kadanes-algorithm

问题 Does anyone have a Scala implementation of Kadane's algorithm done in a functional style? Edit Note: The definition on the link has changed in a way that invalidated answers to this question -- which goes to show why questions (and answers) should be self-contained instead of relying on external links. Here's the original definition: In computer science, the maximum subarray problem is the task of finding the contiguous subarray within a one-dimensional array of numbers (containing at least

问题 Given an array of length n, with integers(can be negative or positive). Find the starting and ending index of the subarray with minimum sum possible. 回答1: As you specified this is about Kadanes Algorithm, it is easy to find a lot of references about it. GeeksForGeeks : Smallest sum contiguous subarray kindly explains about the algorithm and provides implementations in a few languages. Based on the python code from that page, I have revised it to return begin/end indices rather than the sum

问题 There are two key attributes that a problem must have in order for dynamic programming to be applicable: optimal substructure and overlapping subproblems [1]. For this question, we going to focus on the latter property only. There are various definitions for overlapping subproblems , two of which are: A problem is said to have overlapping subproblems if the problem can be broken down into subproblems which are reused several times OR a recursive algorithm for the problem solves the same

来源： https://stackoverflow.com/questions/16323792/dynamic-programming-aspect-in-kadanes-algorithm

问题 I get that question from leet code and I got this answer from YouTube tutorial, but I don't understand the part of max. Because max is arr[0] and the value is -2 , and even it goes inside of the loop, it is just -2 but max returns value 6 . How it possible? const givenArray = [-2, 1, -3, 4, -1, 2, 1, -5, 4]; const getMax = arr => { let sum = arr[0]; //-2 let max = arr[0]; //-2 for (let i = 1; i < arr.length; i++) { sum = Math.max(sum + arr[i], arr[i]); max = Math.max(max, sum); } console.log

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed last year . Improve this question Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Example: Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6. Inputs:[-1] Output:-1

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed last year . Improve this question Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Example: Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6. Inputs:[-1] Output:-1

问题 I have been solving exercise from Introduction to Algorithms - CLRS and came across solving maximum contiguous sub-array in linear time (Q 4.1-5). Please look at my solution below. I have been searching for online judges for this exercise but found none. After solving it when I looked for solutions I found kadane's algorithm which seems different than my implementation also this solution gives the correct output when all numbers are negative. public static int linearMaxSolve(int[] arr) { int

问题 public class Kadane { double maxSubarray(double[] a) { double max_so_far = 0; double max_ending_here = 0; for(int i = 0; i < a.length; i++) { max_ending_here = Math.max(0, max_ending_here + a[i]); max_so_far = Math.max(max_so_far, max_ending_here); } return max_so_far; } } The above code returns the sum of the maximum sub-array. How would I instead return the sub-array which has the maximum sum? 回答1: Something like this: public class Kadane { double[] maxSubarray(double[] a) { double max_so

问题 The subarray contains both positive and negative numbers. You have to find a maximum sum subarray such that the length of the sub-array is greater than or equal to k. Here is my code in c++ using Kadane's algorithm. #include <iostream> using namespace std; int main(){ int n,k; cin >> n >> k; int array[n]; int sum = 0; int maxsum = 0; int beststarts[n]; for(int i = 0;i < n; i++){ cin >> array[i]; } for(int i = 0;i < k-1;i ++){ sum = sum+array[i]; beststarts[i] = 0; } for(int i = k-1;i < n; i++