schema

How to generate orm mapping classes from sql schema in Java

由 坚强是说给别人听的谎言 提交于 2019-12-20 06:05:56
问题 I have an existing sql schema file for db. Is it possible to generate and re-generate when needed DAO's entities and all other required helper/client classes to access it? I don't mind what will it be -- hibernate, other jpa or something else. 回答1: Asuming you/others are still looking for a solution: I just got the same problem and got it working in Eclipse (slightly different) as follows: created JPA Project and downloaded & added user library in the wizard Also wanted to give a schema-sql

How to reuse elements from another Schema / Namespace (i.e. XHTML) with XML Schema?

由 可紊 提交于 2019-12-20 05:10:30
问题 I'm trying to define a Schema which allows the use of specific (X)HTML elements in certain places. The problem that I'm facing is that the Schema fails compiling. Here's the Schema: <?xml version="1.0"?> <xs:schema xmlns:html="http://www.w3.org/1999/xhtml" xmlns:xs="http://www.w3.org/2001/XMLSchema" > <xs:import namespace="http://www.w3.org/1999/xhtml" schemaLocation="http://www.w3.org/MarkUp/Schema/xhtml11.xsd" /> <xs:element name="foo"> <xs:complexType> <xs:sequence> <xs:element ref="html

How to validate a json schema against the version spec it specifies in Java

由 好久不见. 提交于 2019-12-20 05:03:30
问题 Given a json schema like this.. { "$schema": "http://json-schema.org/draft-04/schema#", "title": "Product", "description": "A product from Acme's catalog", "type": "object", "properties": { "id": { "description": "The unique identifier for a product", "type": "integer" }, "name": { "description": "Name of the product", "type": "string" }, "price": { "type": "number", "minimum": 0, "exclusiveMinimum": true } }, "required": ["id", "name", "price"] } How to validate that this json schema

How to validate a json schema against the version spec it specifies in Java

由 余生长醉 提交于 2019-12-20 05:03:04
问题 Given a json schema like this.. { "$schema": "http://json-schema.org/draft-04/schema#", "title": "Product", "description": "A product from Acme's catalog", "type": "object", "properties": { "id": { "description": "The unique identifier for a product", "type": "integer" }, "name": { "description": "Name of the product", "type": "string" }, "price": { "type": "number", "minimum": 0, "exclusiveMinimum": true } }, "required": ["id", "name", "price"] } How to validate that this json schema

Are JSON schemas necessary for defining the structure of a JSON?

由 眉间皱痕 提交于 2019-12-20 04:29:07
问题 I am asking this because I see that the current JSON schema draft (http://json-schema.org/) proposes to have the schema of JSON in the following way: for the JSON : { "a":"abc" "b": 123 } the schema proposed in the draft is like { "type":"object" "properties":{ "a": {"type":"string"} "b": {"type":"integer"} } } My question here is does the JSON itself not define its structure? Is a separate schema necessary? The schema proposed by the draft validates the JSON that have the above structure and

SSM整合

由 霸气de小男生 提交于 2019-12-20 04:22:48
查看不同MyBatis版本整合Spring时使用的适配包； 下载整合适配包 https://github.com/mybatis/spring/releases 官方整合示例，jpetstore https://github.com/mybatis/jpetstore-6 1. 搭建环境 创建一个 动态的Maven--WEB工程 （New Maven Project--->packing war） 导入SSM需要使用的jar包依赖信息 2 Spring + Springmvc 在web.xml中配置: Springmvc的前端控制器 实例化 Spring容器的监听器 字符编码过滤器 REST 过滤器 创建Spring的配置文件: applicationContext.xml :组件扫描、 连接池、 事务..... 创建Springmvc的配置文件: springmvc.xml : 组件扫描、 视图解析器 <mvc:...> 2.3 MyBatis 创建MyBatis的全局配置文件 编写实体类 Mapper接口 Mapper映射文件 2.4 Spring + MyBatis MyBatis的 SqlSession的创建 . MyBatis的 Mapper接口的代理实现类 整合的配置 ① 导入jar包 MyBatis、MySql、log4j、spring-context、spring

How to convert sample JSON into JSON schema in Java

由 倖福魔咒の 提交于 2019-12-20 03:43:17
问题 I want convert json document into json schema. I googled it but not got the exact idea according to my requirement. here is JSON { "empId":1001, "firstName":"jonh", "lastName":"Springer", "title": "Engineer", "address": { "city": "Mumbai", "street": "FadkeStreet", "zipCode":"420125", "privatePhoneNo":{ "privateMobile": "2564875421", "privateLandLine":"251201546" } }, "salary": 150000, "department":{ "departmentId": 10521, "departmentName": "IT", "companyPhoneNo":{ "cMobile": "8655340546",

Laravel 4 - How to validate unique with multiple fields?

由 最后都变了- 提交于 2019-12-20 03:18:05
问题 I have this schema: Schema::create('members', function(Blueprint $table) { $table->increments('id'); $table->string('lname'); $table->string('fname'); $table->integer('mname'); $table->unique(array('lname', 'fname')); }); My problem is, how to validate these unique fields? I tried this but I know this is wrong... public static $rules = array( 'lname' => 'unique:members', 'fname' => 'unique:members' ); Any help is appreciated.. :) 回答1: You should use this package https://github.com/felixkiss

Java, Validate XML against an embedded schema in WSDL

由 不想你离开。 提交于 2019-12-20 01:38:34
问题 I have a .wsdl file with an embedded schema. I want to validate an XML file/string using that .wsdl file (the same way you would validate against an .xsd ). The schema is between the <types> tag. I have this so far: public boolean validate(String xmlString) { try { // Convert to input stream InputStream xml = new ByteArrayInputStream(xmlString.getBytes()); SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = schemaFactory.newSchema(new

Spring 配置dataSource和sessionFactory

由 安稳与你 提交于 2019-12-20 01:27:39
记得导入dbcp和pool的jar包。 <?xml version="1.0" encoding="UTF-8"?> <beans xmlns=" http://www.springframework.org/schema/beans" xmlns:xsi=" http://www.w3.org/2001/XMLSchema-instance" xmlns:context=" http://www.springframework.org/schema/context" xmlns:aop=" http://www.springframework.org/schema/aop" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.springframework.org/schema/aop http://www
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