sorting

问题 Lets say you have a list of tuples (last_name, first_name) and you want to sort them reverse alphabetically by last_name and then if two people have the same name for them to be sorted alphabetically by first name. Is there a way to do this with one line? e.g. Sorted(names, key = ?) = [('Zane', 'Albert'), ('Zane', 'Bart'), ('Python', 'Alex'), ('Python', 'Monty')] With two lines I guess you could rely on sort stability and first sort by first name and then sort by last name reversed. 回答1: Here

问题 I'm making an API call for a list of properties that are unorganized from the API. The data from the API is stored in vuex looks like this: posts:[ { id: 1; title: "Place", acf: { address: { state: "Arkansas", country: "United States" }, }, }, { id: 2; title: "Place 2", acf: { address: { state: "Arkansas", country: "United States" }, }, }, { id: 3; title: "Place 3", acf: { address: { state: "Arkansas", country: "United States" }, }, }, { id: 4; title: "Place 4", acf: { address: { state:

问题 Say I have a vector and its name as follows: vct <- c(67, "apple", 88, "orange", 71) names(vct) <- c("c1", "b2", "d66", "a65", "a11") Now I want the first element 67 to be as is and order the rest on the order of their names. So that it appears: "67", "71", "orange", "apple", "88". 回答1: Do you mean something like this? first <- 67 inds <- match(first, vct) result <- vct[c(inds, setdiff(order(names(vct)), inds))] result # c1 a11 a65 b2 d66 # "67" "71" "orange" "apple" "88" 回答2: You can use -1

问题 This is an extension to my previous question: Below df : In [225]: df = pd.DataFrame({'A': ['a'] * 12, ...: 'B': ['b'] * 12, ...: 'C': ['C1', 'C1', 'C2','C1', 'C3', 'C3', 'C2', 'C3', 'C3', 'C2', 'C2', 'C1'], ...: 'D': ['D1', 'D2', 'D1', 'D3', 'D3', 'D2', 'D4', 'all', 'D1', '0:1:all', 'D3', 'x:all:1'], ...: 'E': [{'value': '4', 'percentage': None}, {'value': 5, 'percentage': None}, {'value': 12, 'percentage': None}, {'value': 9, 'percentage': None}, {'value': '12', 'percentage': None}, {'value

问题 Say I have a vector and its name as follows: vct <- c(67, "apple", 88, "orange", 71) names(vct) <- c("c1", "b2", "d66", "a65", "a11") Now I want the first element 67 to be as is and order the rest on the order of their names. So that it appears: "67", "71", "orange", "apple", "88". 回答1: Do you mean something like this? first <- 67 inds <- match(first, vct) result <- vct[c(inds, setdiff(order(names(vct)), inds))] result # c1 a11 a65 b2 d66 # "67" "71" "orange" "apple" "88" 回答2: You can use -1

问题 I recently saw Quick Sort - Computerphile video on Youtube about how quicksort works (on paper) and I have a question. Imagine that we have an array that contains for example "27,6,19,2,15,9,10" . In first place I choose 10 as pivot and the array becomes like this: 9,2,6 |10| 27,19,15 . Then I choose 6 as pivot for the left unsorted array and it becomes 2 |6| 9 and for the right one I choose 19 as a pivot and the right unsorted array becomes 15 |19| 27 . The question is: Can I choose any

问题 I am doing sorting in asc and desc . I want to make logic if User click first time I want to update it with name asc , when User click second time I want to update it with name desc . It will repeat same manner when ever user click. Code class Example extends React.Component { constructor(props) { super(props); this.state = { Item: 5, skip: 0 } this.handleClick = this.handleClick.bind(this); } urlParams() { return `http://localhost:3001/meetups?filter[limit]=${(this.state.Item)}&&filter[skip]

问题 I am doing sorting in asc and desc . I want to make logic if User click first time I want to update it with name asc , when User click second time I want to update it with name desc . It will repeat same manner when ever user click. Code class Example extends React.Component { constructor(props) { super(props); this.state = { Item: 5, skip: 0 } this.handleClick = this.handleClick.bind(this); } urlParams() { return `http://localhost:3001/meetups?filter[limit]=${(this.state.Item)}&&filter[skip]

问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Improve this question When I print the values in the sorted method, Stream.of("d", "a", "b", "e", "c", "f") .sorted((s1, s2) -> { System.out.printf("sort: %s - %s\n", s1, s2); return s1.compareTo(s2); }).forEach(System.out::println); The output is as follows; sort: a - d sort: b - a sort: b - d sort:

问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Improve this question When I print the values in the sorted method, Stream.of("d", "a", "b", "e", "c", "f") .sorted((s1, s2) -> { System.out.printf("sort: %s - %s\n", s1, s2); return s1.compareTo(s2); }).forEach(System.out::println); The output is as follows; sort: a - d sort: b - a sort: b - d sort: