hyperlink

问题 I have an HTML page in which there is <a href="example.com"><i class="myclass"></i></a> <a href="http://www.google.com" class="cart visible-xs"><i class="t-icon t-icon-cart-xs-2"></i></a> but from wave accessibility tool it's showing an error that the anchor tag contains no text, although I am using <i> tag inside the <a> tag, but I cannot write anything inside anchor tag. 回答1: According to the WAVE tool the two <a> elements you provided both contain Empty Links which violate WCAG 2.0

问题 I have a page that displays a list of users. each user has an ID and a HyperlinkButton to watch more details about the user. When pressing the HyperlinkButton, I would like to navigate to another page (called UserDetails) and somehow read the ID of the user that was pressed. How can I do that? Thanks, Ronny 回答1: I Found a nice solution, but I would like to hear something that is more elegant. Within the UriMapper section I have added another UriMapping: <uriMapper:UriMapping Uri="/UserDetails

问题 This question already has answers here : Change link color of the current page with CSS (13 answers) Closed 2 years ago . I'd like to add a CSS background color to any link in the sidebar navigation (#subnav) that matches the current URL exactly. I've tried div#subnav a:active { background: #f1f2f2; } , but it didn't work. Any help would be appreciated! UPDATE: The code for the subnav is as follows: <!-- START ALL PRODUCTS SUBNAV --> {% if collection.handle == 'all' %} <div id="back_link"><a

问题 I have the following link: <a class="btn btn-primary" href="#">View details »</a> How can I render the link with sitecore glass that it still keeps the css class? With the field renderer in sitecore you used to be able to pass the class along as additional parameters, how does this work with glass? This is what I have so far: @RenderLink(x => x.Link) This only renders the link without the class though. Any help appreciated. Thx. 回答1: You can also make a PageEditor enabled version like this

问题 If I have an action Application.show(tag: String) , and also have a corresponding routing entry, how can I insert a link to this action to a template without crafting the url manually? I would like to do something like magiclink(Application.show("tag")) . 回答1: syntax: <a href='@routes.Application.show("some")'>My link with some string</a> By analogy you can also generate urls in your controllers. ie. for redirecting after some action: public static Result justRedirect(){ // use as String

问题 My example: I have a View that presents a set of div tags that has content populated from the datamodel. [Multiple of these, with different location_id, naturally] <div> <a name="location_id"></a> Content </div> Now, I have a form [in its own view] that submits content that adds another record to the datamodel. Once the record is create and submitted, I redirect back to the Action that returns the View with the <div> listing. My challenge: I'd like the page to focus the <div> block that was

问题 How can you retrieve the value of the rel attribute of a given link and pass it to the handler? I have a list of links such that Link list <div id='one_answer'>Answer1 <a href="$" class="delete_answer" rel='Answer1'>delete</a> </div> <div id='one_answer'>Answer2 <a href="$" class="delete_answer" rel='Answer2'>delete</a> </div> <div id='one_answer'>Answer3 <a href="$" class="delete_answer" rel='Answer3'>delete</a> </div> These links are generated by the following code. The following value of

问题 i want to build a website using codeigniter. The website is look like a social agregator for my school. to build my website i plan : making a class "pages". The class "pages" has a common function login, register , logout.. etc. making a "user" class the class "user" has a function related to user needs like: edit profile, add social api, view_profile etc. i know if we want to see a profile we should pass an url like : www.Mysite.com/user/view_profile/ <user name> I dont know how to make a

问题 Is there any way to get video id from youtube link. I have a way in php script, but I need it in javascript. Here is my php script function get_youtube($url){ parse_str( parse_url( $url, PHP_URL_QUERY ), $my_array_of_vars ); return $my_array_of_vars['v']; } For example I have a youtube video link http://www.youtube.com/watch?v=fWNaR-rxAic&list=RD029I9Ar6upx34 then I get content of V variable = fWNaR-rxAic 回答1: The below function will return video id of the video if it is a valid youtube url

问题 All, I'm trying to use the jQuery Form Validator (http://docs.jquery.com/Plugins/Validation). However I'd like to be able to click a link to do the validation and then submit the form if everything is ok. Does anyone know how to do this? Any tips or suggestions would be greatly appreciated. Thanks! 回答1: Totally possible. The plugin docs even give an example, which I've modified a little bit to submit instead of alert: $("#myform").validate(); $("a.check").click(function() { if ($("#myform")