grid

问题 Unfortunately Bootstrap in Beta version drops push-* and pull-* classes, so I don't have idea how to reorder columns in xs and sm devices from: [column_1] [column_2] [column_3] to: [column_1][column_3] [column_2] Any ideas? 回答1: There are new Reordering helper classes. Place the divs in HTML as you want them to appear in mobile: <div class="container"> <div class="row"> <div class="col-6 col-md-4"> [column_1] </div> <div class="col-6 col-md-4 order-md-12"> [column_3] </div> <div class="col-6

问题 I couldn't find a way how to Draw line using grid. I want to have a line going from North to South seperating left and right frames. self.left= Frame(self.tk, bg="black") self.left.grid(column=0, row = 0, pady=5 ,padx=10, sticky=N) self.center = Frame (self.tk ,bg= "black") self.center.grid(column=1, row = 0, pady=5,padx=10, sticky=N) self.right= Frame(self.tk, bg="black") self.right.grid(column=2, row = 0, pady=5,padx=10, sticky=N) I want something like self.w.create_rectangle(self

问题 In this sample Ext Js grid: http://dev.sencha.com/deploy/ext-4.0.2a/examples/dd/dnd_grid_to_grid.html You can drag and drop items from one grid to another, but you can't change the order of items in the second grid. You can drop items back and forth and order them the way you wish, but that's not an elegant way of doing it. What needs to change in the code so that one can move items up and down on the second grid (the one on right) ? Is it even possible? 回答1: All you need to do is to make

问题 I have a problem with sorting my ExtJS grid. I'm using Ext JS version 5.1.1.451. The grid loads well but when I try to sort the columns I get the "Uncaught TypeError: Cannot read property 'isSynchronized' of undefined" error. The method addCls is triggered on mouse movement and when the error occures, me.getData() returns undefined , where me is constructor $observableInitialized: true component: constructor config: Object destroy: () {} dom: null el: null events: Object hasListeners: statics

问题 im pretty new to extjs and having trouble with it i am using the browser-layout example for my application im trying to add a form grid to it i defined a new class but when i call my form grid i get this error Uncaught TypeError: Cannot call method 'insert' of undefined here is my code: Ext.define('Ext.app.myFormGrid', { extend: 'Ext.grid.Panel', alias: 'widget.formgrid ', myData: [ ['3m Co', 71.72, 0.02, 0.03, '9/1 12:00am'], ['Alcoa Inc', 29.01, 0.42, 1.47, '9/1 12:00am'], ['Altria Group

问题 I am pretty new to WPF and am building an Charting application using WPF. I am adding new rows dynamically and it works perfectly. I am seeing a problem when removing rows. This is my code for adding rows RowDefinition newRow = new RowDefinition(); newRow.Name = "ADX"; newRow.Height = new GridLength(1, GridUnitType.Star); this.chartForm.sciChartControl.ContentGrid.RowDefinitions.Add(newRow); Grid.SetRow(scs, this.chartForm.sciChartControl.ContentGrid.RowDefinitions.Count - 1); this

问题 this is my simple try-it application that create a grid with 2 rows. The 1st row's height is bound to a properties. The value I assigned to it only works at run-time. I tried to make it also work when design-time but I failed to do that (I used this thread to write my app). Please help me to see what I miss. Thank you! [Edit] The reason why I do this is that I want to set dynamically the height of the top grid row, ie. Grid.Row="0" , to be the title bar height. Somewhere in my app, the view

问题 So, right now I'm submitting jobs on a cluster with qsub , but they seem to always run on a single node. I currently run them by doing #PBS -l walltime=10 #PBS -l nodes=4:gpus=2 #PBS -r n #PBS -N test range_0_total = $(seq 0 $(expr $total - 1)) for i in $range_0_total do $PATH_TO_JOB_EXEC/job_executable & done wait I would be incredibly grateful if you could tell me if I'm doing something wrong, or if it's just that my test tasks are too small. 回答1: With your approach, you need to have your

问题 I am binding an items control to a datasource and using a grid as my itemshost. I wish to have the items locate themselves into the correct cell in the grid (I can do this), and also stack themselves so they are not all on top of each other (I can't figure out how to insert the items into a stackpanel or other panel in the grid). here is the .cs file for the two classes: public class listofdata { public List<data> stuff { get; set; } public listofdata() { stuff = new List<data>(); stuff.Add

问题 Is there any chance to get the DOM values of the last selected row inside a grid. I could only get the record with values and not the DOM elements. With DOM elements I mean the <tr> element of the row selected. var selectedRecord = grid.getSelectionModel().getLastSelected(); //only gets the model instance that is selected 回答1: You can use grid's view getNode() method. It returns HTMLElement of the grid record's row. If you want to do something with row HTML element you can use Ext.get()