forms

How to get child record (case class) ID in Play Framework (2.4.0) using Forms

你说的曾经没有我的故事 提交于 2020-01-17 03:44:31
问题 I'm afraid I'm not seeing it yet. There must be a way, using the tools as they are intended to be used, to get the ID of a child record (many-to-one typical relational database stuff) of a series of "items" I can create a "form" (mapping) in the case class of the parent no problem. lazy val aForm = Form( mapping( "ID" -> ignored(id), "firstName" -> nonEmptyText, "lastName" -> nonEmptyText, "listOfEmails" -> seq(email), "statusID" -> ignored(0l), "roleID" -> default(longNumber, roleID),

textarea doesnt return value

无人久伴 提交于 2020-01-17 03:33:07
问题 Im using a code editor codepress in all of my textareas, but no textarea return a value. I think the different name and id is the problem. Example: <textarea name="content_text" rows="20" cols="50" class="codepress sql" id="myCpWindow"></textarea> I have read somewhere in here to use a hidden input to transfer the textarea's value, but i cant do it myself! ayhelp? 回答1: Both answers didnt work... In the support forum of codepress i found this: <input type="submit" onclick="textareaID.textarea

Editing Many RichTextBoxes and TextBoxes

断了今生、忘了曾经 提交于 2020-01-17 03:28:17
问题 How do i cut,copy,paste from main menu in a multi textboxes form ? How does the menu knows to apply on the active textbox ? 回答1: Please see this article here on Codeproject that does the job in synchronizing each text box's "standard" edit menu such as Copy, Cut, Paste, Undo, Select All. Of course, the code originally targets the .NET 1.1, but it can be easily recompiled to target the newer frameworks as well. 回答2: In the menu click event you can examine this.ActiveControl to see what control

Drupal 6 Validation for Form Callback Function

岁酱吖の 提交于 2020-01-17 03:27:12
问题 I have a simple form with a select menu on the node display page. Is there an easy way to validate the form in my callback function? By validation I don't mean anything advanced, just to check that the values actually existed in the form array. For example, without ajax, if my select menu has 3 items and I add a 4th item and try to submit the form, drupal will give an error saying something similar to "an illegal choice was made, please contact the admin." With ajax this 4th item you created

What is correctness in symfony to fill a form in two steps?

青春壹個敷衍的年華 提交于 2020-01-17 03:26:08
问题 Hy, What is correctness in symfony to fill a form in two steps? Imagine that we have a entity called Enterprise and we want to create a form with only required fields and another form, that when the user login can fill the other non-required fields. How is the correctness form? Now i have a form to registration ('lib/form/doctrine/EnterpriseForm.class.php') and another ('lib/form/doctrine/EnterpriseCompleteForm.class.php').In every class we set labels, validators, ... but the problem is in

Add Text to option from the label with pure JS

早过忘川 提交于 2020-01-17 03:25:31
问题 I have a script that applies the label text as a placeholder attribute on the input, however I have one select dropdown field where i need the first option, which is currently just blank, to contain the label name. In this case region I have thought about using another label.querySelectorAll("option"); But i don't know how to just get the top one. Current JS: var labels = document.querySelectorAll("label"); var i = labels.length; while (i--) { var label = labels.item(i); var text = label

How to do “HTML FORM action=location.replace('nextpage.html')”?

不羁岁月 提交于 2020-01-17 03:13:05
问题 The title is actually a failed attempt to achieve my goal. Specifically, I want to 1. Go to a page from main.html (say, to page1.html). 2. Collect data in a form on page1. 3. On Submit, go to page2.html (which saves data to database using PHP and announces result). 4. Click on "Ok" and go back to main menu page. Seems reasonable, right? Step 4 above is my problem. Things I've tried: 1. Invoke history.back on Ok click in page2. This goes to page1 not main 2. Invoke javascript location.href

Validate that a URL entered in a form is from a specific website with javascript

↘锁芯ラ 提交于 2020-01-17 02:53:34
问题 I have a website where people post links from Google+. I am trying to make sure that people can only post specific links from Google plus. An example would be, someone would need to post a link like https://plus.google.com/games/907809777960/params/%22%7B%5C%22encPrms%5C%22%3A%5C

Altering arrays in php from post to a session variable

≯℡__Kan透↙ 提交于 2020-01-17 02:38:08
问题 a couple of days ago, I posted here and got a great response on how to handle the arrays. This was exactly what I needed foreach ($_POST['name'] as $key=>$name) { echo "Name: $name Age: {$_POST['age'][$key]}"; } the problem is, I need it not to print but to persist. Im making session variables like $_SESSION["name"]= "some name"; I wanna know how I can dump the POST array from above into a $SESSION[Array]; ultimately, to be able to re dump all of the data at will on any page. I need access to

Django form “takes exactly 1 argument (2 given) ” error - possibly related to CSRF?

杀马特。学长 韩版系。学妹 提交于 2020-01-17 02:26:32
问题 I am attempting a fairly simple form on Django 1.3, and am trying to understand how CSRF works. I think I've followed the three steps detailed on the Django site, but am still unable to make the form work. The form displays when the URL is loaded, however upon hitting the submit button, I get the following error: TypeError at /txt/ txt() takes exactly 1 argument (2 given) Here's the actual code: views.py: from django.http import HttpResponse from django.shortcuts import render_to_response,