Oracle REGEXP_SUBSTR | Fetch string between two delimiters
问题 I have a string Organization, INC..Truck/Equipment Failure |C . I want to fetch the sub-string after organization name (after two '..' characters) and before pipe character. So the output string should be - Truck/Equipment Failure . Can you please help. I have been trying forming regexp like this but doesn't seem working. select regexp_substr('Organization, INC..Truck/Equipment Failure |C', '[^.]+',1,2) from dual; 回答1: You may use this. SELECT REGEXP_SUBSTR ('Organization, INC..Truck