httpresponse

org.apache.http.ProtocolException: Target host is not specified

时间秒杀一切 提交于 2020-01-30 04:06:32
问题 I have written a simple httprequest/response code and I am getting this below error. I have referenced httpclient, httpcore, common-codecs and common-logging in my classpath. I am very new to java and have no clue what is going on here. Please help me. Code: import org.apache.http.client.HttpClient; import org.apache.http.client.methods.HttpGet; import org.apache.http.HttpResponse; import org.apache.http.impl.client.HttpClientBuilder; import org.apache.http.Header; import org.apache.http

org.apache.http.ProtocolException: Target host is not specified

馋奶兔 提交于 2020-01-30 04:06:20
问题 I have written a simple httprequest/response code and I am getting this below error. I have referenced httpclient, httpcore, common-codecs and common-logging in my classpath. I am very new to java and have no clue what is going on here. Please help me. Code: import org.apache.http.client.HttpClient; import org.apache.http.client.methods.HttpGet; import org.apache.http.HttpResponse; import org.apache.http.impl.client.HttpClientBuilder; import org.apache.http.Header; import org.apache.http

Capture webview requests and responses

南笙酒味 提交于 2020-01-28 02:56:12
问题 I am creating an app in which the user can browse the web via a webview element. <webview src='user-generated'></webview> I would like to be able to capture all of the requests and responses that are generated in the process. I have been looking around for the past two hours trying to figure out how to do this, but have not found anything even remotely relevant. I read something about using session to retrieve session cookies, and I had imagined other stuff like requests and responses,

How to read response of php code to android java code

梦想的初衷 提交于 2020-01-25 12:52:47
问题 I have a php code running on a wamp server which returns all the contents of database as a JSON array. I want to connect my android app to this php file. How do i get the response of this php file to my android java code. MY PHP CODE: <?php $con = mysqli_connect("localhost","root","2015","testdatabase") or die("Error " . mysqli_error($link)); if (!$con) { die('Could not connect: ' . mysqli_error()); } $result = mysqli_query($con,"SELECT * FROM Customer"); while($row = mysqli_fetch_assoc(

How to read response of php code to android java code

自闭症网瘾萝莉.ら 提交于 2020-01-25 12:52:28
问题 I have a php code running on a wamp server which returns all the contents of database as a JSON array. I want to connect my android app to this php file. How do i get the response of this php file to my android java code. MY PHP CODE: <?php $con = mysqli_connect("localhost","root","2015","testdatabase") or die("Error " . mysqli_error($link)); if (!$con) { die('Could not connect: ' . mysqli_error()); } $result = mysqli_query($con,"SELECT * FROM Customer"); while($row = mysqli_fetch_assoc(

org.apache.http.ProtocolException: Target host is not specified

﹥>﹥吖頭↗ 提交于 2020-01-24 19:31:31
问题 I have written a simple httprequest/response code and I am getting this below error. I have referenced httpclient, httpcore, common-codecs and common-logging in my classpath. I am very new to java and have no clue what is going on here. Please help me. Code: import org.apache.http.client.HttpClient; import org.apache.http.client.methods.HttpGet; import org.apache.http.HttpResponse; import org.apache.http.impl.client.HttpClientBuilder; import org.apache.http.Header; import org.apache.http

django: return image data from a view

风流意气都作罢 提交于 2020-01-22 13:54:13
问题 I want a view to return image data. so something along the lines of return HttpResponse(image_data, mimetype=”image/png”) I know I can do a file.read() to get the image data, but because the image is small (like 1x1 px) I want to just store it as a string object (or whatever object I can copy and paste in my code). This way, I save myself the disk lookup everytime the view is hit. How do i go about this? I'm sure this is easy, I'm just not sure what terms to use for search. p.s. I know that

Parsing a JSON response using Unmarshal [duplicate]

社会主义新天地 提交于 2020-01-22 03:57:06
问题 This question already has answers here : JSON and dealing with unexported fields (2 answers) Closed 2 years ago . I am trying to parse a JSON response with the following code: type Token struct { access_token string `json:access_token` token_type string `json:token_type` expires_in int `json:expires_in` } homeURL := "https:/blah.com/oauth2/token" v := url.Values{} v.Set("client_id", "xxx") v.Set("client_secret", "xxx") v.Set("grant_type", "xxx") s := v.Encode() req, err := http.NewRequest(

send custom HTTP response with PHP

℡╲_俬逩灬. 提交于 2020-01-17 08:47:17
问题 I want to send a custom HTTP response back to an application requesting a GET to a php script. The body is will be in binary format (octet-streams). I'm wondering if there is a simple way to do this? I am looking into the HttpResponse class in PECL but is having trouble installing it right now. I do not really need all the other functionalities that goes with it so I'm looking for something simpler. Any help would be appreciated. 回答1: PHP has a header() function built in, so you can customise

POST without response in Django/Javascript interaction

佐手、 提交于 2020-01-17 00:40:27
问题 I have a happy javascript based client that talks to my Django server-side code. I use several XMLHttpRequests for interactions and everything is fine there. Now there is one user interaction where I'd like to receive user-sent info at the server, but I don't need/want a response. As I understand Django all views MUST respond with an HttpResponse item. I can send back a blank one, or a HttpResponseNotModified response. But anything I receive back seems to prompt the browser side to change to