rank

I need some help dealing with ties when ranking in MySQL. For example: PLAYER | POINTS Mary: 90 Bob: 90 Jim: 65 Kevin: 12 Bob and Mary should both be ranked #1. Jim should be #3. Kevin should be #4. MySQL: SET @rank=0; SELECT @rank:=@rank +1 as rank, player, points FROM my_table How can I change the SELECT statement so that the ranking is correct in the case of ties? My real life problem is more complicated, but if I understand how to solve the above, then I should be set. Assuming name is unique SELECT t1.name, (SELECT COUNT(*) FROM table_1 t2 WHERE t2.score > t1.score) +1 AS rnk FROM table_1

I have this table : id ref data 1 111 data1 2 111 data2 3 111 data3 4 111 data4 5 222 data1 6 222 data2 7 222 data3 8 333 data1 9 333 data2 and I'd like to insert a new field, called for example order , where for each ref, I'll set a crescent value. So the output should be : id ref data order 1 111 data1 1 2 111 data2 2 3 111 data3 3 4 111 data4 4 5 222 data1 1 6 222 data2 2 7 222 data3 3 8 333 data1 1 9 333 data2 2 can I do this with a simple query? EDIT The example above is just an example. This is my real table on the database : CREATE TABLE `items` ( `id` int(11) unsigned NOT NULL auto

I have a dataframe as below. Originally it was just two columns/variables -"Timestamp" (which contains date and time) and "Actor". I broke down the "Timestamp" variable into "date" and "time" and then "time further down into "hours" and "mins". This then gives the following structure dataf<-structure(list(hours = structure(c(3L, 4L, 4L, 3L, 3L, 3L, 6L, 6L, 6L, 6L, 6L, 2L, 2L, 2L, 2L, 5L, 5L, 5L, 1L, 1L, 2L, 2L), .Label = c("9", "12", "14", "15", "16", "17"), class = "factor"), mins = structure(c(17L, 1L, 2L, 14L, 15L, 16L, 3L, 4L, 6L, 6L, 7L, 9L, 9L, 13L, 13L, 10L, 11L, 12L, 2L, 5L, 8L, 8L),

HI, I actually posted similar (or same?) question yesterday, but I thought I need to post a new question since I have short, but clear question. I have the following table. id point 1 30 2 30 3 29 4 27 5 28 6 26 what I want: get all the users order by rank. user #1 and #2 should have 1 as their rank value because they both have 30 points I want to query a rank by user id. I like to get 1 as the result of my rank when I query user #1 and #2 because both of them have 30 points Added on: 3/18 I tried Logan's query, but got the following result id point rank 1 30 1 2 30 1 3 29 3 4 27 5 5 28 4 6 26

I am trying to rank a pandas data frame based on two columns. I can rank it based on one column, but how can to rank it based on two columns? 'SaleCount', then 'TotalRevenue'? import pandas as pd df = pd.DataFrame({'TotalRevenue':[300,9000,1000,750,500,2000,0,600,50,500], 'Date':['2016-12-02' for i in range(10)], 'SaleCount':[10,100,30,35,20,100,0,30,2,20], 'shops':['S3','S2','S1','S5','S4','S8','S6','S7','S9','S10']}) df['Rank'] = df.SaleCount.rank(method='dense',ascending = False).astype(int) #df['Rank'] = df.TotalRevenue.rank(method='dense',ascending = False).astype(int) df.sort_values([