format

问题 I am getting the following errors: In function 'main': [Warning] unknown conversion type character 'L' in format [-Wformat=] [Warning] too many arguments for format [-Wformat-extra-args] In function 'error_user': [Warning] unknown conversion type character 'L' in format [-Wformat=] [Warning] too many arguments for format [-Wformat-extra-args] In the below code: #include <stdio.h> #include <stdlib.h> void error_user (long double *error); int main(void) { long double error; printf("What error

问题 I am getting the following errors: In function 'main': [Warning] unknown conversion type character 'L' in format [-Wformat=] [Warning] too many arguments for format [-Wformat-extra-args] In function 'error_user': [Warning] unknown conversion type character 'L' in format [-Wformat=] [Warning] too many arguments for format [-Wformat-extra-args] In the below code: #include <stdio.h> #include <stdlib.h> void error_user (long double *error); int main(void) { long double error; printf("What error

问题 I just want to ask how to make a JavaScript of currency format of input type text. Is it possible that the numbers will have comma while you type the number? Also, how to make the number fixed with 2 decimal numbers. If I input a 3 decimal placed numbers the last number will round off so it can be 2 decimal. I have a textbox which accepts numbers only and I want it to automatically convert the numbers into currency format. 1234.556 will be Php 1,234.56 . (Php means Philippine peso) Here's my

问题 If I'm dealing with hundreds of graphs, which are right now automatically setting the y axis, how can I eliminate 10.0%, 20.0%, and make it simply 10%, 20% (a savings of 2 characters)? I'm using Excel 2010, and don't want to mess up automatic formatting since there may be times that I need the percent decimal places, as in unemployment (4.5% is meaningful). Of course, sometimes I graph stuff on the y axis in millions or billions of dollars (but that's a separate question). Update: I found out

问题 There is an HDF file 'file.h5' and the key name of a pandas DataFrame (or a Series) saved into it is 'df'. How can one determine in what format (i.e. ‘fixed’ or ‘table’) was 'df' saved into the file? Thank you for your help! 回答1: A bit late but maybe someone else may find it helpful. You can parse the output of HDFStore.info(). Objects in table format have the type appendable : >>> print(h5_table.info()) <class 'pandas.io.pytables.HDFStore'> File path: /tmp/df_table.h5 /df frame_table (typ-

问题 it's very hard to find information about {:} online I saw some code below: def dateformat(date): day, month, year=date.split('/') return "{:4d}{:02d}{:02d}".format(int(year),int(month),int(day)) I kinda of know it is filling leading 0 in the format, but I don't know what do '02' and 'd' in {:02d} do? 回答1: You are looking for the str.format() documentation. Specifically, the 02d part is documented in the Format Specification Mini-Language. 02d formats an integer ( d ) to a field of minimum

问题 it's very hard to find information about {:} online I saw some code below: def dateformat(date): day, month, year=date.split('/') return "{:4d}{:02d}{:02d}".format(int(year),int(month),int(day)) I kinda of know it is filling leading 0 in the format, but I don't know what do '02' and 'd' in {:02d} do? 回答1: You are looking for the str.format() documentation. Specifically, the 02d part is documented in the Format Specification Mini-Language. 02d formats an integer ( d ) to a field of minimum

问题 it's very hard to find information about {:} online I saw some code below: def dateformat(date): day, month, year=date.split('/') return "{:4d}{:02d}{:02d}".format(int(year),int(month),int(day)) I kinda of know it is filling leading 0 in the format, but I don't know what do '02' and 'd' in {:02d} do? 回答1: You are looking for the str.format() documentation. Specifically, the 02d part is documented in the Format Specification Mini-Language. 02d formats an integer ( d ) to a field of minimum

问题 A similar question has been asked before but has received no responses I have looked through a number of forums for a solution. The other questions involve a year but mine does not - it is simply H:M:S I web scraped this data which returned Time - 36:42 38:34 1:38:32 1:41:18 Data samples here: Source data 1 and Source data 2 I need this time in minutes like so 36.70 38.57 98.53 101.30 To do this I tried this: time_mins = [] for i in time_list: h, m, s = i.split(':') math = (int(h) * 3600 +

问题 Hi I'm receiving a string with a date format yyyy-MM-dd , but I want to compare it with a format dd-MM-yyyy in case it is not the same, sure is not, I want to convert it, the problem for me it's not to convert, it's to compare both formats... so I imagine maybe it's something like this var dt = obj.date; //this a string if (dt.formatDateorsomethingIguess == "dd/MM/yyyy") //this is the part I'm asking for { usedt(dt); } else { DateTime dt_format = DateTime.ParseExact(dt.Trim(), "dd-MM-yyyy",