location

Get Location Permissions from User in Android Application [duplicate]

由 烈酒焚心 提交于 2019-12-05 20:39:04
This question already has an answer here: How to request Location Permission at runtime 5 answers I´m trying to get the users actual location with the typicaly permissions box: like this: If anyone knows how to make it , pleas answer. Ask for permission at runtime to use device current location as below : if (ActivityCompat.checkSelfPermission(YourActivity.this, Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED && ActivityCompat.checkSelfPermission(YourActivity.this, Manifest.permission.ACCESS_COARSE_LOCATION) != PackageManager.PERMISSION_GRANTED) { ActivityCompat

如何重定向到另一个网页？

由 ∥☆過路亽．° 提交于 2019-12-05 20:36:03
这篇文章是 社区维基 。 编辑现有答案以改善此职位。 它当前不接受新的答案。 如何使用jQuery或纯JavaScript将用户从一个页面重定向到另一页面？ #1楼 您可以在没有jQuery的情况下做到这一点： window.location = "http://yourdomain.com"; 如果只需要jQuery，则可以这样做： $jq(window).attr("location","http://yourdomain.com"); #2楼 重定向页面的标准“香草” JavaScript方法 window.location.href = 'newPage.html'; 或更简单地说：（因为 window 是“全局”） location.href = 'newPage.html'; 如果您在这里是因为重定向时 丢失了 HTTP_REFERER，请继续阅读： （否则忽略最后一部分） 以下部分适用于那些将 HTTP_REFERER 用作许多安全措施之一的人（尽管这不是很好的保护措施）。 如果您使用的是 Internet Explorer 8 或更低版本，则在使用任何形式的JavaScript页面重定向（location.href等）时，这些变量都会丢失。 下面我们将为 IE8及更低版本 实现替代方案，以免丢失HTTP_REFERER。 否则，您几乎总是可以简单地使用 window

Getting mouse click location of a label in qt

由 谁说我不能喝 提交于 2019-12-05 20:03:10
问题 I googled around and found this forum thread in which the OP seems to have had the exact problem I am having. The question is, how would I inherit from QLabel and reimplement the mousepressed event? I'm guessing it would be something like this: class CustomLabel : public QLabel { public: //what about the constructors? void mousePressEvent ( QMouseEvent * ev ); } void CustomLabel::mousePressEvent ( QMouseEvent * ev ) { QPoint = ev->pos(); //I want to have another function get the event

window.location.href用法与a标签的比较

由 亡梦爱人 提交于 2019-12-05 19:54:10
1.在使用这两种方法进行页面的跳转时，这两种方法都能够有效的实现该功能 但是其原理不尽相同 第一：window.location.href()方法必须书写在js中 <html> <head> <title>Title</title> </head> <body><a onclick="submit1()"></a><a onclick="submit2()"></a> </body> <script> function submit1(){ // window.alert('测试'); window.location.href="/https://www.baidu.com/baidu?tn=monline_3_dg&ie=utf-8&wd=%E7%99%BE%E5%BA%A6"; } function submit2(){ // window.alert('测试'); window.location.href="/url"; } </script> </html> 该方法主要通过给a标签添加点击事件跳转页面； 第二种 <a href="https://www.baidu.com/baidu?tn=monline_3_dg&ie=utf-8&wd=%E7%99%BE%E5%BA%A6"></a> 该方法直接进行跳转不需要任何中间步骤，

User's location and battery's consumption

由 橙三吉。 提交于 2019-12-05 19:22:40
I am working on an iOS app that's focuses on pedestrians in a block of buildings (campus). I have developed a good enough (I believe) user's location update but, I would like anyone more expert than me to give me some tips, advices on accurate location, battery's issues etc. In addition, is it possible to stop the location update and start it again after n seconds? Is a thought that I did in order to save energy. As it is at the moment, app is detecting current location, but, blue dot (user) is still moving around and I don't like that. There is something that can be done? Below is my

