file-io

How to add data to existing XLSX file in MATLAB every time using a push button?

你说的曾经没有我的故事 提交于 2021-02-17 02:38:40
问题 I have a function which generates some variable, like score, right, wrong, unanswered. This function is called using a push button. The problem is how can I add/append these values generated by a function to an XLSX file every time? Or, how to create a MAT file so that it can be added? What may be a possible solution? 回答1: The challenge involved in appending to a xls file is knowing its last row, to avoid overwriting data with the xlswrite command. I'd suggest taking a look at this file

How to add data to existing XLSX file in MATLAB every time using a push button?

假装没事ソ 提交于 2021-02-17 02:37:04
问题 I have a function which generates some variable, like score, right, wrong, unanswered. This function is called using a push button. The problem is how can I add/append these values generated by a function to an XLSX file every time? Or, how to create a MAT file so that it can be added? What may be a possible solution? 回答1: The challenge involved in appending to a xls file is knowing its last row, to avoid overwriting data with the xlswrite command. I'd suggest taking a look at this file

How to read alphanumeric values from Excel cells in Java?

[亡魂溺海] 提交于 2021-02-11 16:01:02
问题 I have to read a ZIP code from Excel sheet. Zip code can be any of the following formats: ααααα 11111-αααα 3 3 3 3 3 - 6 6 6 6 12345 123456 12345-123456 I tried cell.getRichStringCellValue() and cell.getStringCellValue() but it's not working. 回答1: Above is the Image of the excel. I have used poi to get the data, looks like you have used poi but not 100% sure. Below is the code that is working and reading all the values public static void main(String[] args) throws IOException {

Fortify security issue “Unreleased resource stream” for try-with-resource

走远了吗. 提交于 2021-02-11 14:34:11
问题 Fortify security run Noncompliant Code public static A read(String path) throws IOException, ClassNotFoundException { try (ObjectInputStream os = new ObjectInputStream(new GZIPInputStream(new FileInputStream(path)))) { return (A) os.readObject(); } } It is saying "Unreleased Resource: Streams" , but it is inside try-with-resource then what can be the issue? please help me. 回答1: Likely the issue your tool is worried about is if GZIPInputStream or ObjectInputStream throws an exception during

In Python 2.7 why are strings written faster in text mode than in binary mode?

那年仲夏 提交于 2021-02-11 14:16:37
问题 The following example script writes some strings to a file using either "w" , text, or "wb" , binary mode: import itertools as it from string import ascii_lowercase import time characters = it.cycle(ascii_lowercase) mode = 'w' # mode = 'wb' # using this mode takes longer to execute t1 = time.clock() with open('test.txt', mode) as fh: for __ in xrange(10**7): fh.write(''.join(it.islice(characters, 0, 50))) t2 = time.clock() print 'Mode: {}, time elapsed: {:.2f}'.format(mode, t2 - t1) With

Java NIO Files count() Method for Counting the Number of Lines

和自甴很熟 提交于 2021-02-10 20:20:51
问题 I was using the below code to calculate the number of lines in a file. long numberOfLines = Files.lines(filePath).count(); Based on the output of the above, if the number of lines is 1, then the record delimiter (extracted from the last character of the line) should be replaced by <delimiter>\n . The delimiter got replaced fine, but when I tried to delete this file after this operation, it did not work. if (numberOfLines == 1) { String rawData = (new String(Files.readAllBytes(filePath))).trim

Java NIO Files count() Method for Counting the Number of Lines

白昼怎懂夜的黑 提交于 2021-02-10 20:19:32
问题 I was using the below code to calculate the number of lines in a file. long numberOfLines = Files.lines(filePath).count(); Based on the output of the above, if the number of lines is 1, then the record delimiter (extracted from the last character of the line) should be replaced by <delimiter>\n . The delimiter got replaced fine, but when I tried to delete this file after this operation, it did not work. if (numberOfLines == 1) { String rawData = (new String(Files.readAllBytes(filePath))).trim

PyPDF's PdfFileReader() having problems reading file, file not callable

我的未来我决定 提交于 2021-02-10 14:18:54
问题 So here is my import: from pyPdf import PdfFileWriter, PdfFileReader Here is were I write my pdf: filenamer = filename + '.pdf' pdf = PdfPages(filenamer) (great naming convention, I know!) I write some things to it. I close it here: pdf.close() Here is where I try and read it: input1 = PdfFileReader(file(filenamer, "rb")) And here is the error: Traceback (most recent call last): File "./datamine.py", line 405, in <module> input1 = PdfFileReader(file(filenamer, "rb")) TypeError: 'file' object

ZSTD String compression using luben

我与影子孤独终老i 提交于 2021-02-10 14:14:58
问题 I have been struggling to compress a regular string to ZSTD format using the Luben library (v1.4.0-1). I do the following: byte[] zstdBytes = Zstd.compress(payload.getBytes(StandardCharsets.UTF_8)); ZstdInputStream zstdInputStream= new ZstdInputStream(new ByteArrayInputStream(zstdBytes)); However while reading the zstdInputStream I get the following error: java.io.IOException: Decompression error: Unknown frame descriptor at com.github.luben.zstd.ZstdInputStream.readInternal(ZstdInputStream

Why am I getting unwanted newline in my string?

若如初见. 提交于 2021-02-09 10:56:35
问题 This should be so simple, it's silly. But I can't get it to work. I have a header which I define while reading a file: if "[gene=env]" in line or "[gene=HIV2gp7]" in line: header = line now this header looks something like ">lcl|NC_001802.1_prot_NP_057856.1_8 [gene=env]" I need to attach a number to it like so: ">lcl|NC_001802.1_prot_NP_057856.1_8 [gene=env]1" I have 100 identical headers, which have to be numbered 1 through 100 But whatever I try, I can't get the number on the same line. The