for-loop

问题 I'm trying to bruteforce a password. As I was playing with some loops, I've noticed there's a specific order. Like, if I have for i in '.'..'~' it puts . / 0 1 2 3 4 5 6 7 8 9 : ; < = > ? @ A B C D E F G H I J K L M N O P Q R S T U V W X Y Z [ \ ] ^ _ ` a b c d e f g h i j k l m n o p q r s t u v w x y z { | } ~ After seeing this, I wondered to myself "what is the loop order in Ruby?" What character is the highest priority and which is the lowest priority? Sorry if this question is basic. I

问题 Following data and using MS Access with VB6 UserID UserName LogTime LogDate 1 S 9:00 21/5/2010 1 S 10:00 21/5/2010 1 S 11:00 21/5/2010 1 S 12:00 21/5/2010 1 S 14:00 21/5/2010 1 S 17:00 21/5/2010 Need Output as in below 6 columns:- 1 S 21/5/2010 9:00 21/5/2010 10:00 1 S 21/5/2010 11:00 21/5/2010 12:00 1 S 21/5/2010 14:00 21/5/2010 17:00 回答1: This is not going to be fast: SELECT x.UserID, x.UserName, y.LogTime, x.LogTime, y.LogDate FROM ( SELECT Test.UserID, Test.UserName, Test.LogTime, Test

问题 The following link if else statement gone bad suggests not to use the formulation > any( c(5,6,7) )==0 [1] FALSE I have been using any() to get rid of empty data frames in for() loops like this: id <- c(1,2,3,4,5,6) len <- c(11.25,11.75,12,12,12.5,13.25) df <- data.frame(id,len) bin.brks <- c(10,11,12,13,14) options(warn = -1) # to turn warnings off for (m in 1: (length(bin.brks)-1)){ #subset weights into each bin; empty when m=1 temp <- df[(df$len > bin.brks[m] & df$len <= bin.brks[m+1]),] #

问题 I'm very new to R, and much more new to programming in R. I have the following question and its answer (which is not mine). I've trying to understand why some values, from where they are obtained, why they are used, etc. Question: Make the vector 3 5 7 9 11 13 15 17 with a for loop. Start with x=numeric() and fill this vector with the for loop I know I have to create x=numeric() so I can fill it with the result obtained from the loop. The answer from a classmate was: > x <- numeric() > for(i

问题 I've 2 post types and I want to output them alternately but without using many loops so I found this solution which does that. However, it is not ideal as I need to output the_post_thumbnail which I find I am unable to do using this method ( echo $smallPosts->posts[$i]->post_thumbnail; does nothing). Additonally I've read post_content is not the same as the_content(); - with the latter what I want to use. Any suggestions on how I can loop through the alternating post types and have more

问题 I am trying to output all AD users calendar and contact permissions. I have tried adding an -or operator but as per the error screenshot it does not work. I am not sure if Get-MailboxFolderPermission can take more than one parameter. This script does not run $OU = OrganizationalUnit "OU=users,OU=test.com,OU=PIPE,OU=Hosting,DC=options,DC=com" Get-Mailbox -OrganizationalUnit $OU -Filter * | select -Expand alias | Where-Object {Get-MailboxFolderPermission -Identity $($_ + ':\Calendar') -or $($_

问题 I'm coding this in JavaFX using a FXMLController and the scene builder. I'm currently creating an Instagram "liker" mostly just for practice as I'm a Computer Science major, and I just like coding. My issue is, I have a for loop that "likes" 20 photos for each hashtag, I obviously need a delay or I'd get banned rather quickly. The user can choose the delay, then I randomize this delay so it's not too robotic. The only way I've been able to use this delay is through the thread.sleep method,

问题 I'm working on next step of my data aggregation following previous question. There Jon Spring pointed me to a solution for indicating number of active events in given time interval. At next step I'd like to be able to aggregate this data and obtain number of observations with same ID that were active at any point during the fixed time interval. Starting with a toy dataset of seven events with five IDs: library(tidyverse); library(lubridate) df1 <- tibble::tibble( id = c("a", "b", "c", "c", "c

问题 I have a 4D matrix A of size m × n × p × q . Consider B = A(:,:,1,1) which is an m × n matrix. I want to sum all the elements of B to give a number. I want to do this for all such B matrices for all A so finally I will have a p by q matrix. How can i do this without for loops? As an example for a 3D matrix (for example A be a 3D matrix) I think this works, sum(squeeze(sum(A,1)),1) But I don't know how to do this for a 4D matrix... 回答1: what's wrong with [m n p q] = size( A ); squeeze( sum(

问题 I made a simple WF in C# in an attempt to change the label dynamically. However, when I run this code, there is no visible change, until after the code has run, and then it changes to "Processing 9" 0-8 are not ever shown. Is it because it is within the loop? private void button1_Click(object sender, EventArgs e) { for (int i = 0; i < 10; i++) { label9.Text = "Processing " + i.ToString(); Thread.Sleep(1000); } } EDIT: X-Tech's code worked but when I tried to incorporate it into my code, I get