for-loop

问题 Does every recursive function have an equivalent for loop? (Both achieve the same result). I have this recursive function: private static boolean recur(String word, int length) { if(length == 1 || length == 2) return false; if(length == 0) return true; if(words[length].contains(word.substring(0, length))) return recur(word.substring(length), word.length() - length); return recur(word, length-1); } Given that words is a Set[], and where words[i] = a set with words of length i. What am trying

问题 Does every recursive function have an equivalent for loop? (Both achieve the same result). I have this recursive function: private static boolean recur(String word, int length) { if(length == 1 || length == 2) return false; if(length == 0) return true; if(words[length].contains(word.substring(0, length))) return recur(word.substring(length), word.length() - length); return recur(word, length-1); } Given that words is a Set[], and where words[i] = a set with words of length i. What am trying

问题 I am struggling to find an efficient way to convert these for loops to a working set of while loops. Any Suggestions? I am using 2.7 def printTTriangle(height): for row in range(1,height+1): # print row T's for col in range(1,row+1): print 'T', print Thank you all for your help! 回答1: It's like this: def printTTriangle(height): row = 1 while row < height+1: col = 1 while col < row+1: print 'T', col += 1 print row += 1 Here's how I did it. For example, let's convert this line: for row in range

问题 I have following code: @echo off SET ITER=0 for %%i in (%*) do ( SET ITER+=1 ECHO %ITER% ) The output is (for three arguments): 0 0 0 Expected output: 1 2 3 Why can't I access the updated variable in the for loop? 回答1: Expansion of variables with percents is done before a statement/block is executed. So in your case the complete block is expanded before the echo %ITER% is executed, to constant echo 0 . The variable ITER itself is updated in the loop properly. To avoid this, you could use the

问题 Can you confirm if the next break cancels the inner for loop? for (out in 1:n_old){ id_velho <- old_table_df$id[out] for (in in 1:n) { id_novo <- new_table_df$ID[in] if(id_velho==id_novo) { break }else if(in == n) { sold_df <- rbind(sold_df,old_table_df[out,]) } } } 回答1: Well your code is not reproducable so we never know for sure, but this is what help('break') says: break breaks out of a for, while or repeat loop; control is transferred to the first statement outside the inner-most loop. So

问题 I want to implement a kind of jQuery live search. But before sending the input to the server I'd like to remove all items in my array which have 3 or less characters (because in the german language, those words usually can be ignored in terms of searching) So ["this", "is", "a", "test"] becomes ["this", "test"] $(document).ready(function() { var timer, searchInput; $('#searchFAQ').keyup(function() { clearTimeout(timer); timer = setTimeout(function() { searchInput = $('#searchFAQ').val().match

问题 I have this sample matrix: X1 X2 X3 X4 1 F F F F 2 C C C C 3 D D D D 4 A# A# A# A And I'm trying to use a for loop to get the number of unique pitches in each column. Here's how I'm trying to do it: y <- read.csv(file) frame <- data.frame(y) for(i in 1:4){ specframe <- frame[, i] x <- unique(specframe) } length(x) But the result of length is just 4. The output I'm looking for is a vector of 4 elements in which each element details the number of unique elements in their respective columns. It

问题 I have an array with a particular size (100 for example), which is filled with user input. However, the user might not necessarily enter enough data to fill the entire array. I want to count the elements of the array which the user entered. How can I do this? I tried by this for loop: int COUNT=0; for( int i=0; i<size; i++) if (Student[i]=1) //which means this element is true, not empty element. COUNT++; cout<< COUNT+1 << "\n"; But this code gives an error on this line: if (Students[i]==1)

问题 I have 2 seperate forloops and i am using forloop.counter in bothloops. I want to start the second forloop counter from the ending of first forloop {% for i in something1 %} <tr> <td>{{ forloop.counter }}</td> <td>i.username</td> </tr> {% endfor %} {% for j in something2 %} <tr> <td>{{ forloop.counter }}</td> <td>j.username</td> </tr> {% endfor %} if the first forloop ends at 10 then i want to start the next for loop from 11.plz help 回答1: I'm not comfortable with Django, so I show a couple of

问题 I am trying to print the following using a nested loop in Java: 1 2 3 4 5 6 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1 but it's coming out like the following: 1 2 3 4 5 6 2 3 4 5 6 3 4 5 6 4 5 6 5 6 6 Here is my code: for (int i = 1; i <= 6; i++) { for (int j = 1; j < i; j++) { System.out.print(" "); } for (int j = i; j <= 6; j++) { System.out.print(j + " "); } System.out.println(); } Any help would be appreciated. Thanks 回答1: int n = 7; for (int i = 1; i <= n; i++) { for (int j = 1; j < i; j++) { System