sorting

问题 I want to sort a list but I want it to be sorted excluding the first element. For example: a = ['T', 4, 2, 1, 3] Now I want the list to be sorted but the first element should stay in its place: a = ['T', 1, 2, 3, 4] I know this can be done by using a sorting algorithm but is there a one line way to do it or a more pythonic way to do this? 回答1: You could slice it, sort the trailing slice and concatenate it afterwards: >>> a = a[:1] + sorted(a[1:]) >>> a ['T', 1, 2, 3, 4] 回答2: You can do so by

问题 I have next structure self.modules = { ["Announcements"] = { priority = 0, -- Tons of other attributes }, ["Healthbar"] = { priority = 40, -- Tons of other attributes }, ["Powerbar"] = { priority = 35, -- Tons of other attributes }, } I need to sort this table by priorty DESC, other values does not matter. E.g. Healthbar first, then Powerbar, and then going all others. // edit. Keys must be preserved. // edit #2 Found a solution, thanks you all. local function pairsByPriority(t) local

问题 I have next structure self.modules = { ["Announcements"] = { priority = 0, -- Tons of other attributes }, ["Healthbar"] = { priority = 40, -- Tons of other attributes }, ["Powerbar"] = { priority = 35, -- Tons of other attributes }, } I need to sort this table by priorty DESC, other values does not matter. E.g. Healthbar first, then Powerbar, and then going all others. // edit. Keys must be preserved. // edit #2 Found a solution, thanks you all. local function pairsByPriority(t) local

问题 I have a list of strings def123, abc999, zzz000, abc123, zzz111 . I want the list sorted such that first three characters are sorted in ascendng order and next three in descending. So the output should be abc999, abc123, def123, zzz111,zzz000 Is this possible? 回答1: Other answers have suggested you implement Comparator . That's no longer necessary with recent utility methods added to the interface in Java 8: list.sort(Comparator .comparing(s -> s.substring(0, 3)) .thenComparing(s -> s.subtring

问题 First of all I would like to point out that my question is different than this one: Sort a numpy matrix based on its diagonal The question is as follow: Suppose I have a numpy matrix A= 5 7 8 7 2 9 8 9 3 I would like to sort the matrix based on its diagonal and then re-arrange the matrix element based on it. Such that now sorted_A: 2 9 7 9 3 8 7 8 5 Note that: (1). The diagonal is sorted (2). The other elements (non-diagonal) re-adjusted by it. How? because diag(A)= [5,2,3] & diag(sorted_A)=

问题 I'm having difficulty understanding the concept that I can pass a 2D array to java's Arrays.sort() method.(I have seen the java docs, the sort method can take only 1D arrays) But then when I try the following code I get error int[][] b={{1,2},{2,3}}; int[] a=b; But the following code works fine int[][] temp = { { 1, 50, 5 }, { 2, 30, 8 }, { 3, 90, 6 },{ 4, 20, 7 }, { 5, 80, 9 }, }; Arrays.sort(temp, new Comparator<int[]>() { @Override public int compare(int[] o1, int[] o2) { return Integer

问题 I have two js arrays, one contains strings, the other color codes, something like: strings = ['one', 'twooo', 'tres', 'four']; colors = ['000000', 'ffffff', 'cccccc', '333333']; I need to sort the first array by the length of the values, longer first. I know I can do something like: strings.sort(function(a, b){ return b.length - a.length; }); But this way I am losing the color assined to each string. How can I sort both arrays keeping the keys pairing? 回答1: Blatantly copied from Sorting with

问题 I was given a task to sort numbers in stack a of integers in ascending order using two stacks a and b . Using eleven operations: sa : swap a - swap the first 2 elements at the top of stack a sb : swap b - swap the first 2 elements at the top of stack b . ss : sa and sb at the same time. pa : push a - take the first element at the top of b and put it at the top of a . pb : push b - take the first element at the top of a and put it at the top of b . ra : rotate a - shift up all elements of

问题 I was given a task to sort numbers in stack a of integers in ascending order using two stacks a and b . Using eleven operations: sa : swap a - swap the first 2 elements at the top of stack a sb : swap b - swap the first 2 elements at the top of stack b . ss : sa and sb at the same time. pa : push a - take the first element at the top of b and put it at the top of a . pb : push b - take the first element at the top of a and put it at the top of b . ra : rotate a - shift up all elements of

问题 I have 2D jagged array. And I want to sort it by any rows. I've searched and found code for sorting by columns private static void Sort<T>(T[][] data, int col) { Comparer<T> comparer = Comparer<T>.Default; Array.Sort<T[]>(data, (x,y) => comparer.Compare(x[col],y[col])); } Can I adapt it for sort by any rows ? Any help is appreciated. Sample of my jagged array (Added) using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class