sorting

问题 Problem setup : Creating a function to take multiple CSV files selected by ID column and combine into 1 csv, then create an output of number of observations by ID. Expected : complete("specdata", 30:25) ##notice descending order of IDs requested ## id nobs ## 1 30 932 ## 2 29 711 ## 3 28 475 ## 4 27 338 ## 5 26 586 ## 6 25 463 I get: > complete("specdata", 30:25) id nobs 1 25 463 2 26 586 3 27 338 4 28 475 5 29 711 6 30 932 Which is "wrong" because it has been sorted by id. The CSV file I

问题 Can you change the MySQL sort by function? I am trying to sort my values according to an arbitrary order. Currently looking for ways to inject a function that might help me out here short of adding a column and modifying the import. This is the order I want: AAA AA+ AA AA- A+ A A- BBB+ BBB BBB- BB+ BB BB- B+ B B- CCC+ CCC CCC- CC This is my result using sort by: A A+ A- AA AA+ AA- AAA B B+ B- BB BB+ BB- BBB BBB+ BBB- C CC CCC CCC+ CCC- EDIT: Attempting but getting syntax errors: CREATE

问题 Can you change the MySQL sort by function? I am trying to sort my values according to an arbitrary order. Currently looking for ways to inject a function that might help me out here short of adding a column and modifying the import. This is the order I want: AAA AA+ AA AA- A+ A A- BBB+ BBB BBB- BB+ BB BB- B+ B B- CCC+ CCC CCC- CC This is my result using sort by: A A+ A- AA AA+ AA- AAA B B+ B- BB BB+ BB- BBB BBB+ BBB- C CC CCC CCC+ CCC- EDIT: Attempting but getting syntax errors: CREATE

问题 I'm trying to define a function named combine to take two lists as parameters and combine them into one sorted list recursively. def combine (l1,l2): if l1 == []: return l2 elif l2 == []: return l1 elif l1 == [] and l2 == []: return [] sort_l = [] index = 0 for num in l1: if num <= l2[0]: sort_l.append(num) index += 1 else: return combine(l2, l1[index:]) return sort_l + l2 It gives me: combine([1,3,5,7,9],[0,2,4,6,8]) -> [8, 9] but should: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] Any advice??? 回答1:

问题 I'm VERY new to Excel VBA. I want to write a function that offsets the cells in the current vector (the range selected by the user) by an amount also specified by the user. The cells must be moved up out of the array by "n", and must then be displayed at the bottom of the same array after the remaining cells have moved up to take the place of the cells shifted up and out of the array. Any advice will be greatly appreciated, the current code I wrote is not working and I know too little to help

问题 I'm generating schedule for the tournament. Each team should play exactly 8 games. Number of teams 2 < n < 36 For sorting teams into pairs I'm using Round Robin algorithm to get a table, example of 6 teams : Then I convert it into the set of pairs: 1 4 2 3 3 2 4 1 5 6 6 5 1 2 2 1 3 5 4 6 5 3 6 4 ... The question is how to sort this set, in order to get schedule, where the same team can't play 2 games in a row. But if it's impossible, minimize the number of exceptions. Example with new

问题 I need to sort close to a 1,00,000 floating point entries in Delphi. I am new to Delphi and would like to know if there are any ready made solutions available. I tried a few language provided constructs and they take an inordinate amount of time to run to completion.(a 5-10 sec execution time is fine for the application) 回答1: why not just implement a quick Sort algorithm? see this simple code program ProjectSortFoat; {$APPTYPE CONSOLE} uses SysUtils; procedure QuickSort(var List: array of

问题 I have an xml <root> <node1> <B>text</B> <A>another_text</A> <C>one_more_text</C> </node1> <node2> <C>one_more_text</C> <B>text</B> <A>another_text</A> </node2> </root> I want get output like: <root> <node1> <A>another_text</A> <B>text</B> <C>one_more_text</C> </node1> <node2> <A>another_text</A> <B>text</B> <C>one_more_text</C> </node2> </root> I tried with some code like: from xml.etree import ElementTree as et tr = et.parse(path_in) root = tr.getroot() for children in root.getchildren():

问题 Consider below df: In [3771]: df = pd.DataFrame({'A': ['a'] * 11, 'B': ['b'] * 11, 'C': ['C1', 'C1', 'C2','C1', 'C3', 'C3', 'C2', 'C3', 'C3', 'C2', 'C2'], 'D': ['D1', 'D2', 'D1', 'D3', 'D3', 'D2', 'D4', 'D4', 'D1', 'D2', 'D3'], 'E': [{'value': '4', 'percentage': None}, {'value': 5, 'percentage': None}, {'value': 12, 'percentage': None}, {'value': 5, 'percentage': None}, {'value': '12', 'percentage': None}, {'value': 'N/A', 'percentage': None}, {}, {'value': 19, 'percentage': None}, {'value':

问题 I want to sort a list but I want it to be sorted excluding the first element. For example: a = ['T', 4, 2, 1, 3] Now I want the list to be sorted but the first element should stay in its place: a = ['T', 1, 2, 3, 4] I know this can be done by using a sorting algorithm but is there a one line way to do it or a more pythonic way to do this? 回答1: You could slice it, sort the trailing slice and concatenate it afterwards: >>> a = a[:1] + sorted(a[1:]) >>> a ['T', 1, 2, 3, 4] 回答2: You can do so by