spring-mvc

问题 Is there any way to select current value in dropdown list by Spring MVC by <form:options> ? 回答1: Sets 'selected' as appropriate based on bound value. http://static.springsource.org/spring/docs/2.0.x/reference/spring-form.tld.html#spring-form.tld.options 回答2: Here's my fix to this problem. Its massive, but it works genders : qualifier from java model // model.addAttribute("genders", genders); account : binded modelattribute for spring forms fmt:message : translates m to "Mees" (Estonian) <form

问题 I am looking for help to display the Spring property value in a jsp file. I found one link which is having the same requirement of mine. Click Using spring:eval inside hasRole I am using Spring 2.5 This is my applicationContext-util.xml file: xmlns:util="http://www.springframework.org/schema/util" xmlns:context="http://www.springframework.org/schema/context" http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-2.5.xsd http://www.springframework.org

问题 Is there a way to sort repository query results by querydsl alias? So far I've managed to filter, but sorting results with an error: org.springframework.data.mapping.PropertyReferenceException: No property username found for type User! request: GET /users?size=1&sort=username,desc my rest controller method: @GetMapping("/users") public ListResult<User> getUsersInGroup( @ApiIgnore @QuerydslPredicate(root = User.class) Predicate predicate, Pageable pageable) { Page<User> usersInGroup =

问题 Is there a way to sort repository query results by querydsl alias? So far I've managed to filter, but sorting results with an error: org.springframework.data.mapping.PropertyReferenceException: No property username found for type User! request: GET /users?size=1&sort=username,desc my rest controller method: @GetMapping("/users") public ListResult<User> getUsersInGroup( @ApiIgnore @QuerydslPredicate(root = User.class) Predicate predicate, Pageable pageable) { Page<User> usersInGroup =

问题 Is there a way to sort repository query results by querydsl alias? So far I've managed to filter, but sorting results with an error: org.springframework.data.mapping.PropertyReferenceException: No property username found for type User! request: GET /users?size=1&sort=username,desc my rest controller method: @GetMapping("/users") public ListResult<User> getUsersInGroup( @ApiIgnore @QuerydslPredicate(root = User.class) Predicate predicate, Pageable pageable) { Page<User> usersInGroup =

问题 I want to implement video Player in Angular using Spring Boot Rest API. I can play the video but I can't make video seeking. Every time the video starts over and over again when I use Chrome or Edge. I tried this endpoint: @RequestMapping(value = "/play_video/{video_id}", method = RequestMethod.GET) @ResponseBody public ResponseEntity<byte[]> getPreview1(@PathVariable("video_id") String video_id, HttpServletResponse response) { ResponseEntity<byte[]> result = null; try { String file = "/opt

问题 I want to implement video Player in Angular using Spring Boot Rest API. I can play the video but I can't make video seeking. Every time the video starts over and over again when I use Chrome or Edge. I tried this endpoint: @RequestMapping(value = "/play_video/{video_id}", method = RequestMethod.GET) @ResponseBody public ResponseEntity<byte[]> getPreview1(@PathVariable("video_id") String video_id, HttpServletResponse response) { ResponseEntity<byte[]> result = null; try { String file = "/opt

问题 I get the following error when running codes in Spring Tool Suite. .............................................................................. Port 8080 required by Pivotal tc Server Developer Edition v3.0 is already in use. The server may already be running in another process, or a system process may be using the port. To start this server you will need to stop the other process or change the port number(s). ..............................................................................

问题 In my spring application, I have the following configuration classes for the spring environment: WebAppInitializer.java @Order(value=1) public class WebAppInitializer implements WebApplicationInitializer { @SuppressWarnings("resource") @Override public void onStartup(ServletContext container) { // Create the 'root' Spring application context AnnotationConfigWebApplicationContext rootContext = new AnnotationConfigWebApplicationContext(); rootContext.register(WebAppConfig.class); // Manage the

问题 In my spring application, I have the following configuration classes for the spring environment: WebAppInitializer.java @Order(value=1) public class WebAppInitializer implements WebApplicationInitializer { @SuppressWarnings("resource") @Override public void onStartup(ServletContext container) { // Create the 'root' Spring application context AnnotationConfigWebApplicationContext rootContext = new AnnotationConfigWebApplicationContext(); rootContext.register(WebAppConfig.class); // Manage the