Alert when two users/friends are near to each other - Android Proximity

由 前提是你 提交于 2019-12-05 18:55:38
I tried searching but i couldn't find anything. My Question is " How can i alert 2 or more users if they are nearby each other? " in android using Geo-fencing or something else. Say, If a UserA is in football ground and UserB walking nearby that football ground. Then UserA and UserB automatically gets notification that UserA/UserB are somewhere nearby. Rafique Mohammed Finally after spending a couple of hours thinking, I thought a better way to do this: Setup a database (MySQL,SQL etc) in your server which have users table and location table which have the locations data In Android create a

get the current location (gps/wifi)

由 我的未来我决定 提交于 2019-12-05 18:00:59
I'm trying to get my location using it like this: LocationManager myLocationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE); Criteria criteria = new Criteria(); criteria.setAccuracy(Criteria.ACCURACY_FINE); criteria.setAltitudeRequired(false); criteria.setBearingRequired(false); criteria.setCostAllowed(true); criteria.setPowerRequirement(Criteria.POWER_LOW); String provider = myLocationManager.getBestProvider(criteria,true); if (provider != null) { //there is a provider myLocationManager.requestLocationUpdates(provider, 10L, 500.0f, (LocationListener) mainContext);

nginx工作原理

由 孤街醉人 提交于 2019-12-05 17:49:47
Nginx的模块与工作原理 Nginx由内核和模块组成，其中，内核的设计非常微小和简洁，完成的工作也非常简单，仅仅通过查找配置文件将客户端请求映射到一个location block（location是Nginx配置中的一个指令，用于URL匹配），而在这个location中所配置的每个指令将会启动不同的模块去完成相应的工作。 Nginx的模块从结构上分为核心模块、基础模块和第三方模块： 核心模块：HTTP模块、EVENT模块和MAIL模块 基础模块：HTTP Access模块、HTTP FastCGI模块、HTTP Proxy模块和HTTP Rewrite模块， 第三方模块：HTTP Upstream Request Hash模块、Notice模块和HTTP Access Key模块。 Nginx的模块从功能上分为如下三类。 Handlers（处理器模块）。此类模块直接处理请求，并进行输出内容和修改headers信息等操作。Handlers处理器模块一般只能有一个。 Filters （过滤器模块）。此类模块主要对其他处理器模块输出的内容进行修改操作，最后由Nginx输出。 Proxies （代理类模块）。此类模块是Nginx的HTTP Upstream之类的模块，这些模块主要与后端一些服务比如FastCGI等进行交互，实现服务代理和负载均衡等功能。 　　

How do I get the coordinates of a map on tap with MapFragment (not MapView)?

由 霸气de小男生 提交于 2019-12-05 17:01:35
问题 I have searched around on how to get the coordinates of a location when the map is tapped. However, most, if not all the examples require a MapView as a parameter. For example: public boolean onTap(GeoPoint p, MapView map){ if ( isPinch ){ return false; }else{ Log.i(TAG,"TAP!"); if ( p!=null ){ handleGeoPoint(p); return true; // We handled the tap }else{ return false; // Null GeoPoint } } } @Override public boolean onTouchEvent(MotionEvent e, MapView mapView) { int fingers = e.getPointerCount

How get the current latitud and longitud without use getLastKnownLocation method in Android?

由 烈酒焚心 提交于 2019-12-05 16:00:37
I am trying to get the current position of the phone, for this I use the GPSTracker tutorial , the problem is always use the method getLastKnownLocation and return older position. if (isNetworkEnabled) { locationManager.requestLocationUpdates( LocationManager.NETWORK_PROVIDER, MIN_TIME_BW_UPDATES, MIN_DISTANCE_CHANGE_FOR_UPDATES, this); Log.d("Network", "Network"); if (locationManager != null) { location = locationManager .getLastKnownLocation(LocationManager.NETWORK_PROVIDER); if (location != null) { latitude = location.getLatitude(); longitude = location.getLongitude(); } } } // if GPS
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