extend

My attempt to simply 'Extend' the Map class fails because List is an interface and cannot be extended but must be implemented. The goal was simply to add a few methods on top of some existing class such as: List.add_unique(item) where I only want to append if the item does not already exist. This can be done nicely by and-ing the append !=null logic with List.indexOf(item) != -1 (where -1 is notFound). This would be a good and easy to understand example? But, how to accomplish this in the shortest, least overall overhead sort of way? I think I would be OK with loose typing - at least to start

Django version: 4.0.2 Django-Registration version: 0.8 App name: userAccounts PROBLEM: Im trying to create a user type called professor extending the user model. I can complete the registration process, the problem is that only the user is saved on the DB, the professor table keep empty. So i think the problem could be in the save method. Some clue about what could be the problem? SETTINGS.PY AUTH_PROFILE_MODULE = "userAccounts.Professor" MODELS.PY - Here i create the model that extending from user and a example field from django.db import models from django.contrib.auth.models import User

Working my way into Python (2.7.1) But failing to make sense (for hours) of this: >>> a = [1, 2] >>> b = [3, 4] >>> >>> a.extend([b[0]]) >>> a [1, 2, 3] >>> >>> a.extend([b[1]]) >>> a [1, 2, 3, 4] >>> >>> m = [a.extend([b[i]]) for i in range(len(b))] # list of lists >>> m [None, None] The first two extends work as expected, but when compacting the same in a list comprehension it fails. What am i doing wrong? extend modifies the list in-place. >>> [a + b[0:i] for i in range(len(b)+1)] [[1, 2], [1, 2, 3], [1, 2, 3, 4]] the return value of extend is None . list.extend() extends a list in place .

I was searching for a proper way of extending bootstrap plugin, and found this answer: https://stackoverflow.com/a/12689534/1276032 What troubles me, is the last section - initialization overriding. Copied code below: // override the old initialization with the new constructor $.fn.modal = $.extend(function(option) { var args = $.makeArray(arguments), option = args.shift(); return this.each(function() { var $this = $(this); var data = $this.data('modal'), options = $.extend({}, _super.defaults, $this.data(), typeof option == 'object' && option); if ( !data ) { $this.data('modal', (data = new

概述 我看的是3.1.0版本的，先上一段代码吧，不要版本都不一样那就尴尬了，这段代码看着没有多少，但我相信这基本上是这个世界上执行的最多的代码了，再不济也是一个之一。 直接看代码有一点绕，所以我们通过先黑盒的方式，先看实现的功能，在来分析功能实现的代码是怎么实现的。 jQuery.extend = jQuery.fn.extend = function() { var options, name, src, copy, copyIsArray, clone, target = arguments[ 0 ] || {}, i = 1, length = arguments.length, deep = false; // 如果第一个参数类型是boolean类型，处理深拷贝 if ( typeof target === "boolean" ) { deep = target; // 跳过第一个Boolean参数 target = arguments[ i ] || {}; i++; } // 如果target类型不是Object或者function就把目标对象设为空 if ( typeof target !== "object" && !jQuery.isFunction( target ) ) { target = {}; } // 如果只有一个参数就扩展jQuery本身 if (

I need to reinvent/recreate the Label Control from scratch to add my own mojoness to it. Yes, I know what you're thinking (and if you're not thinking that, shouldn't you be?). Can somebody point me in the right direction? Thank you. The whole purpose for recreating the label is that I want full control over how it is drawn onto screen, and so that I can have KeyDown Event Handlers for it, too. For example, the user can edit the contents of a label the same way they would edit the contents of a TextBox control. Also, I cannot just simply use a TextBox control, as it would require almost, if not

Here's my try: H file: @interface Strings : NSArray @end M file: @implementation Strings - (id) init { [self initWithObjects: @"One.", nil]; return self; } @end When I run I get this: 'NSInvalidArgumentException', reason: ' * -[NSArray initWithObjects:count:]: method only defined for abstract class. Define -[Strings initWithObjects:count:]!' This is what I did instead: H file: @interface Strings : NSObject + (NSArray*) getStrings; @end M file: @implementation Strings + (NSArray*) getStrings { NSArray* strings = [[NSArray alloc] initWithObjects: @"One.", nil]; return strings; } @end NSArray is