inline | 易学教程

How can I use qnorm on Rcpp?

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问题 require(inline) func <- cxxfunction(, 'return Rcpp::wrap( qnorm(0.95,0.0,1.0) );' ,plugin="Rcpp") error: no matching function for call to ‘qnorm5(double, int, int)’ require(inline) func <- cxxfunction(, 'return Rcpp::wrap( qnorm(0.95, 0.0, 1.0, 1, 0) );' ,plugin="Rcpp") error: no matching function for call to ‘qnorm5(double, double, double, int, int)’ require(inline) code <-' double a = qnorm(0.95, 0.0, 1.0); return Rcpp::wrap( a ); ' func <- cxxfunction(, code ,plugin="Rcpp") func() error:

Inline function and type extension

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问题 Consider I have two different library types: type Foo = { foo : string } type Bar = { bar : int32 } I want to implement generic function zoo that will work for either Foo or Bar instances. And I cannot change Foo and Bar because they are part of library code. Here's my first attempt using type extensions and inline function as explained here: // Library.fs module Library type Foo = { foo : string } type Bar = { bar : int32 } // Program.fs type Foo with static member zoo (f : Foo) = "foo" type

In C, is it possible to change exported function name to different one?

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问题 all. I want to link a library which calls malloc() function. However, my target environment is different one and malloc() is supplied as inline-function. How can I make the library's call to malloc() direct to my target environment's malloc() routine? Is it any way to change the exported function name? If so I can code my_malloc() first and export it as malloc() and link the library to that one: #include <my_environment.h> // malloc() is inline function declared there void my_malloc (void) {

Does SASS support inline IF statements?

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问题 I'd like to set a SASS variable using inline IF's similar to how its done in PHP or Javascript Is something like this possible? $myVar: ($something >= 10 ? true : false); I'm aware of @if control directives but I want to use a shorter inline syntax. 回答1: Sass does support of conditional (ternary) operator or one line if statement as it works in languages like Javascript or PHP. $variable: if(condition, result-when-true, result-when-false); Article about improved if and what's new in Sass 3.3.

Does SASS support inline IF statements?

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Private method inlining

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问题 In the Scala immutable Vector code there is a comment that says: In principle, most members should be private. However, access privileges must be carefully chosen to not prevent method inlining What's the effect of private on inlining decisions? Does this apply to Java as well? 回答1: This generally does not apply to Java. The access checks are performed only once during the Resolution process. When Java method is JIT-compiled, the symbolic references are already resolved and verified. In fact,

Do inline functions have addresses?

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问题 In section 7.1.1 of the book "The C++ Programming Language" the author states: "inline function still has a unique address and so do the static variables of an inline function" I am confused. If I have an inline function then it can't have address. Does this happen in C also? 回答1: The inline attribute is just a hint to the compiler that it should try to inline your function. It's still possible to take the address of the function, and in that case the compiler will also need to emit a non

inline函数

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inline函数 1.什么是inline函数内联函数是指用inline关键字修饰的函数。如果内联函数在类体内定义，不用inline关键字声明，默认为内联函数，在编译阶段遇到函数调用直接进行代码展开。 2.内联具体是怎么实现的？编译器在它的符号表里放入函数类型和参数（包括函数名字和参数类型及返回值类型），另外，编译器看到内联函数和内联函数的分析没有错时，函数的代码也被放入符号表中，代码是以源程序的形式存放还是以编译过的指令存放取决于编译器。 3.inline 函数的优缺点优点: 没有函数的开栈与清栈过程使得效率高。缺点： 1. 以代码膨胀为代价，用空间换取了时间。 2.如果内联函数发生了改动，那么就需要重新编译代码； 3.要把内联函数放在头文件中；建议：开栈和清栈消耗 > 执行的消耗代码少设置为inline函数执行的消耗 > 开栈的消耗代码多不设置inline函数 4.inline 函数注意事项 1.inline的定义和实现写在头文件中， 2.inline 函数只在release版本生效， 3.inline函数只是给编译器的一个建议，所以最后能否真正内联，看编译器的意思，它如果认为函数不复杂，能在调用点展开，就会真正内联，并不是说声明了内联就会内联。（例如，递归，for，switch等） inline void Print(int *arr, int

Is it good practice to make getters and setters inline?

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问题 public: inline int GetValue() const { return m_nValue; } inline void SetValue(int nNewValue) { this -> m_nValue = nNewValue; } On Learn C++ , they said it would run faster. So, I thought it would be great to use on getters and setters. But maybe, there are some drawbacks to it? 回答1: I don't inline anything until a profiler has specifically told me that not inlining is resulting in a performance problem. The C++ compiler is very smart and will almost certainly automatically inline such simple

Can GHC really never inline map, scanl, foldr, etc.?

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问题 I've noticed the GHC manual says "for a self-recursive function, the loop breaker can only be the function itself, so an INLINE pragma is always ignored." Doesn't this say every application of common recursive functional constructs like map , zip , scan* , fold* , sum , etc. cannot be inlined? You could always rewrite all these function when you employ them, adding appropriate strictness tags, or maybe employ fancy techniques like the "stream fusion" recommended here. Yet, doesn't all this