How to use SELECT IN clause in JDBCTemplates?

删除回忆录丶 提交于 2019-11-27 14:46:50

I don't think you can do this as a single '?'. It's nothing to do with Spring JDBC templates, it's core SQL.

You'll have to build up a (?, ?, ?) for as many of them as you need.

There is walkaround using NamedParameterJdbcTemplate instead of SimpleJdbcDaoSupport, where you can do something like this:

List integerList = Arrays.asList(new Integer[] {1, 2, 3});
Map<String,Object> params = Collections.singletonMap("fields", integerList);    
Long id = namedParameterJdbcTemplate.queryForLong("SELECT * FROM table WHERE field IN (:fields)", params);

This, however, has a potentially catastrophic limitation regarding the number of parameters you can pass in the list which depends on the DB you are using.

Hope this is helpful...

For long list (ex. Oracle has limitation for 1000 items) you can just separate it to more selects:

List<Long> listIds = Arrays.asList(1L, 2L, ..... , 10000L); // list with ids

String query = "select NOTE from NOTE where ID in (:listIds)";

List<String> noteListResult = new ArrayList<>();

int current = 0;
int iter = 100;

while (current < listIds.size()) {
    Map<String, List<Long>> noteIdsMap = Collections.singletonMap("listIds",
            listIds.subList(current, (current + iter > listIds.size()) ? listIds.size() : current + iter));

    List<String> noteListIter = namedParameterJdbcTemplate.queryForList(query, noteIdsMap, String.class);
    noteListResult.addAll(noteListIter);

    current += iter;
}

return noteListResult;
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