How can I get the autoincremented id when I insert a record in a table via jdbctemplate

独自空忆成欢 提交于 2019-11-27 16:07:04

问题


private void insertIntoMyTable (Myclass m) {
    String query = "INSERT INTO MYTABLE (NAME) VALUES (?)";
    jdbcTemplate.update(query, m.getName());
}

When the above query inserts a record, the ID column in the table autoincrements.

Is there a way to get this auto incremented ID back at the time of the insertion. So in this example the return value of my method would be int


回答1:


Check this reference. You can use jdbcTemplate.update as:

EDIT Added imports as asked

import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.SQLException;

import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.PreparedStatementCreator;
import org.springframework.jdbc.support.GeneratedKeyHolder;
import org.springframework.jdbc.support.KeyHolder;

following is the code usage:

final String INSERT_SQL = "insert into my_test (name) values(?)";
final String name = "Rob";
KeyHolder keyHolder = new GeneratedKeyHolder();
jdbcTemplate.update(
    new PreparedStatementCreator() {
        public PreparedStatement createPreparedStatement(Connection connection) throws SQLException {
            PreparedStatement ps =
                connection.prepareStatement(INSERT_SQL, new String[] {"id"});
            ps.setString(1, name);
            return ps;
        }
    },
    keyHolder);
// keyHolder.getKey() now contains the generated key



回答2:


I get id generated by database (MSSQL) after insert like below, imports:

  import org.springframework.jdbc.core.BeanPropertyRowMapper;
  import org.springframework.jdbc.core.JdbcTemplate;
  import org.springframework.jdbc.core.RowMapper;
  import org.springframework.jdbc.core.SqlParameter;
  import org.springframework.jdbc.core.SqlReturnResultSet;
  import org.springframework.jdbc.core.simple.SimpleJdbcCall;

and the code snippet:

    final String INSERT_SQL = "INSERT INTO [table]\n"
            + " ([column_1]\n"
            + " ,[column_2])\n"
            + " VALUES\n" +
            " (?, ?)";

    Connection connection = jdbcTemplate.getDataSource().getConnection();
    PreparedStatement preparedStatement = connection.prepareStatement(INSERT_INVOICE_SQL, Statement.RETURN_GENERATED_KEYS);
    preparedStatement.setString(1, "test 1");
    preparedStatement.setString(2, "test 2");

    preparedStatement.executeUpdate();
    ResultSet keys = preparedStatement.getGeneratedKeys();

    if (keys.next()) {
        Integer generatedId = keys.getInt(1); //id returned after insert execution
    } 



回答3:


JdbcTemplate is at the core of Spring. Another option is to use SimpleJdbcInsert.

SimpleJdbcInsert simpleJdbcInsert = new SimpleJdbcInsert(jdbcTemplate);
simpleJdbcInsert
    .withTableName("TABLENAME")
    .usingGeneratedKeyColumns("ID");
SqlParameterSource params = new MapSqlParameterSource()
    .addValue("COL1", model.getCol1())
    .addValue("COL2", model.getCol2());
Number number = simpleJdbcInsert.executeAndReturnKey(params);   

You can still @Autowire jdbcTemplate. To me, this is more convenient than working with jdbcTemplate.update() method and KeyHolder to get the actual id.

Example code snippet is tested with Apache Derby and should work with the usual databases.

Use of Spring JPA is another option - if ORM is for you.



来源:https://stackoverflow.com/questions/12882874/how-can-i-get-the-autoincremented-id-when-i-insert-a-record-in-a-table-via-jdbct

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