segment

Assembly: Using the Data Segment Register (DS)

我只是一个虾纸丫 提交于 2019-12-03 09:40:27
问题 Currently I am in the midst of learning x86 assembly for fun, I'm love microcontroller programming, so I'm familiar with assembly. Currently I've been searching high and low for the answer to this question, but can't seem to find it... the DS register, I know it's supposed to point to the global data in my program, but I don't know how it works exactly. I'm using NASM, and in most simple programs I see the following: [org 0x7C00] [bits 16] main: mov ax, 0x0000 mov ds, ax mov al, [msg] mov ah,

how to reassemble tcp segment?

匿名 (未验证) 提交于 2019-12-03 02:52:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: im now developing a project using winpcap..as i have known packets being sniffed are usually fragmented packets. how to reassemble this TCP segements?..any ideas, suggestion or tutorials available?.. this i assume to be the only way i can view the HTTP header... thanks!.. 回答1: tcp is a byte stream protocol. the sequence of bytes sent by your http application is encapsulated in tcp data segments and the byte stream is recreated before the data is delivered to the application on the other side. since you are accessing the tcp datasegments

What if a TCP handshake segment is lost?

匿名 (未验证) 提交于 2019-12-03 02:47:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: In TCP 3-way handshake, 3 segments will be sent (SYN, SYN ACK, ACK). What if the third segment(ACK) is lost? Is the sender going to resend the segment or give up establishing the connection? And how do the two hosts know the segment is lost? 回答1: TCP has a sequence number in all packets. Hence it's easy to know if a packet was lost or not. If a host doesn't get an ACK on a packet he just resends it. In most cases though, even if that ACK was lost, there will be no resending for a very simple reason. Directly after the ACK, the host that

What's the difference of section and segment in ELF file format

匿名 (未验证) 提交于 2019-12-03 02:08:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: From wiki Executable and Linkable Format : The segments contain information that is necessary for runtime execution of the file, while sections contain important data for linking and relocation. Any byte in the entire file can be owned by at most one section, and there can be orphan bytes which are not owned by any section. But what's difference between section and segment? In an executable ELF file, does a segment contain one or more sections? 回答1: But what's difference between section and segment? Exactly what you quoted: the segments

How to programmatically add a UISegmentedControl to a container view

匿名 (未验证) 提交于 2019-12-03 01:58:03
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: How would I define the frame for a UISegmentedControl ? I would like the segmented control to appear at the bottom of a container view i.e UIView . 回答1: this one is perfect i tested..... UIScrollView *scroll = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 0, 320, 435)]; scroll.contentSize = CGSizeMake(320, 700); scroll.showsHorizontalScrollIndicator = YES; NSArray *itemArray = [NSArray arrayWithObjects: @"One", @"Two", @"Three", nil]; UISegmentedControl *segmentedControl = [[UISegmentedControl alloc] initWithItems:itemArray];

Valgrind reporting a segment overflow

匿名 (未验证) 提交于 2019-12-03 01:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: When running my program with valgrind / callgrind I get the following message a lot: ==21734== brk segment overflow in thread #1: can't grow to 0x4a39000 (with different addresses) Note that it is not preceded by a stack overflow message. I can't find any documentation on this message and I have no idea what is overflowing exactly. Can anybody help me figure out what the problem is? Is this a problem of valgrind, or of my program? 回答1: Line 1327 from the valgrind source code points to the user manual, "see section Limitations in user manual"

what is the use of $this->uri->segment(3) in codeigniter pagination

匿名 (未验证) 提交于 2019-12-03 01:10:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: hear is my code public function viewdeletedrecords() { if($this->session->userdata('applicant_firstname') == '') { redirect('papplicant/login') ; } $profile = $this->m_applicant->showdeletedrecods('',''); $total_rows = count($profile) ; $config['base_url'] = base_url().'index.php/papplicant/viewdeletedrecords/' ; $config['per_page'] = '10' ; $config['full_tag_open'] = ' ' ; $config['full_tag_close'] = ' ' ; $config['first_link'] = 'First' ; $config['last_link'] = 'Last' ; $config['use_page_numbers'] = TRUE ; $config['prev_link'] = '<' ;

Assembly Language Absolute addresses and segment registers

匿名 (未验证) 提交于 2019-12-03 00:59:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: a review problem lists these registers in hex: cs = ???? sp = 0300 ax = a66a ip = 01cf ds = 4100 bp = 0003 bx = 1234 ss = 48ee si = 0100 cx = 00ff es = 4cee di = 1000 dx = 0000 The absolute address of the next instruction to be executed is 40f0f. 40f0f -01cf _____ 40d40 / 10 = 40d4 = cs Is the size of the data segment in bytes always equal to the stack segment minus the data segment * 10? 48ee - 4100 = 7ee0. Likewise, is the code segment in bytes always equal to the data segment minus the code segment * 10? 48ee - 40d4 = 81a0. For mov cx,[bx

设有一段英文字母,其字符变量为ENG,并以'$'结束。编写程序,检查单词SUN 在文段中出现的次数,并将次数输出显示

匿名 (未验证) 提交于 2019-12-03 00:26:01
;设有一段英文字母,其字符变量为ENG,并以'$'结束。编写程序,检查单词SUN ;在文段中出现的次数,并将次数输出显示 DATA SEGMENT ENG DB 'SUNHUAHHDUDSUNHCUHDHUSUNHDHSUNHUHSDJSUNHHSUNJKJKSUNKOOSUNSHSUNHUIFHSUNHSAHISAHSUN$' COUNT DW 0 DATA ENDS STACK SEGMENT PARA STACK DW 128 DUP(?) TOP LABEL WORD STACK ENDS CODE SEGMENT ASSUME CS:CODE,SS:STACK,DS:DATA MAIN PROC FAR START: MOV AX,DATA MOV DS,AX MOV AX,STACK MOV SS,AX LEA SP,TOP LEA SI,ENG L0: MOV AL,[SI] CMP AL,'$' JE EXIT CMP AL,'S' JE L1 INC SI JMP L0 L1: INC SI MOV AL,[SI] CMP AL,'$' JE EXIT CMP AL,'U' JE L2 INC SI JMP L0 L2: INC SI MOV AL,[SI] CMP AL,'$' JE EXIT CMP AL,'N' JE L3 INC SI JMP L0 L3:

ConcurrentHashMap的使用场景

匿名 (未验证) 提交于 2019-12-03 00:19:01
先大概的说一下几个map的区别: hashMap :读取快,插入慢,线程不安全 LinkedHashMap :读取快,插入慢 treeMap :排序 concurrentHashMap :线程安全,支持高并发的操作 当项目中的全局变量有多线程操作时需要用concurrentHashMap,若只是单线程则可以使用hashmap。 在多线程环境下使用hashMap会造成的问题: hashMap ,底层是数组+链表 结构,当两个线程同时插入需要扩容的时候,获得改map的size()大小不一样,则会报错。当有两个线程在读,第三个线程正好在对map扩容时,这两个线程就会进入死循环,cup占用率就会高。 concurrentHashMap ,线程安全,读写快,底层实现是一种以空间换时间的结构,创建的时候直接分了16个segment,每个segment实际上存储的还是哈希表,写入的时候先找到对应的segment,然后对segment加锁,写完,解锁。锁segment的时候其他segment还可以继续工作。 文章来源: ConcurrentHashMap的使用场景