matrix

问题 Following Jama Matrices are defined in my code: P: 3*3 Matrix I: 3*3 identity Matrix K: 3*2 Matrix H: 2*3 Matrix Q: 3*3 Matrix Following is my code snippet: private Matrix getP() { P= (I.minus(K.times(H))).times(Q); Log.d("csv", "P is calculated"); return P; } While running the code, at first iteration it works, i.e, P is calculated is printed at the Logcat. However, it happens only once and the application gets stopped. Following is the error: java.lang.IllegalArgumentException: Matrix inner

问题 I know how to find indices with a negative value from a matrix. matrix(matrix<0) = %something should be done; But don't know how to replace their values with the nearest index's value that happens to be positive. The nearest index here should be in the same row where the observed index is laid. If there is no index with a positive value in the row, 0 should be interpolated to every index of that row. If there is more than one index that is the nearest to the observed index in the same row,

问题 I know how to find indices with a negative value from a matrix. matrix(matrix<0) = %something should be done; But don't know how to replace their values with the nearest index's value that happens to be positive. The nearest index here should be in the same row where the observed index is laid. If there is no index with a positive value in the row, 0 should be interpolated to every index of that row. If there is more than one index that is the nearest to the observed index in the same row,

问题 This question already has answers here : Puzzle: Find largest rectangle (maximal rectangle problem) (7 answers) Closed 6 years ago . Given a binary matrix, I have find out the maximum size square sub-matrix with all 1 s. For example, consider the below binary matrix: 0 1 1 0 1 1 1 0 1 0 0 1 1 1 0 1 1 1 1 0 1 1 1 1 1 0 0 0 0 0 The maximum square sub-matrix with all set bits is 1 1 1 1 1 1 1 1 1 I searched the web for solutions and I found a relation to construct an auxiliary matrix: If M[i][j]

问题 This question already has answers here : Puzzle: Find largest rectangle (maximal rectangle problem) (7 answers) Closed 6 years ago . Given a binary matrix, I have find out the maximum size square sub-matrix with all 1 s. For example, consider the below binary matrix: 0 1 1 0 1 1 1 0 1 0 0 1 1 1 0 1 1 1 1 0 1 1 1 1 1 0 0 0 0 0 The maximum square sub-matrix with all set bits is 1 1 1 1 1 1 1 1 1 I searched the web for solutions and I found a relation to construct an auxiliary matrix: If M[i][j]

问题 This question already has answers here : Puzzle: Find largest rectangle (maximal rectangle problem) (7 answers) Closed 6 years ago . Given a binary matrix, I have find out the maximum size square sub-matrix with all 1 s. For example, consider the below binary matrix: 0 1 1 0 1 1 1 0 1 0 0 1 1 1 0 1 1 1 1 0 1 1 1 1 1 0 0 0 0 0 The maximum square sub-matrix with all set bits is 1 1 1 1 1 1 1 1 1 I searched the web for solutions and I found a relation to construct an auxiliary matrix: If M[i][j]

问题 I do have two sets of points and I want to find the best transformation between them. In OpenCV, you have the following function: Mat H = Calib3d.findHomography(src_points, dest_points); that returns you a 3x3 Homography matrix, using RANSAC. My problem is now, that I only need translation and rotation (& maybe scale), I don't need affine and perspective. The thing is, my points are only in 2D. (1) Is there a function to compute something like a homography but with less degrees of freedom? (2

问题 I do have two sets of points and I want to find the best transformation between them. In OpenCV, you have the following function: Mat H = Calib3d.findHomography(src_points, dest_points); that returns you a 3x3 Homography matrix, using RANSAC. My problem is now, that I only need translation and rotation (& maybe scale), I don't need affine and perspective. The thing is, my points are only in 2D. (1) Is there a function to compute something like a homography but with less degrees of freedom? (2

问题 I am trying to classify my dataset. To do this, I will use the 4th column of my dataset. If the 4th column of the dataset is equal to 1, that row will added in new matrix called Q1 . If the 4th column of the dataset is equal to 2, that row will be added to matrix Q2 . My code: i = input('Enter a start row: '); j = input('Enter a end row: '); search = importfiledataset('search-queries-features.csv',i,j); [n, p] = size(search); if j>n disp('Please enter a smaller number!'); end for s = i:j

问题 This question already has an answer here : How do I remove elements at a set of indices in a vector in MATLAB? (1 answer) Closed 6 years ago . In R, I can do the following: v <- 11:20 v[-(4:5)] and get 11 12 13 16 17 18 19 20 , thus all indices except the 4th and 5th. Is there an equivalent in Matlab's indexing logic? However I wrap my mind around it, I do not seem to get the correct search terms to google my own result for this fairly elementary question. Note: Of course I might use some of