long-integer

Me and my friend have just encountered a very weird issue with long long range. So basically, my computer has a 64bit processor but a 32 bit system on it. He has both 32 bit OS and CPU. First, we printfed sizeof(long long) . For both of us that was 8. Then we did this: long long blah = 1; printf ("%lld\n", blah<<40); For me this returns 1099511627776 (which is the correct result). For him it is 0. How is that possible? We both have the same sizeofs. Thanks in advance. EDIT: I compiled and ran it under Win7 with Code Blocks 12.11. He uses Win XP and the same version of CB. EDIT2: Source codes

Do literal expressions have types too ? long long int a = 2147483647+1 ; long long int b = 2147483648+1 ; std::cout << a << ',' << b ; // -2147483648,2147483649 Yes, literal numbers have types. The type of an unsuffixed decimal integer literal is the first of int , long , long long in which the integer can be represented. The type of binary, hex and octal literals is selected similarly but with unsigned types in the list as well. You can force the use of unsigned types by using a U suffix. If you use a single L in the suffix then the type will be at least long but it might be long long if it

I'm trying to use a bitcoin address validator written in Python from here : This snippet gives me trouble though: def decode_base58(bc, length): n = 0 for char in bc: n = n * 58 + digits58.index(char) return n.to_bytes(length, 'big') I understand that n is either an int or a long, but neither has a method called to_bytes, so I don't really understand how this code could have ever worked? Does anybody know what's wrong here? Am I doing something wrong, or is this code simply written wrong? All tips are welcome! Python 2.7 int and long don't have the .to_bytes method. Python 3.2 int has the .to

Im working with a embedded system and I need implement a way to convert long long to char. The problem is that I can not use sprintf in this system to do that, so im looking for alternative ways/functions to implement this. Suggestions of implementations for LongLongToChar function are welcome. Google "itoa". There are many variations. Here's an example. char* itoa(int val, int base){ static char buf[32] = {0}; int i = 30; for(; val && i ; --i, val /= base) buf[i] = "0123456789abcdef"[val % base]; return &buf[i+1]; } Specifically, here's an 'lltoa'. #include <stdio.h> #include <limits.h> char*

Why the following code Gives output as -2 instead for throwing overflow exception ? long x = long.MaxValue; long y = long.MaxValue + x; The actual behaviour depends on project settings, unchecked etc. To ensure overflow exception use checked , e.g. checked { long x = long.MaxValue; long y = long.MaxValue + x; } Presumably because you're executing it in an unchecked context. Arithmetic on the primitive integer types can execute in a checked or unchecked context . Operations which overflow throw an exception in a checked context, and just use the bottom N bits (depending on the type) in an