sorting

问题 I am trying to sort a list of User Objects by the order in which User IDs appear in the MessageList Array. The MessageList consists of ID's of people a user is chatting with (ordered by time - using sortwith), which is then to be sent to a User Adapter as a list of Users in the same order as the message list. This is so that username, profile image and other details can be displayed... I have learnt a datasnapshot of the Users from firebase provides as is order and hence needs to be ordered

问题 private static double[] BubbleSortAscending(double[] numberArray) { int arrayLength = numberArray.Length; for(int i = 0; i < arrayLength - 1; i++) { for(int j = 0; j < arrayLength - 1 - i; j++) { if(numberArray[j] > numberArray[j + 1]) { double num = numberArray[j]; numberArray[j] = numberArray[j + 1]; numberArray[j + 1] = num; } } } return numberArray; } Hello, in the code above I have managed to make it so that it sorts an array in ascending order, however I am fully stuck and stumped on

问题 private static double[] BubbleSortAscending(double[] numberArray) { int arrayLength = numberArray.Length; for(int i = 0; i < arrayLength - 1; i++) { for(int j = 0; j < arrayLength - 1 - i; j++) { if(numberArray[j] > numberArray[j + 1]) { double num = numberArray[j]; numberArray[j] = numberArray[j + 1]; numberArray[j + 1] = num; } } } return numberArray; } Hello, in the code above I have managed to make it so that it sorts an array in ascending order, however I am fully stuck and stumped on

问题 I have a list lst1<-list(cxr.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CXRDT", "CXRFIND", "CXRFNDSP", "CXRYN"), cy1.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY1TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy2.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY2TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy24.CSV = c("project", "Subject", "Site", "InstanceName",

问题 I have a list lst1<-list(cxr.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CXRDT", "CXRFIND", "CXRFNDSP", "CXRYN"), cy1.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY1TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy2.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY2TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy24.CSV = c("project", "Subject", "Site", "InstanceName",

问题 I have a list lst1<-list(cxr.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CXRDT", "CXRFIND", "CXRFNDSP", "CXRYN"), cy1.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY1TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy2.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY2TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy24.CSV = c("project", "Subject", "Site", "InstanceName",

问题 I have a list lst1<-list(cxr.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CXRDT", "CXRFIND", "CXRFNDSP", "CXRYN"), cy1.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY1TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy2.CSV = c("project", "Subject", "Site", "InstanceName", "RecordPosition", "CYSHPYN", "CYSHPDT", "CY2TMPT", "CYND", "CYNDSP", "CYDT", "CYTM"), cy24.CSV = c("project", "Subject", "Site", "InstanceName",

问题 I am trying to sort based on frequency and display it in alphabetical order After freq counting , I have a list with (string, count) tuple E.g tmp = [("xyz", 1), ("foo", 2 ) , ("bar", 2)] I then sort as sorted(tmp, reverse=True) This gives me [("foo", 2 ) , ("bar", 2), ("xyz", 1)] How can I make them sort alphabetically in lowest order when frequency same, Trying to figure out the comparator function expected output: [("bar", 2), ("foo", 2 ), ("xyz", 1)] 回答1: You have to sort by multiple keys

问题 I have an array with decimal numbers like this: reihenfolge ########### 100000.00001 1000000.00001 101000.00001 101010.00001 101020.10001 If I sort it without parameters I get the order above. I would expect that the second number is the last entry. I also tried to sort as int or as version or with regex, but until now I didn't find the way I expect. $script:array = $script:array | Sort-Object reihenfolge $script:array = $script:array | Sort-Object { [regex]::Replace($_.reihenfolge, '\d+', {

问题 Lets say you have a list of tuples (last_name, first_name) and you want to sort them reverse alphabetically by last_name and then if two people have the same name for them to be sorted alphabetically by first name. Is there a way to do this with one line? e.g. Sorted(names, key = ?) = [('Zane', 'Albert'), ('Zane', 'Bart'), ('Python', 'Alex'), ('Python', 'Monty')] With two lines I guess you could rely on sort stability and first sort by first name and then sort by last name reversed. 回答1: Here