extend

Creating custom Object3D class

一个人想着一个人 提交于 2019-12-05 05:03:02
问题 I'm new to THREE.js coming from an AS3/Away3D background. I'm trying to create a custom object class that extends THREE.Object3D to add to my scene. CustomObject will encapsulate a lot of behavioural properties and methods. Ideally I'd like to pass each CustomObject it's own data object which will determine how it will look/move/behave. Encapsulating this code will keep my main.js a lot cleaner. My problem is I can't seem to add an instance of the class directly to my scene. I can only add

Extending hibernate entities with annotation

北城余情 提交于 2019-12-04 20:11:37
问题 i need to extend an entity, with the same characteristics without using abstract classes. can i code something like below? @Entity @Table(name="ABC") @SequenceGenerator(sequenceName="SEQ_ABC",name="idGenerator",allocationSize=1) public class Abc { .. // define members } @Entity @Table(name="EX_ABC") public class ExAbc extends Abs { .. // define extras.. } thx in advance 回答1: Yes, this one works without any problems. However you should have a look at the inheritance annotation. What's the

Laravel extending class

别说谁变了你拦得住时间么 提交于 2019-12-04 19:40:24
Are there any other steps required to extend a class in Laravel 3? I created application/libraries/response.php : class Response extends Laravel\Response { public static function json($data, $status = 200, $headers = array(), $json_options = 0) { $headers['Content-Type'] = 'application/json; charset=utf-8'; if(isset($data['error'])) { $status = 400; } dd($data); return new static(json_encode($data, $json_options), $status, $headers); } public static function my_test() { return var_dump('expression'); } } But for some reason, neither the my_test() function, or the modified json() function works

Laravel extend a vendor class installed from composer

回眸只為那壹抹淺笑 提交于 2019-12-04 19:10:16
问题 Hi I am using the following package https://github.com/jayhealey/Robots to add a different robots.txt file per environment I have on my application. However this is missing one method I am using on my application which is the crawl delay i.e. Crawl-delay: 3600 Now i have the following folder from the composer install of this package: vendor/healey/robots/src/Healey/Robots/Robots.php and this starts as so: <?php namespace Healey\Robots; class Robots {....} Now I want to be able to extend this

Make DateTime::createFromFormat() return child class instead of parent

心不动则不痛 提交于 2019-12-04 18:05:23
问题 I'm extending DateTime do add some useful methods and constants. When using new to create a new object everything is fine but when using the static method createFromFormat it always returns the original DateTime object and of course none of the child methods are available. I am using the following code to circumvent this issue. Is this the best approach? namespace NoiseLabs\DateTime; class DateTime extends \DateTime { static public function createFromFormat($format, $time) { $ext_dt = new

What are the differences between extending Activity and extending ListActivity?

試著忘記壹切 提交于 2019-12-04 17:48:05
问题 I am using a class which extends Activity to obtain a list from an API... In some apps which do basically the same, the devs extended ListActivity... Which are the differences? 回答1: ListActivity extends the functionality of the common android.app.Activity by providing a number of list centric features 'for-free' if you like. For example, the handling of a list entry click is neatly contained within ListActivity's onListItemClick(...) whereas if you were using a plain android.app.Activity then

Can you extend the val() function in jQuery?

杀马特。学长 韩版系。学妹 提交于 2019-12-04 14:05:59
Is there a way to extend the val() function in jQuery. Basically, what I want to do is set a class variable if there is content being dynamically entered into an input. Whick normally would be something like var thisVal = 'Hello World'; $('#myInput').val(thisVal).addClass('dark'); It would just be nice to tell the val() function to always add the class 'dark' to an input if there is a value, and to remove it if it is empty. Possible? Try $.fn.xval = function () { return this.toggleClass(arguments.length).val.apply(this, arguments); }; Demo: http://jsfiddle.net/mattball/v9YFu/ You could do this

Extending a class

断了今生、忘了曾经 提交于 2019-12-04 13:42:51
EDIT Answered: Although my original question didn't explain my needs in exactly the way the answer provided by Konrad Rudolph addressed them, He (by accident or design) essentially wrote for me what I was trying to write! The class itself does not get extended, but has it's functionality extended by making the class aware of new functions which allow it (the class) to handle a wider array of issues. My grateful thanks for an excellent answer which in turn is also a great tutorial, even if it does require some ahemm light? reading of books by me ;-). I am sure that this a very basic question,

Extending Magento Shopping Cart

依然范特西╮ 提交于 2019-12-04 12:25:11
问题 I need to extend the Magento shopping cart to include an extra step for a store locator. I understand that I need to overwrite the core OnePage controller ( Mage_Checkout_OnepageController ) and blocks ( Mage_Checkout_Block_Onepage ) but what needs to be done with regards to keeping track of the extra information (e.g. user's selected options from my custom step). 回答1: There are a number of steps required here to get the whole solution. Firstly, create a new module. Use the ModuleCreator if

Private members when extending a class using ExtJS

不打扰是莪最后的温柔 提交于 2019-12-04 07:47:57
问题 I have done some research on the ExtJS forum regarding private methods and fields inside a extended class , and I couldn't find any real answer to this. And when I say an extended class I mean something like this: Ext.ux.MyExtendedClass = Ext.extend(Ext.util.Observable, { publicVar1: 'Variable visible from outside this class', constructor: function(config) { this.addEvents("fired"); this.listeners = config.listeners; }, // to show that I need to use the base class publicMethod1: function() {