double

问题 Double is represented in memory using 8 bytes. I believe these 8 bytes should be having two components, one each for integer-part and one for the fractional-part(Correct me if I am wrong in this assumption). My machine is a little endian(Nowadays every Macmini is). I want to transfer these 8 bytes representing Double to a file, which should be readable on a BigEndian platform(Specifically JVM which is BE). It is safe for plain Integers to reverse the byte order, as they don't have components

问题 This question already has answers here : How do I print a double value without scientific notation using Java? (15 answers) Closed 4 years ago . I need to convert string value to double with dot. Here is simple code double dValue=Double.parseDouble("999999999.99"); System.out.println(dValue); output is: 9.9999999999E8 When i gave value like 10000 or 100000 it works. Help me to overcome this problem. 回答1: You could use BigDecimal and toPlainString() for that. BigDecimal dValue= new BigDecimal(

问题 I am getting error of "Double free or corruption(out)" after I print my output. But this error is only coming for small inputs. For bigger inputs program doesn't throw that error. When I create the multidimensional arrays inside the main and delete them, I do not get the error. I have only posted the part of the code which is relevant to this issue here. Please kindly explain how to resolve the issue. #include<iostream> #include<vector> using namespace std; class Knapsack{ public: int noItems

问题 I'm having the strangest thing with a DecimalFormat. I'm using it in an webapplication. I setup some test and it keeps on failing with me locally. A friend of me ran it and he was able to successfully ran the JUnit tests. The strange part is that on our server the application runs it perfectly without any problems either. Could it be that Java depends on the system settings like valuta and number settings? Or could there be another reason? This is how my piece of code looks like: public

问题 I wanted to see if anyone can explain why the following code works with valueOf but not others. import java.math.BigDecimal; public class Change { public static void main(String args[]) { double a = 4.00d; double b = 3.10d; BigDecimal a1 = new BigDecimal(a); BigDecimal b1 = new BigDecimal(b); BigDecimal diff = a1.subtract(b1); System.out.println("Double difference"); System.out.println(diff); float c = 4.00f; float d = 3.10f; BigDecimal a2 = new BigDecimal(c); BigDecimal b2 = new BigDecimal(d

问题 This question already has answers here : How do I print a double value without scientific notation using Java? (15 answers) Closed 4 years ago . I need to convert string value to double with dot. Here is simple code double dValue=Double.parseDouble("999999999.99"); System.out.println(dValue); output is: 9.9999999999E8 When i gave value like 10000 or 100000 it works. Help me to overcome this problem. 回答1: You could use BigDecimal and toPlainString() for that. BigDecimal dValue= new BigDecimal(

问题 I wanted to see if anyone can explain why the following code works with valueOf but not others. import java.math.BigDecimal; public class Change { public static void main(String args[]) { double a = 4.00d; double b = 3.10d; BigDecimal a1 = new BigDecimal(a); BigDecimal b1 = new BigDecimal(b); BigDecimal diff = a1.subtract(b1); System.out.println("Double difference"); System.out.println(diff); float c = 4.00f; float d = 3.10f; BigDecimal a2 = new BigDecimal(c); BigDecimal b2 = new BigDecimal(d

问题 I have a program that uses a formula to calculate the refurb on a unit (parts replaced on cableboxes that were damaged) divided by total units (cableboxes that went through refurb, but did not have any parts replaced). I looked up casting online, and the format for it is: int valuetoconvert = Convert.ToInt32; I'm doing that, but I still get the following error: Cannot implicitly convert type 'double to int. An explicit conversion exists(are you missing a cast?) What am I doing wrong? Can

问题 I have a UITextfield and it is being populated by data from database. The value is formatted in a way that the fractional part is separated by comma. So, the Structure is something like 1,250.50 I save the data in a string and when I try to use the doubleValue method to convert the string to a double or floating number. I am getting 1. Here is my code. NSString *price = self.priceField.text; //here price = 1,250.50 double priceInDouble = [price doubleValue]; Here I get 1 instead of 1250.50. I

问题 I have a UITextfield and it is being populated by data from database. The value is formatted in a way that the fractional part is separated by comma. So, the Structure is something like 1,250.50 I save the data in a string and when I try to use the doubleValue method to convert the string to a double or floating number. I am getting 1. Here is my code. NSString *price = self.priceField.text; //here price = 1,250.50 double priceInDouble = [price doubleValue]; Here I get 1 instead of 1250.50. I