location

Using location.search to locate a parameter's value

和自甴很熟 提交于 2019-12-06 04:34:28
问题 I’m working on a tool which takes the value parameters in the URL and does a few things with them. My issue is, I can’t seem to use document.location to show the specific value that I’m after, for example: www.examplesite.com?yourname=gilgilad I want to use document.location.search and put it in a var, I need that var's value to be "gilgilad". Is this even possible using location.search? 回答1: location.search will return all after question mark including it. So there is universal js to get

装饰器login_required

无人久伴 提交于 2019-12-06 04:34:22
装饰器login_required将游客身份引导至登录页面,登录成功后跳转到目的页面 url.py path('login/',views.login), path('home/',views.home), views.py from django.contrb.auth.decorators import login_required @login_required def home(request): return render(request,'home.html') 装饰器@login_required,会跳转到django设置的默认路径:‘/accounts/login/’,在setting.py中进行修改,跳转到登录页的路由 setting.py LOGIN_URL ='/login/' 第一次请求: http://127.0.0.1:8999/home/ 转到 'http://127.0.0.1:8999/login/?next=home' 登录成功,转到 'http://127.0.0.1:8999/home/' 如果是ajax请求如何实现登录成功后自动跳回第一次请求的路径: success:function(response){ if(resonse.user){ if(location.search){ //间接进入login时,转回 location.href

javascript location.href onchange event listener?

半城伤御伤魂 提交于 2019-12-06 04:29:24
I want to show a message whenever you are leaving the page (not an annoying alert, just some html telling you to wait), in thinking about it I'm facing certain difficulties: when the user presses Stop in the browser, cancelling the navigate-away action, I'd like the message to go away. whenever any link is clicked, the message should appear. it shouldn't capture when the clicked link just opens another tab ( ignore _blank target ) that being said, firing the event is pretty simple, with just something like $(document).unload(function() { // display message }); the problem being that if the

android.location.Location setters not working as expected

别来无恙 提交于 2019-12-06 04:13:52
I need to create a Location object from some latitude and longitude values, without going through a location provider. I do the following: Location l = new Location(""); l.setLatitude(32); l.setLongitude(43); The values, however, are not set properly, since both getLatitude() and getLongitude() return 0. Can you please tell me where is the problem? Isn't this the correct way to create a "custom" Location? I figured it out eventually. When unit testing using the Android APIs, you need to use the instrumentation framework. I was using JUnit alone, thus the malfunctioning. I resolved by using

Nginx源码安装及调优配置

眉间皱痕 提交于 2019-12-06 03:49:34
Nginx编译前的优化 [root@linuxprobe ~]# wget http://nginx.org/download/nginx-1.10.1.tar.gz [root@linuxprobe ~]# tar xvf nginx-1.10.1.tar.gz -C /usr/local/src/ [root@linuxprobe ~]# cd /usr/local/src/nginx-1.10.1/ 编译前的优化主要是用来修改程序名等等,例如: [root@linuxprobe nginx-1.10.1]# curl -I http://www.baidu.com …… Server: bfe/1.0.8.14 …… [root@linuxprobe nginx-1.10.1]# curl -I http://www.sina.com.cn …… Server: nginx …… [root@linuxprobe nginx-1.10.1]# curl -I http://www.linuxprobe.com HTTP/1.1 200 OK Server: nginx/1.10.1 #我们目标是将nginx更改名字 Content-Type: text/html; charset=UTF-8 Connection: keep-alive X-Powered-By: PHP/5

Get current position with GPS AND WIFI

纵饮孤独 提交于 2019-12-06 03:35:34
I'm currently using GPS only to get current location of the user to return certain results. As in Belgium, if you're inside, most of the time you can't get GPS-connection. So I want to get the current location with the wifi-connection. I've found this example: get the current location (gps/wifi) But I'm not sure which lines tell the device which connection to choose. I'm guessing it's this one: String provider = myLocationManager.getBestProvider(criteria,true); That I've to add to my code. When I check what's inside of this, I always get a null-value, I don't quite understand why. My code

Android - How to determine whether coordinates lie on road in Google Maps

元气小坏坏 提交于 2019-12-06 03:30:52
问题 I need to make a check in my application that determines whether the given coordinates lie on road or not in Google Maps. Is there any function in Google Maps API that can aid me with that? Thanks in advance! 回答1: As far as I know this can't be done using the Google Maps API. I think your best bet is to use a crowd-sourced dataset such as OpenStreetMap (OSM). You'd need to set up your own spatial database (e.g., PostGIS) and import OSM data into the database. Then, you'd create a server-side

redirect html page if not login

笑着哭i 提交于 2019-12-06 03:16:17
I have simple Login Form on my webpage. It uses javascript to login user and works fine. problem is that is user types the landing page url directly into the adress bar he directly can acess the page without login. i want to redirect him to the login page if he didn't login. below are the links of loding and target page. login: http://samdesign.comli.com/protected/index.html target: http://samdesign.comli.com/protected/user-soft.html and here is the script used are below.. <form> <table align=center> <tr> <td>Username:</td> <td><input type="text" name="username" style="background:#bfbfbf;color

JavaScript 打开新链接的方式

不问归期 提交于 2019-12-06 03:08:19
<a onclick="window.open('http://www.runoob.com', '_blank', 'location=yes,height=570,width=520,scrollbars=yes,status=yes');"> 1、点我在新窗口打开页面 </a> <br> <input type="button" value="加载新文档" onclick="newDoc()"> <input type="button" value="加载新頁面1" onclick="newhref()"> <input type="button" value="加载新頁面2" onclick="newopen()"> <input type="button" value="加载新頁面3" onclick="newopen2()"> <input type="button" value="加载新頁面4" onclick="newopen3()"> <input type="button" value="加载新頁面5" onclick="newopen4()"> <input type="button" value="加载新頁面6" onclick="newreplace()"> <script> function newDoc(){ window.location

Google maps containsLocation on android

六眼飞鱼酱① 提交于 2019-12-06 02:31:07
问题 I'm writing an app that needs to determine whether a user falls within one of several defined zones (based on gps location). The Google maps javascript API has an easy to use function containsLocation(). However I want to be able to do this from an app on android, not a web-based service. Does anyone know if such a call exists in the android version of maps? Any pointers will be helpful! 回答1: A bit late, but here's the answer: com.google.maps.android.PolyUtil.containsLocation() from Google