dynamic-programming

问题 In my project, I generate an object obj of type CubicObject . At runtime, a GUI setting should be allowed to change the type of obj to Tofu or Box (and back), depending on what the user wants to do and what (s)he thinks the object is best represented by. Then the user should benefit from specific algorithms implemented in the corresponding classes. I am looking for a nice implementation of this behaviour. I have played with the code below, which changes the __class__ attribute, but I am sure

问题 I recently encountered this problem in an interview There are n stairs, a person standing at the bottom wants to reach the top. The person can climb either 1 stair or 2 stairs at a time. Print all possible ways person can reach the top. For example, n=4 Output: 1 2 3 4 1 2 4 1 3 4 2 3 4 2 4 But I couldn't code this properly. How to code up solution for this? 回答1: To print the number of ways, you can first understand how to calculate the number of ways, and adjust it so each "count" will print

问题 I am trying to Dynamically Generating the Codes for Web Application I Want to read External HTML File and store it to string variable in Javascript or Jquery ? Is there any efficient way for this..? HTML File - Object-text.html <div class="text-object"> <div class='text-area'> <span class='content'> <span class='title'> title</span><br/> <span class='address'> address </span> </span> </div> <div class='patch'></div> </div> <br class='float-clear'/> JQUERY $(document).ready(function() { $.get(

问题 I am trying to Dynamically Generating the Codes for Web Application I Want to read External HTML File and store it to string variable in Javascript or Jquery ? Is there any efficient way for this..? HTML File - Object-text.html <div class="text-object"> <div class='text-area'> <span class='content'> <span class='title'> title</span><br/> <span class='address'> address </span> </span> </div> <div class='patch'></div> </div> <br class='float-clear'/> JQUERY $(document).ready(function() { $.get(

问题 I am trying to create a dynamic conditional panel. So my conditions are as follows: Input in UI: selectInput('inpt','Input Number', seq(1,50,1), selectize = FALSE) My conditional panel UI input is: conditionalPanel( "input.inpt == 2", box( selectInput("id1", "Select number", seq(1, 24, 1), selected = 1), selectInput("id2", "Select number", seq(1, 24, 1), selected = 1), width = 2, status = "primary" ) ), conditionalPanel( "input.inpt == 3", box( selectInput("id1", "Select number", seq(1, 24, 1

问题 I am trying to create a dynamic conditional panel. So my conditions are as follows: Input in UI: selectInput('inpt','Input Number', seq(1,50,1), selectize = FALSE) My conditional panel UI input is: conditionalPanel( "input.inpt == 2", box( selectInput("id1", "Select number", seq(1, 24, 1), selected = 1), selectInput("id2", "Select number", seq(1, 24, 1), selected = 1), width = 2, status = "primary" ) ), conditionalPanel( "input.inpt == 3", box( selectInput("id1", "Select number", seq(1, 24, 1

问题 Is there a way to find a number of rectangular submatrices containing all zeros with a complexity smaller than O(n^3), where n is the dimension of given matrix? 回答1: Here is a solution O(n² log n) . First, let's convert the main problem to something like this: For given histogram, find the number of submatrices containing all zeros. How to convert it ? For each position calculate the height of column that start on that position and contain only zeros. Example: 10010 01101 00111 12000 00001 ->

问题 If there is an unlimited number of every coin then the complexity is O(n*m) where is n is the total change and m is the number of coin types. Now when the coins for every type are limited then we have to take into account the remaining coins. I managed to make it work with a complexity of O(n*m 2 ) using another for of size n so I can track the remaining coins for each type. Is there a way-trick to make the complexity better? EDIT : The problem is to compute the least ammount of coins

问题 If there is an unlimited number of every coin then the complexity is O(n*m) where is n is the total change and m is the number of coin types. Now when the coins for every type are limited then we have to take into account the remaining coins. I managed to make it work with a complexity of O(n*m 2 ) using another for of size n so I can track the remaining coins for each type. Is there a way-trick to make the complexity better? EDIT : The problem is to compute the least ammount of coins

问题 Given an array of Integers, and a range (low, high), find all contiguous subsequence in the array which have sum in the range. Is there a solution better than O(n^2)? I tried a lot but couldn't find a solution that does better than O(n^2). Please help me find a better solution or confirm that this is the best we can do. This is what I have right now, I'm assuming the range to be defined as [lo, hi] . public static int numOfCombinations(final int[] data, final int lo, final int hi, int beg,