regexp-substr

Oracle REGEXP_SUBSTR | Fetch string between two delimiters

懵懂的女人 提交于 2021-02-05 11:42:34
问题 I have a string Organization, INC..Truck/Equipment Failure |C . I want to fetch the sub-string after organization name (after two '..' characters) and before pipe character. So the output string should be - Truck/Equipment Failure . Can you please help. I have been trying forming regexp like this but doesn't seem working. select regexp_substr('Organization, INC..Truck/Equipment Failure |C', '[^.]+',1,2) from dual; 回答1: You may use this. SELECT REGEXP_SUBSTR ('Organization, INC..Truck

How to split a CLOB object using , and : delimiter in Oracle into multiple records

被刻印的时光 ゝ 提交于 2020-06-16 19:10:27
问题 I have a CLOB object sample as shown below. I want to first split this by using delimiter "," and save it in a temporary table for later use. ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0

How to split a CLOB object using , and : delimiter in Oracle into multiple records

房东的猫 提交于 2020-06-16 19:08:34
问题 I have a CLOB object sample as shown below. I want to first split this by using delimiter "," and save it in a temporary table for later use. ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0

How to split a CLOB object using , and : delimiter in Oracle into multiple records

假如想象 提交于 2020-06-16 19:08:12
问题 I have a CLOB object sample as shown below. I want to first split this by using delimiter "," and save it in a temporary table for later use. ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0,ABCDEF:PmId12345RmLn1VlId0

Sql query with regexp_substr is slow and timing out once more records are inserted in table

孤街醉人 提交于 2020-04-30 09:07:52
问题 I have a table cbcm(REPORT_NAME varchar2(30), WHERE_CLAUSE varchar2(2000)) insert into cbcm(REPORT_NAME,WHERE_CLAUSE) values('SE_SUPP2','29786399,29271272,29815958,29821597,29821140,29821791,29850566') Here WHERE_CLAUSE is having integer(id) values which are inserted with "," delimited values. In second table: cust_bug_data(id integer, name varchar2(20)) Which is having id as values from WHERE_CLAUSE in table cbcm . insert into cust_bug_data(29786399,'test') Now I want to list records in cust

Oracle split message with regexp_substr

穿精又带淫゛_ 提交于 2020-01-24 00:19:11
问题 I need to split message: 500 Oracle Parkway.Redwood Shores.*.=13 Now I have a bit worked solution for Substr1/2/4 SELECT '500 Oracle Parkway.Redwood Shores.*.=13' string1, REGEXP_SUBSTR('500 Oracle Parkway.Redwood Shores.*.=13','.[^.]+') "SUBSTR1" , replace(REGEXP_SUBSTR('500 Oracle Parkway.Redwood Shores.*.=13','[$.]+ [^.]+'),'.',null) "SUBSTR2" , REGEXP_SUBSTR('500 Oracle Parkway.Redwood Shores.*.=13','[$.]+.[$.]+[^.]') "SUBSTR3" , REGEXP_SUBSTR('500 Oracle Parkway.Redwood Shores.*.=13','[^

Oracle extract json fields using regular expression with oracle regexp_substr

若如初见. 提交于 2019-12-25 18:23:52
问题 I'm using Oracle query with regular expression and oracle regexp_substr to extract json fields from JSON string. whene I try to get the value of code key it working well and its value, but whene i try to get the value of results key it return null. I'm using this query: select regexp_replace(regexp_substr('{"code":"001","message":"success","transactionId":437,"results":{"name":"osama"}}','"results":\s*("(\w| )*")', 1, level), '"results":\s*"((\w| )*)"', '\1', 1, 1) results from dual connect

Regular Expression for REGEXP_SUBSTR in Oracle

落花浮王杯 提交于 2019-12-22 13:31:40
问题 I have the following text to search: #S7Z OK #Wed Feb 18 07:16:26 GMT 2015 expiration=10.0 lastModified=1424192425832 length=466472 path=/name/_master_/563/5638ad54-8079-4399-ba2b-3257b6e6c7fd.pdf userType= The words proceeding each = are the names of properties. For each property name, I'd like to get the property value. That means I'm looking for a regular expression to use with regexp_substr to get the value of each known property. Something like this: SELECT REGEXP_SUBSTR( '#S7Z OK #Wed