scp

bash: check if remote file exists using scp

空扰寡人 提交于 2020-06-24 11:32:21
问题 I am writing a bash script to copy a file from a remote server, to my local machine. I need to check to see if the file is available, so I can take an alternative action if it is not there. I know how to test if a local file exists, however, using scp complicates things a bit. Common sense tells me that one way would be to try to scp the file anyhow, and check the return code from the scp command. Is this the correct way to go about it? If yes, how do I test the return code from the scp

SCP from Windows to Linux using Jenkins pipeline script

跟風遠走 提交于 2020-06-16 19:13:12
问题 I want to do SCP from Windows Jenkins node to Linux server. In this set up, Windows machine is a Jenkins slave and the target server where i want to copy is Linux. Below is my Jenkins pipeline script. Before the below script runs, i am cloning the repository and then building the project which finally creates a .jar file. I want to copy this file to Linux server. stage('SCP JAR file') { steps { bat 'scp /c/Jenkins/workspace/migration/test-project/build/libs/ssupservice-0.0.1-SNAPSHOT.jar

How to get the latest folder that contains a specific file of interest in Linux and download that file using Paramiko in Python?

自古美人都是妖i 提交于 2020-05-14 01:16:37
问题 I am trying to scp a specific file from a remote server to my local machine using Paramiko in Python 3. Background: There is a directory mydir on the destination machine 198.18.2.2 that contains many timestamp directories that start with the name 2020... Destination machine: 198.18.2.2 Source Machine: 198.18.1.1 So far I have managed to construct the command to be executed as follows - cd "$(ls -1d /mydir/20* | tail -1)"; scp -o StrictHostKeyChecking=no email_summary.log root@198.18.1.1:

How to get the latest folder that contains a specific file of interest in Linux and download that file using Paramiko in Python?

淺唱寂寞╮ 提交于 2020-05-14 01:14:55
问题 I am trying to scp a specific file from a remote server to my local machine using Paramiko in Python 3. Background: There is a directory mydir on the destination machine 198.18.2.2 that contains many timestamp directories that start with the name 2020... Destination machine: 198.18.2.2 Source Machine: 198.18.1.1 So far I have managed to construct the command to be executed as follows - cd "$(ls -1d /mydir/20* | tail -1)"; scp -o StrictHostKeyChecking=no email_summary.log root@198.18.1.1:

How to get the latest folder that contains a specific file of interest in Linux and download that file using Paramiko in Python?

允我心安 提交于 2020-05-14 01:12:48
问题 I am trying to scp a specific file from a remote server to my local machine using Paramiko in Python 3. Background: There is a directory mydir on the destination machine 198.18.2.2 that contains many timestamp directories that start with the name 2020... Destination machine: 198.18.2.2 Source Machine: 198.18.1.1 So far I have managed to construct the command to be executed as follows - cd "$(ls -1d /mydir/20* | tail -1)"; scp -o StrictHostKeyChecking=no email_summary.log root@198.18.1.1:

How do I provide a zip file for download from an AWS EC2 instance running Ubuntu?

拜拜、爱过 提交于 2020-04-07 08:31:28
问题 I have created a Flask app that is capable of uploading multiple files to the EC2 instance. My flass app code: import os from flask import Flask, request, render_template, url_for, redirect import flask #Initialize the app by adding: app = Flask(__name__) #Add the below line to create the home page route: @app.route("/") def fileFrontPage(): return render_template('index.html') @app.route("/handleUpload", methods=['POST']) def handleFileUpload(): files = flask.request.files.getlist("photo")

How do I provide a zip file for download from an AWS EC2 instance running Ubuntu?

瘦欲@ 提交于 2020-04-07 08:29:46
问题 I have created a Flask app that is capable of uploading multiple files to the EC2 instance. My flass app code: import os from flask import Flask, request, render_template, url_for, redirect import flask #Initialize the app by adding: app = Flask(__name__) #Add the below line to create the home page route: @app.route("/") def fileFrontPage(): return render_template('index.html') @app.route("/handleUpload", methods=['POST']) def handleFileUpload(): files = flask.request.files.getlist("photo")