here is my Skelton of my code. #app.py @app.route('/', methods=['GET']) def login(): '''login process''' @app.route('/reset-password', methods=['GET']) def reset_password(): '''reset password process''' @app.route('/add-psa', methods=['GET']) def add_user(): '''add user process''' if __name__ == '__main__': app.debug = True app.run(use_reloader=False, threaded=True) Deployed app work fine in the Heroku. But sometime

问题 My situation: A browser displays a webpage served by a locally running webserver. When the user clicks a button on the page, I would like to jump to another, possibly already running, application. Working on Windows, I thought about processing the button-click in my locally running webserver and just look for the respective HWND to call SetForegroundWindow on it. However, as it stands, the locally running webserver is not sufficiently privileged to SetForegroundWindow. Those restrictions make

问题 I have a Sidekiq worker that does some background processing and then finally POSTs a success message to a 3rd party API. This message I post is essentially a "thank you" message and can contain HTML. In the message I'd like to link back to my site in a properly formatted way. This naturally sounds like a view to me. I'd love to simply use a view template, render it to HTML and finally post it off to the API. For the life of me, i cannot figure how to render a view from within my Sidekiq

问题 I have a Sidekiq worker that does some background processing and then finally POSTs a success message to a 3rd party API. This message I post is essentially a "thank you" message and can contain HTML. In the message I'd like to link back to my site in a properly formatted way. This naturally sounds like a view to me. I'd love to simply use a view template, render it to HTML and finally post it off to the API. For the life of me, i cannot figure how to render a view from within my Sidekiq

问题 I know I can run my bash script in the background by using bash script.sh & disown or alternatively, by using nohup . However, I want to run my script in the background by default, so when I run bash script.sh or after making it executable, by running ./script.sh it should run in the background by default. How can I achieve this? 回答1: Self-contained solution: #!/bin/sh # Re-spawn as a background process, if we haven't already. if [[ "$1" != "-n" ]]; then nohup "$0" -n & exit $? fi # Rest of