Python regex to find all case of curly brackets, inclusive of brackets

问题

I would to like find and replace strings within double curly brackets, inclusive of the brackets themselves.

For example:

<a href="#">{{hello}}</a>

should ideally return:

{{hello}}

I found this expression: {{(.*?)}} here

However this only returns text between the brackets. Ie. With this expression, the example above would return: "hello", rather than "{{hello}}"

回答1:

You can just move the ( and ) to include the brackets within the group.

Try: ({{.*?}}). I highly recommend a regex tester for this kind of work.

回答2:

I'm assuming you're using re.findall() which only returns the contents of capturing groups, if they are present in the regex.

Since you don't want them, just remove the capturing parentheses:

matches = re.findall("{{.*?}}", mystring)

When using re.sub() for replacing, the original regex will work just fine.

来源：https://stackoverflow.com/questions/35485949/python-regex-to-find-all-case-of-curly-brackets-inclusive-of-brackets