jdbctemplate

Why Spring's jdbcTemplate.batchUpdate() so slow?

给你一囗甜甜゛ 提交于 2019-11-28 05:02:38
I'm trying to find the faster way to do batch insert . I tried to insert several batches with jdbcTemplate.update(String sql) , where sql was builded by StringBuilder and looks like: INSERT INTO TABLE(x, y, i) VALUES(1,2,3), (1,2,3), ... , (1,2,3) Batch size was exactly 1000. I inserted nearly 100 batches. I checked the time using StopWatch and found out insert time: min[38ms], avg[50ms], max[190ms] per batch I was glad but I wanted to make my code better. After that, I tried to use jdbcTemplate.batchUpdate in way like: jdbcTemplate.batchUpdate(sql, new BatchPreparedStatementSetter() {

JDBCTemplate set nested POJO with BeanPropertyRowMapper

时光总嘲笑我的痴心妄想 提交于 2019-11-28 04:25:37
Given the following example POJO's: (Assume Getters and Setters for all properties) class User { String user_name; String display_name; } class Message { String title; String question; User user; } One can easily query a database (postgres in my case) and populate a list of Message classes using a BeanPropertyRowMapper where the db field matched the property in the POJO: (Assume the DB tables have corresponding fields to the POJO properties). NamedParameterDatbase.query("SELECT * FROM message", new BeanPropertyRowMapper(Message.class)); I'm wondering - is there a convenient way to construct a

JDBC通用DAO

点点圈 提交于 2019-11-27 23:53:37
dbcBaseDao接口,内容如下: package com.sun4j.core.jdbc.dao; import java.io.Serializable; import java.util.List; import java.util.Map; import org.springframework.jdbc.core.JdbcTemplate; import org.springframework.jdbc.support.rowset.SqlRowSet; public interface JdbcBaseDao<T> { void save(T entity); void update(T entity); void delete(T entity); void delete(Serializable id); void deleteAll(); T findById(Serializable id); List<T> findAll(); void batchDelete(Serializable[] ids); void batchUpdate(List<T> list); void batchSave(List<T> list); Map<String, Object> findOne(String sql, Object... args); List<Map

A ResourcePool could not acquire a resource from its primary factory or source

自古美人都是妖i 提交于 2019-11-27 22:11:45
问题 I'm trying to connect to a database in Java, using jdbcTemplate and I'm gettin the error below. I have Googled for a long time and all solutions I found didn't solve my problem. I tried several different DBs (both SQLServer and MySQL) and none worked. SEVERE: Servlet.service() for servlet [Faces Servlet] in context with path [/promotion-handler-admin] threw exception [Could not open JDBC Connection for transaction; nested exception is java.sql.SQLException: Connections could not be acquired

jdbcTemplate模板数据库简化对数据库的操作,他是sping提供的

六眼飞鱼酱① 提交于 2019-11-27 20:59:22
jdbc: jdbc是Java提供的原生态接口,操作数据库的唯一技术 缺点:重复写代码,代码写死,耦合性高,开发效率低换数据库比较苦难 优点:运行速度最快,所有操作数据库的技术底层都是jdbc写的 jpa:   java persistence api 持久规范,他是ORM对象关系型数据库映射的规范,不用写sql语句,面向对象的   优点:数据库移植快,一级二级缓存,查询,提高性能( ehcache 框架实现缓存 )   缺点:查询所有的时候,find性能无法控制,无法干预sql语句的生成,对sql语句要求高的话,    jpa是为了让面向对象设置的,为了不写sql语句而设置的(几十张表写sql语句关联,那种才是高手,本人三张表的sql语句就很头疼)      spring jdbc jdbcTemplate模板数据库简化对数据库的操作,他是sping提供的   spring data jpa 是对jpa规范的再次抽象,底层还是用的实现jpa的hibernate技术( entitymanager )。   hibernate 是一个标准的orm框架,实现jpa接口(好像是 session )。   mybatis 也是一个持久化框架,但 不完全是一个orm框架,不是依照的jpa规范,她需要些sql语句,半ORM 。 来源: https://www.cnblogs.com

JDBCTemplate set nested POJO with BeanPropertyRowMapper

六眼飞鱼酱① 提交于 2019-11-27 19:15:56
问题 Given the following example POJO's: (Assume Getters and Setters for all properties) class User { String user_name; String display_name; } class Message { String title; String question; User user; } One can easily query a database (postgres in my case) and populate a list of Message classes using a BeanPropertyRowMapper where the db field matched the property in the POJO: (Assume the DB tables have corresponding fields to the POJO properties). NamedParameterDatbase.query("SELECT * FROM message

使用JDBCTemplate执行DQL/DML语句

偶尔善良 提交于 2019-11-27 16:52:36
package cn.itcast.datasource.jdbctemplate;import cn.itcast.domain.User;import cn.itcast.utils.JDBCUtils;import org.junit.Test;import org.springframework.jdbc.core.BeanPropertyRowMapper;import org.springframework.jdbc.core.JdbcTemplate;import org.springframework.jdbc.core.RowMapper;import java.sql.ResultSet;import java.sql.SQLException;import java.util.List;import java.util.Map;/** * @author newcityman * @date 2019/8/17 - 21:05 */public class JdbcTemplateDemo02 { /* * 根据id号,修改user对象 * */ // 获取JdbcTemplate对象 private JdbcTemplate temp = new JdbcTemplate(JDBCUtils.getDataSource()); @Test public

Spring框架--spring的jdbcTemlate

女生的网名这么多〃 提交于 2019-11-27 16:19:13
一、Spring对不同的持久化支持 Spring为各种支持的持久化技术,都提供了简单操作的模板和回调 ORM持久化技术 模板类 JDBC org.springframework.jdbc.core.JdbcTemplate Hibernate5.0 org.springframework.orm.hibernate5.HibernateTemplate IBatis(MyBatis) org.springframework.orm.ibatis.SqlMapClientTemplate JPA org.springfrmaework.orm.jpa.JpaTemplate 其实Spring的JDBCTemplate有点像DBUtils,但是有时候还没有DBUitls好用。下面我们就来学习一下使用SpringJDBCTemplate来玩一下CRUD。 二、实现jdbcTemlate的CRDU 1.引入依赖: <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM

How can I get the autoincremented id when I insert a record in a table via jdbctemplate

独自空忆成欢 提交于 2019-11-27 16:07:04
问题 private void insertIntoMyTable (Myclass m) { String query = "INSERT INTO MYTABLE (NAME) VALUES (?)"; jdbcTemplate.update(query, m.getName()); } When the above query inserts a record, the ID column in the table autoincrements. Is there a way to get this auto incremented ID back at the time of the insertion. So in this example the return value of my method would be int 回答1: Check this reference. You can use jdbcTemplate.update as: EDIT Added imports as asked import java.sql.Connection; import

How to use SELECT IN clause in JDBCTemplates?

删除回忆录丶 提交于 2019-11-27 14:46:50
This is my first experience with JDBCTemplates and I ran into a case where I need to use a query that looks like this: SELECT * FROM table WHERE field IN (?) How do I do that? I already tried passing a list/array value but that didn't do the trick, I get an exception. My current code looks like this: Long id = getJdbcTemplate().queryForLong(query, new Object[]{fieldIds}); Spring Documentation states that there is no way of doing this besides generating the required number of "?" placeholders to match the size of the parameter List. Is there a workaround? I don't think you can do this as a