MySQL Rank in the Case of Ties

空扰寡人 提交于 2019-12-01 14:47:05

Assuming name is unique

SELECT t1.name, (SELECT COUNT(*) FROM table_1 t2 WHERE t2.score > t1.score) +1
AS rnk
FROM table_1 t1
SELECT players.*, COUNT(higher_ranking.id) + 1 AS rank
    FROM players
    LEFT JOIN players AS higher_ranking
        ON higher_ranking.points > players.points
    GROUP BY players.id

On Postgres, you could use window functions RANK() to achieve this, which is much nicer. I don't know of anything like that for MySQL.

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