format

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 6 years ago . Apparently "if", "and", and "or" are such generic search parameters that I can't find the answer on google for my life. Which of these is the correct format according to the Java standards? Option 1 : if (condition1 && condition2 && condition3) ... or Option 2 : if

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 6 years ago . Apparently "if", "and", and "or" are such generic search parameters that I can't find the answer on google for my life. Which of these is the correct format according to the Java standards? Option 1 : if (condition1 && condition2 && condition3) ... or Option 2 : if

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 6 years ago . Apparently "if", "and", and "or" are such generic search parameters that I can't find the answer on google for my life. Which of these is the correct format according to the Java standards? Option 1 : if (condition1 && condition2 && condition3) ... or Option 2 : if

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 6 years ago . Apparently "if", "and", and "or" are such generic search parameters that I can't find the answer on google for my life. Which of these is the correct format according to the Java standards? Option 1 : if (condition1 && condition2 && condition3) ... or Option 2 : if

问题 How can I format the time elapsed from seconds to hours, mins, seconds? My code: start = time.time() ... do something elapsed = (time.time() - start) Actual Output: 0.232999801636 Desired/Expected output: 00:00:00.23 回答1: If you want to include times like 0.232999801636 as in your input: import time start = time.time() end = time.time() hours, rem = divmod(end-start, 3600) minutes, seconds = divmod(rem, 60) print("{:0>2}:{:0>2}:{:05.2f}".format(int(hours),int(minutes),seconds)) Example: In

问题 I have a dataframe df that look like this: ID Date 0 1 2008-01-24 1 2 2007-02-17 The format of Date is %Y-%m-%d How can I format the dates to %m-%d-%Y format? I tried using this syntax but it did not give the right format: df["Date"] = df["Date"].strftime("%m-%d-%Y") Any idea how to solve this? 回答1: Use the .dt accessor: df["Date"] = df["Date"].dt.strftime("%m-%d-%Y") 回答2: The accepted answer from root only works if the Date column contains datetime instances. The dataframe shown by the

问题 I'm using the following custom log format to view my commits: Command: git log --pretty=format:"%C(auto)%h %<(8,trunc)%aN %Cgreen%s %+b" 3758d35 Daniel This commit does nothing You really should remove it before commiting. 1. This is a line 2. This is another line a191c2b Daniel Viral helvetica lomo, typewriter fashion axe 814a6a9 John Umami pork belly pickled, fanny pack yr keffiyeh fap YOLO d5e130e Daniel Cardigan raw denim banjo f7107d8 Daniel 90's ramps pinterest, craft beer blue bottle

问题 So I am looking to simply format the offset string (at least that is what i think it is called, see image) that matplotlib places along with an axis that has been set to show tick labels in scientific notation, but where the range is less than one order of magnitude (power of 10). here is what I am talking about: Essentially, how do I make it bigger/coloured? 回答1: you can use ax.yaxis.get_offset_text() to access the offset text. You can then set the size and color on that Text object. For

问题 I'm trying to read DBase 7 timestamp values from .dbf files. From DBase format specification I got the following: 8 bytes - two longs, first for date, second for time. The date is the number of days since 01/01/4713 BC. Time is hours * 3600000L + minutes * 60000L + Seconds * 1000L However, I didn't get any correct values via this algorithm. Here are some timestamp values in binary representation and actual datetime values: 42 CC E1 EC 41 FB 64 00 | 27/08/2013 19:12:13 42 CC E1 ED AF 0E 60 00

问题 How can I format a float, from a pandas dataframe, to separate thousands by dots and commas, instead by commas and dots? ? Input: 112299420.40 Actual output: 112,299,420.40 Required output: 112.299.420,40 My code: pd.set_option('display.float_format', lambda x: '{:,.2f}'.format(x) if abs(x) < 10000 else '{:,.0f}'.format(x)) How can I change this piece of code to produce the required output? I've tried to change it the intuitive way, but without success... From: '{:,.2f}' To: '{:.,2f}' 回答1: