prepared-statement

问题 This question already has answers here : MySQLSyntaxErrorException near “?” when trying to execute PreparedStatement (2 answers) Closed 1 year ago . I am trying to execute the following code package jdbclesson; import java.sql.*; public class PreparedQuery { public static void main(String[] args) throws Exception { String url = "jdbc:mysql://localhost:3306/alien?useSSL=false"; String uname = "root"; String pass = "ma123"; String query = "UPDATE student SET username= ? where userid= ? ";

问题 This question already has answers here : MySQLSyntaxErrorException near “?” when trying to execute PreparedStatement (2 answers) Closed 1 year ago . I am trying to execute the following code package jdbclesson; import java.sql.*; public class PreparedQuery { public static void main(String[] args) throws Exception { String url = "jdbc:mysql://localhost:3306/alien?useSSL=false"; String uname = "root"; String pass = "ma123"; String query = "UPDATE student SET username= ? where userid= ? ";

问题 How do I insert a BIT value in MySQL using a PDO Prepared Statement? Below is what I tried and my results. <?php function testIt($value) { $sql='INSERT INTO test(id,data) VALUES(?,?)'; $stmt=db::db()->prepare($sql); $stmt->execute(array(0,$value)); $id=db::db()->lastInsertId(); $sql='SELECT * FROM test WHERE id='.$id; $stmt=db::db()->query($sql); $rs=$stmt->fetch(PDO::FETCH_ASSOC); echo("Test for {$value} returns id {$rs['id']} and data {$rs['data']}<br>"); } date_default_timezone_set(

问题 How do I insert a BIT value in MySQL using a PDO Prepared Statement? Below is what I tried and my results. <?php function testIt($value) { $sql='INSERT INTO test(id,data) VALUES(?,?)'; $stmt=db::db()->prepare($sql); $stmt->execute(array(0,$value)); $id=db::db()->lastInsertId(); $sql='SELECT * FROM test WHERE id='.$id; $stmt=db::db()->query($sql); $rs=$stmt->fetch(PDO::FETCH_ASSOC); echo("Test for {$value} returns id {$rs['id']} and data {$rs['data']}<br>"); } date_default_timezone_set(

问题 I am well-versed in the old php mysql extension. I am working on my first script that uses the mysqli extension. I am going to be inserting a large number of rows into a table that are being generated dynamically. Is it possible to use a prepared statement to insert multiple rows into a table without previously knowing the number of new rows that will be inserted each time? $stmt = $mysqli->prepare("INSERT INTO `activity` (`id`, `name`, `type`) VALUES ?, ?, ?;"); If that isn't possible, which

问题 I'm trying to convert this query from a normal pg_query() to pg_prepare() & pg_execute() . Its a generic query that I reuse when I need to update different tables from different pages in order to keep my code clean. I've just realised that parameters can be used only in where clauses and not in other parts of the query. $res = pg_query($con, "update " . $_REQUEST['table'] . " set " . $_REQUEST['colname'] . "=" . $colval . " where " . $_REQUEST['colnameid'] . "=" . $_REQUEST['colvalid'] . "

问题 I'm having some issues with an update on table, when used with a prepared statement. Seems like mysql is updateing a wrong column which was not even specifed in the update command. prepare: drop table test1; create table test1( id int not null, show_from timestamp not null, updated_at timestamp NULL DEFAULT NULL ); insert into test1(id, show_from, updated_at) values(1, '2018-01-11 12:10:11.19808', '2019-04-15 11:50:00.704748'); do this in one batch: UPDATE test1 SET show_from='2018-04-15 11

问题 I'm having some issues with an update on table, when used with a prepared statement. Seems like mysql is updateing a wrong column which was not even specifed in the update command. prepare: drop table test1; create table test1( id int not null, show_from timestamp not null, updated_at timestamp NULL DEFAULT NULL ); insert into test1(id, show_from, updated_at) values(1, '2018-01-11 12:10:11.19808', '2019-04-15 11:50:00.704748'); do this in one batch: UPDATE test1 SET show_from='2018-04-15 11

问题 I am building a web app that imports data from data feeds in php/mysql. I import the data into a buffer/temp holding table. As each data format is different I choose the column to select based on the particular source. I am having trouble getting this query to work in this context : $stmt = $this->dbObj->prepare("SELECT mk.PK_phone_maker, b.?, b.phoneDescription b.thumbPic, FROM buffer_table b left join mobile_phone pm on b.? = pm.phoneModel LEFT JOIN phone_maker mk on mk.CompanyName = b.?

问题 I'd like to know how to bind values in where clause. I have understood that is something that MUST be done for security reasons. $db = JFactory::getDbo(); $query = $db->getQuery(true); $query ->select("*") ->from($db->quoteName("food")) ->where("taste = :taste") ->bind(':taste', 'sweet'); $db->setQuery($query); $rows = $db->loadAssocList(); I'm getting this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use