regex

问题 Currently, I need to apply a transformation on bellow third column: ACAC | 0 | 01 ACAC | 0 | 0101 ACAC | 0 | 0102 ACAC | 0 | 010201 I need to transform "010201" to "01/02/01" . So first I need to: trim all ending 0 characters split each 2 numbers and add "/" character. The context of this transformation is inside solr data import handler transformers, but it's using java regex library internally. Is there anyway to get that? I've tried using this regex: Currently, I need to apply a

问题 Jmeter URL patterns to exclude under workbench - not excluding patterns that are giving there. Can we give direct URL's. i have a list of URL that needs to be excluded from the recorded script. Example: 'safebrowsing.google.com` 'safebrowsing-cache.google.com' 'self-repair.mozilla.org' i'm giving these directly under patters to exclude. or do i need to give as a regular expression only. Can someone provide more info whether to use regular expression or direct url can be provided under

问题 I'm using the following regex to match strings inside brackets: \((.*?)\) But this matches this: (word) and this too: ( word ) I need to modify it to only match the first case: words inside brackets with no spaces around: (word) Any ideas? Thanks in advance 回答1: Use lookahead/lookbehind to disallow space after the opening parenthesis and before the closing parenthesis: \((?!\s)[^()]+(?<!\s)\) (?!\s) and (?<!\s) mean "not followed by / not preceded by a space". The part in the middle, [^()]+

问题 I need to match numbers that are not preceeded by "/" in a group. In order to do this I made the following regex: var reg = /(^|[^,\/])([0-9]*\.?[0-9]*)/g; First part matches start of the string and anything else except "/", second part matches a number. Everything works ok regarding the regex (it matches what I need). I use https://regex101.com/ for testing. Example here: https://regex101.com/r/7UwEUn/1 The problem is that when I use it in js (script below) it goes into an infinite loop if

问题 I have a character vector which looks like this "9/14/2007,,,,88.22" "9/21/2007,,,,92.53" "9/28/2007,,,,92" "10/5/2007,,,,92.85" Now i need to remove all the elements before the 4 commas. So at the end it should look like this "88.22" "92.53" "92" "92.85" I have tried the following code gsub("[^0-9.]", "", x) where x is my character vector but this keeps the integers before the commas (which are dates). "914200788.22" "921200792.53" "928200792" "105200792.85" Also the number of elements to

问题 I would to like find and replace strings within double curly brackets, inclusive of the brackets themselves. For example: <a href="#">{{hello}}</a> should ideally return: {{hello}} I found this expression: {{(.*?)}} here However this only returns text between the brackets. Ie. With this expression, the example above would return: "hello" , rather than "{{hello}}" 回答1: You can just move the ( and ) to include the brackets within the group. Try: ({{.*?}}) . I highly recommend a regex tester for

问题 Using Sublime Text 3 I want to extract only uppercase words and expressions from a text. Example: Hello world! It's a SUNNY DAY for all. If I use the find tool, I can extract all uppercase words separately by using this regex: \b[A-Z]+\b The results are SUNNY and DAY, but I would like to consider SUNNY DAY as a whole to extract trough the find tool, without leaving behind simple words like in: It's SUNNY today. 回答1: You can simply use \b[A-Z]+(?:\s+[A-Z]+)*\b See regex demo I added (?:\s+[A-Z

问题 I have a dictionary of regular expressions and I want to count the matches in the dictionary with topics and regex that include compound words. import pandas as pd terms = {'animals':"(fox|russian brown deer|bald eagle|arctic fox)", 'people':'(John Adams|Rob|Steve|Superman|Super man)', 'games':'(basketball|basket ball|bball)' } df=pd.DataFrame({ 'Score': [4,6,2,7,8], 'Foo': ['Superman was looking for a russian brown deer.', 'John adams started to play basket ball with rob yesterday before

问题 I want to store a series of pre-tested regexes in a config file, and read and apply them at runtime. However, because they're commonly packed with escape characters, by the time I've loaded them up into memory, and populated them into a dict, they've been escaped to death. How can I preserve the integrity of my regex definitions, so that they will re.compile ? Alternately, given that many of the post-escape strings end up in a form with \x00 characters, how do I convert these back into a form

问题 Is there a way to exclude subfolders of a website using Stylish? @-moz-document domain("www.website.com") { } Will affect all pages of website.com. The problem is, this website also hosts a wiki ( www.website.com/wiki/* ), which has an entirely different style. Some of the Stylish CSS affects this wiki as well, which I want to avoid. Is there any way to do this? I've read: Disable stylish on certain sites in Firefox, but this is for a global style, which I don't have. I should say I don't