forward

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: my intention is to process a ResourceRequest that serves a resource (A dinamically generated PDF). If something goes wrong generating this file, the whole portal with a failure message in the portlet should be rendered. Is it possible to forward a ResourceRequest to a request that renders the complete portal? I am also considering a redirect, but I will like to be able to pass some attributes/parameters along. I hope I explained my problem clear enough. Thank you. Related/Duplicate: How to make the ResourceResponse to forward the request to

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have an Action method in Foo Controller which requires parameters: public function fooAction($one, $two) { $a = one; $b = $two; } And I need to forward to that method from the other method of some Boo Controller. And one of those parameters has to be by reference parameter. The only example that the manual has is this: $result = $this->forward()->dispatch('Boo\Controller\Boo', array('action' => 'boo')); No any additional parameters. But they write: $params is an optional array of parameters with which to see a RouteMatch object for

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: The controller redirect() method in Lithium does an actual HTTP redirect. But is there a method to simply forward a request to another controller/action without an HTTP redirect? For example, say I want to add an authentication layer and rather than redirecting the user to a "/auth/login" page, the login layout and template get rendered rather than the content for the page they requested. Then, when they submit the form and they authenticate, they're already on the page they requested. Zend framework has something similar with a _forward()

　　weak callback template<typename CLASS, typename... ARGS> class WeakCallback { public: WeakCallback(const std::weak_ptr<CLASS>& object, const std::function<void (CLASS*, ARGS...)>& function) : object_(object), function_(function) { } // Default dtor, copy ctor and assignment are okay void operator()(ARGS&&... args) const { std::shared_ptr<CLASS> ptr(object_.lock()); if (ptr) { function_(ptr.get(), std::forward<ARGS>(args)...); } } private: std::weak_ptr<CLASS> object_; std::function<void (CLASS*, ARGS...)> function_; }; template<typename CLASS, typename... ARGS> WeakCallback<CLASS, ARGS...>

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm reading Overview of the New C++ (C++11/14) (PDF only) , at Slide 288 it gives an implementation of std::forward : template<typename T> // For lvalues (T is T&), T&& std::forward(T&& param) // take/return lvalue refs. { // For rvalues (T is T), return static_cast<T&&>(param); // take/return rvalue refs. } And then gives another implemention in text: The usual std::forward implementation is: template<typename T> struct identity { typedef T type; }; template<typename T> T&& forward(typename identity<T>::type&& param) { return static_cast

What's the best solution to forward declare a typedef within a class. Here's an example of what I need to solve: class A; class B; class A { typedef boost::shared_ptr<A> Ptr; B::Ptr foo(); }; class B { typedef boost::shared_ptr<B> Ptr; A::Ptr bar(); }; I suppose I could just do the following: boost::shared_ptr<B> foo(); But is there a more elegant solution? There is no such thing as forward declaring a typedef unfortunately. However, there's a trick using late template instantiation: template <typename T> class BImpl; template <typename T> class AImpl { public: typedef boost::shared_ptr<AImpl>

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: import java.io.*; import jxl.*; class Xlparsing { Workbook wb =wb.getWorkbook(new File( "C:\\Documents and Settings\\kmoorthi\\Desktop\\ak\\new.xls")); // Illegal forward reference What it means Sheet st = wb.getSheet(0); Cell cell1 = st.getCell(0,0); String a1 = cell1.getContents(); public static void main(String s[]) { System.out.println(new Xlparsing().a1); } } Hi When I tried to extract data from excel sheet illegal forward reference error comes in the file object creation. How to resolve this? 回答1: "Illegal forward reference" means that

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I keep getting Forward reference extends over definition of value a error while trying to compile my application (inside SBT). a is just val a = "" , the error is triggered by accessing a particular parameter (of the function) right before a definition. The parameter is of a simple case class type with all three fields of Option[...] type (2 of Option[org.joda.time.DateTime] and 1 of Option of an enumeration value). What can "Forward reference extends over definition of value" mean at all and what can be the ways to fight it? 回答1: Depending

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: When facing difficulties during training ( nan s , loss does not converge , etc.) it is sometimes useful to look at more verbose training log by setting debug_info: true in the 'solver.prototxt' file. The training log then looks something like: I1109 ...] [Forward] Layer data, top blob data data: 0.343971 I1109 ...] [Forward] Layer conv1, top blob conv1 data: 0.0645037 I1109 ...] [Forward] Layer conv1, param blob 0 data: 0.00899114 I1109 ...] [Forward] Layer conv1, param blob 1 data: 0 I1109 ...] [Forward] Layer relu1, top blob conv1 data: 0

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have a UIView and I'm trying to set its layer properties. self . colorSwatch = [[ UIView alloc ] initWithFrame : CGRectMake ( 400 , 150 , 100 , 100 )]; self . colorSwatch . layer . cornerRadius = 8 ; However, when I try to access the .layer.cornerRadius property, I get a warning that says "Property 'cornerRadius' cannot be found in forward class object 'CALayer *'. What does this mean? Thanks 回答1: It doesn't know what type of object the layer property is. Add #import to the top of your file. 回答2: You need to import the file