spiral

so I'm very new to C and am wondering how I could create the following spiral shape: This is my comical attempt.. #include <stdio.h> int main(void) { int size; int i,j; printf("Enter size: "); scanf("%d", &size); for (i = 0, j = 0; i < size - 4; i++, j+=2) { int row = 1; while (row <= size) { int column = 1; while (column <= size) { if ((row == 1 + j && column > j && column < size - j)|| (row == size - (j) && column > j && column < size - j) || (column == size - (j) && row > j && row <= size - j) || (column == 1 + j && row > (2+j) && row < size - j)) { printf("*"); } else { printf("-"); }

How to create a spiral graph in R? Is there any package for this kind of analysis? Or is there any other way to visualize time oriented data (regarding periodicity)? For examining periodicity, cycle plots (pdf) work well. There are also many, many functions for analysing periodicity in time series. Start with stl and periodicity in the xts package. Using ggplot2 , you can create a spiral graph like this: library(ggplot2) data(beavers) p <- ggplot(beaver1, aes(time, temp, colour = day)) + geom_line() + coord_polar(theta = "x") p 来源： https://stackoverflow.com/questions/6828350/spiral-graph-in-r

I need to make a spiral pattern made of stars '*' using nested for loops. I managed to make outter lines, now I don't know how to repeat smaller swirls in the same place. What I should have: ********* * ******* * * * * * *** * * * * * * * ***** * * * ********* Any help would be greatly appreciated. After being thoroughly nerd-sniped , I came up with this: #include <stdio.h> void print_spiral(int size) { for (int y = 0; y < size; ++y) { for (int x = 0; x < size; ++x) { // reflect (x, y) to the top left quadrant as (a, b) int a = x; int b = y; if (a >= size / 2) a = size - a - 1; if (b >= size /

I want to make a function that I give it a number and the function returns a spiral from 1 to that number(in 2 dimensional array). For example if I give the number 25 to the function it will return something like this: I tried different ways but nothing worked out. I just cant figure it out. Hope I explained myself properly. Mostly the issue here is one of enumerating coordinates - match numbers to coordinates, then print it out however you want. Start by noticing the two fundamental patterns: (Direction) Move right, then down, then left, then up, then... (this is hopefully obvious) (Magnitude

I wanted to build a spiral square matrix using recursion. I am able to build spiral square matrix using iterative method as below: void main() { int initial_direction = UP , n = MAX , p = 1 ; /* intial_direction is set to UP because we need to start moving right */ int r ,c , a[MAX][MAX]; int row_right = 0 , column_down = n-1 , row_left = n-1 , column_up = 0 ; clrscr (); //Set all elements of the matrix to 0 for(r = 0 ; r < MAX ; r++) { for(c = 0 ; c < MAX ; c++) a[r][c] = 0 ; } //Generate elements of the spiral matrix while(p != n*n+1) { if(initial_direction == UP) { //Move RIGHT r = row

I'm trying to fill an array in spiral order. So far, I can print the array in spiral order, but is there a way to modify the array so that i can fill it in spiral order and then just print the array? I'd like it to go in decreasing order like a countdown. Please help! public class Spiral { public static void main(int m, int n) { // create m by n array of integers 1 through m*n int[][] values = new int[m][n]; for (int i = 0; i < m; i++) for (int j = 0; j < n; j++) values[i][j] = 1 + (m*n)*i + j; // spiral for (int i = (m*n)-1, j = 0; i > 0; i--, j++) { for (int k = j; k < i; k++) System.out