post

Alfresco: linking directly to workflow

房东的猫 提交于 2020-02-06 07:23:47
问题 I would like to start a workflow from the site links dashlet on my Alfresco site. Using Firebug to examine the POST gives me a URL that works, but it only displays the form without any UI: http://localhost:8081/share/service/components/form?htmlid=template_x002e_start-workflow_x002e_start-workflow_x0023_default-startWorkflowForm-alf-id1&itemKind=workflow&itemId=activiti%24orpWorkflow&mode=create&submitType=json&showCaption=true&formUI=true&showCancelButton=true&destination= Is this possible?

js 模拟form表单post提交

大憨熊 提交于 2020-02-06 04:04:09
1 var generateHideElement = function (name, value) { 2 var tempInput = document.createElement("input"); 3 tempInput.type = "hidden"; 4 tempInput.name = name; 5 tempInput.value = value; 6 return tempInput; 7 } 8 9 var form = document.createElement("form"); 10 document.body.appendChild(form); 11 12 13 var jData = generateHideElement("jData", "11"), 14 jsongroups = generateHideElement("jsongroups", "22"), 15 cacheKey = generateHideElement("cacheKey", "33"), 16 execlName = generateHideElement("execlName", "44"); 17 18 19 20 21 form.appendChild(jData); 22 form.appendChild(jsongroups); 23 form

Uniquely identifying a user from a POST request with node.js

▼魔方 西西 提交于 2020-02-06 02:38:40
问题 I'm making a browser game that utilizes voice communication, to record audio in the browser I'm using wami-recorder which uses flash to send a POST request to the server with the recorded audio, only it doesn't seem to give me any control over the request. My game server, which is written in node.js/express, needs to be able to identify the client from the audio it's received, as well as pair it with the correct web socket from socket.io I've considered using the ip address, however it wouldn

nodejs的get与post

◇◆丶佛笑我妖孽 提交于 2020-02-05 21:43:20
get 由于GET请求直接被嵌入在路径中,URL是完整的请求路径,包括了?后面的部分,因此你可以手动解析后面的内容作为GET请求的参数。 get.js var http = require ( 'http' ) ; var url = require ( 'url' ) ; var util = require ( 'util' ) ; http . createServer ( function ( req , res ) { var data = url . parse ( req . url , true ) ; console . log ( 'Request Data: ' ) ; console . log ( util . inspect ( data ) ) ; var params = data . query ; res . writeHead ( 200 , { 'Content-Type' : 'text/plain' } ) ; res . write ( 'Website Name: ' + params . name ) ; res . write ( '<br>' ) ; res . write ( 'Website Url: ' + params . url ) ; res . end ( ) ; } ) . listen ( 8888 ) ;

前端需要了解的HTTP协议

此生再无相见时 提交于 2020-02-05 20:49:51
目录 HTTP协议 HTTP概述 HTTP之URL HTTP状态码 HTTP首部 HTTP首部字段 HTTP通用首部字段 HTTP请求首部字段 HTTP工作原理 HTTP报文内的HTTP信息 HTTP之请求消息Request HTTP之响应Response get请求和post请求 get请求 post请求 post和get请求的区别 HTTP协议 @ HTTP概述 http协议是用来规定客户端和服务器间通信的报文的格式的; 客户端和服务器端通信的内容称为报文; 客户端和服务器间通信是基于请求和响应的模式的;客户端给服务器发送请求报文,服务器给客户端返回响应报文; 服务器:接收请求返回响应; 请求 request 响应 response http客户端和服务器端 客户端发送给服务器的请求就相当于是客户端给服务器写信(请求报文); 服务器返回的相应就相当于服务器给客户端写回信(响应报文); http协议就是规定客户端和服务器端传输的协议; HTTP之URL HTTP使用统一资源标识符(Uniform Resource Identifiers, URI)来传输数据和建立连接。URL是一种特殊类型的URI,包含了用于查找某个资源的足够的信息; URL,全称是UniformResourceLocator, 中文叫统一资源定位符,是互联网上用来标识某一处资源的地址。 以下面这个URL为例

DART & GAE : Why a POST method send from dart can't be evaluate in GAE?

主宰稳场 提交于 2020-02-05 14:47:31
问题 I have a Dart code used to send an HttpRequest with a POST method to my GAE WepApp2 application. The dart code is executed in chromium and serve by Chrome dev editor. I add in my GAE code some headers to avoid the XHR error in the client side. The dart code send the datas to my GAE app but I can't read the data with self.request.POST.get("language")) and the app never enter in def post(self): section but with self.request.body I can read the data. Could you explain that and provide some

DART & GAE : Why a POST method send from dart can't be evaluate in GAE?

不羁岁月 提交于 2020-02-05 14:44:36
问题 I have a Dart code used to send an HttpRequest with a POST method to my GAE WepApp2 application. The dart code is executed in chromium and serve by Chrome dev editor. I add in my GAE code some headers to avoid the XHR error in the client side. The dart code send the datas to my GAE app but I can't read the data with self.request.POST.get("language")) and the app never enter in def post(self): section but with self.request.body I can read the data. Could you explain that and provide some

上传文件multipart form-data boundary 说明

霸气de小男生 提交于 2020-02-05 12:04:02
post表单部分是这样:    模拟表单提交返回如是    查看原始报文发现两次提交的报文差异       ...... 表单中既然没有出现--开头的两行 那么post的时候如何在首尾添加呢 我在post中提交的是键值数据 这就犯了难 后来发现在headers部分发现了端倪    同样的数据出现了 搜索之      找到 上传文件multipart form-data boundary 说明 了解其为分割提交数据的 那就好办了   post 部分使用 String类型   headers 部分添加 指定 Content-Type 提交看下 成功 来源: https://www.cnblogs.com/feiyucha/p/12263019.html

Get and post method in html

大兔子大兔子 提交于 2020-02-05 06:28:06
问题 what is the meaning of these three statements: If get method is used and if the page is refreshed it would not prompt before the request is submitted again. If the response of the page is always same for the posted query then use GET example database searches If the service associated with the processing of a form has side effects (for example, modification of a database or subscription to a service), the method should be POST. The second one I understand partially: That the same result is

Django组件-forms组件

醉酒当歌 提交于 2020-02-05 05:39:54
forms组件 django中的Form组件有以下几个功能: 生成HTML标签 验证用户数据(显示错误信息) HTML Form提交保留上次提交数据 初始化页面显示内容 校验字段功能 之前写的视图函数,提交的数据,没有做校验,就调教到数据库里面了。这样是不对的。 比如:用户名,必须要符合一定的长度。密码复杂度,等等。 forms组件最大的作用,就是做数据校验。 普通做法,一个一个写校验规则,没有解耦。校验规则,都在视图函数里面。 新建项目formDemo 新建urls.py ,新增路径index 1 from app01 import views 2 urlpatterns = [ 3 path('admin/', admin.site.urls), 4 path('index/', views.index), 5 ] 修改views.py ,新增index视图函数,form组件先放到视图函数 单独起一个类,后续会分离出来 from django.shortcuts import render # Create your views here. from django import forms # 必须导入模块 class DemoForm(forms.Form): # 必须继承Form #限制数据为字符串,最大长度32 name = forms.CharField(max