dictionary

map function not working in React

由 怎甘沉沦 提交于 2021-02-04 14:02:03
问题 I am new to React JS, I was testing out some functions in fiddler. I am not sure why I get an error pointing to the map function. I am not able to render the array i defined. Relevant snippet: {this.props.data.productSpecs.map(function(productSpec){ <b>Category Name:</b> {productSpec}; })} Full code: var productCategory = { productName: 'SamamgaTV1', productCategory: 'Television', productSpecs: ['32inch','black','hd'] }; var ProductComponent = React.createClass({ render: function() { return(

Using Chinese to build a dictionary in Python

由 我是研究僧i 提交于 2021-02-04 13:53:29
问题 so this is my first time here, and also I am new to the world of Python. I am studying Chinese also and I wanted to create a program to review Chinese vocabulary using a dictionary. Here is the code that I normally use: #!/usr/bin/python # -*- coding:utf-8-*- dictionary = {"Hello" : "你好"} # Simple example to save time print(dictionary) The results I keep getting are something like: {'hello': '\xe4\xbd\xa0\xe5\xa5\xbd'} I have also trying adding a "u" to the beginning of the string with the

matplotlib bar plot add legend from categories dataframe column

由 。_饼干妹妹 提交于 2021-02-04 13:21:53
问题 I try to add the legend which should, according to my example, output: a red square with the word fruit and a green square with the word veggie. I tried several things (the example below is just 1 of the many trials), but I can't get it work. Can someone tell me how to solve this problem? import pandas as pd from matplotlib import pyplot as plt data = [['apple', 'fruit', 10], ['nanaba', 'fruit', 15], ['salat','veggie', 144]] data = pd.DataFrame(data, columns = ['Object', 'Type', 'Value'])

splitting a dictionary in python into keys and values

由 柔情痞子 提交于 2021-02-04 09:47:25
问题 How can I take a dictionary and split it into two lists, one of keys, one of values. For example take: {'name': 'Han Solo', 'firstname': 'Han', 'lastname': 'Solo', 'age': 37, 'score': 100, 'yrclass': 10} and split it into: ['name', 'firstname', 'lastname', 'age', 'score', 'yrclass'] # and ['Han Solo', 'Han', 'Solo', 36, 100, 10] Any ideas guys? 回答1: Not that hard, try help(dict) in a console for more info :) keys = dictionary.keys() values = dictionary.values() For both keys and values: items

In Python, I have a dictionary. How do I change the keys of this dictionary?

由 风格不统一 提交于 2021-02-02 19:55:03
问题 Let's say I have a pretty complex dictionary. {'fruit':'orange','colors':{'dark':4,'light':5}} Anyway, my objective is to scan every key in this complex multi-level dictionary. Then, append "abc" to the end of each key. So that it will be: {'fruitabc':'orange','colorsabc':{'darkabc':4,'lightabc':5}} How would you do that? 回答1: Keys cannot be changed. You will need to add a new key with the modified value then remove the old one, or create a new dict with a dict comprehension or the like. 回答2:

In Python, I have a dictionary. How do I change the keys of this dictionary?

由 大憨熊 提交于 2021-02-02 19:41:09
问题 Let's say I have a pretty complex dictionary. {'fruit':'orange','colors':{'dark':4,'light':5}} Anyway, my objective is to scan every key in this complex multi-level dictionary. Then, append "abc" to the end of each key. So that it will be: {'fruitabc':'orange','colorsabc':{'darkabc':4,'lightabc':5}} How would you do that? 回答1: Keys cannot be changed. You will need to add a new key with the modified value then remove the old one, or create a new dict with a dict comprehension or the like. 回答2:

C# 14道编程题练习

由 与世无争的帅哥 提交于 2021-02-02 15:31:20
C# 语言不允许 数值类型隐式转换为 char 类型 声明两个变量：int n1=10,n2=20;要求将两个变量交换，最后输出n1为20，n2为10。扩展（*）：不使用第三个变量如何交换？ using System; namespace ConsoleApp1 { class Program { static void Main(string[] args) { int n1 = 10, n2 = 20; n1 = n2 - n1; // n1 = 10 n2 = n2 - n1; // n2 = 10 n1 = n1 + n2; // n1 = 20 } } } 用方法来实现：将上题的交换操作封装成一个方法，方法有两个参数n1,n2，在方法中将n1和n2交换。（提示：使用ref）。 using System; namespace ConsoleApp1 { class Program { public static void swap(ref int A, ref int B) { A = B - A; // 10 B = B - A; // 10 A = A + B; // 20 } static void Main(string[] args) { int n1 = 10, n2 = 20; swap(ref n1, ref n2); Console.WriteLine(

How to optimised the conversion of nested into flat level dictionary in Python? [duplicate]

由 冷暖自知 提交于 2021-01-29 22:31:40
问题 This question already has answers here : What is the fastest way to flatten arbitrarily nested lists in Python? [duplicate] (3 answers) Closed 7 months ago . The objective is to convert the following nested dictionary secondary_citing_paper = [{"paper_href": 'Unique One', 'Paper_year': 1}, \ {"paper_href": 'Unique Two', 'Paper_year': 2}] inner_level = [secondary_citing_paper, secondary_citing_paper] my_dict_x = [inner_level, inner_level] into a flat level dictionary in Python (sorry for the

TypeError: Cannot read property 'map' of undefined, Is passing an array as a prop to a functional component not possible?

由 筅森魡賤 提交于 2021-01-29 22:11:08
问题 I am following a MERN stack tutorial in which a parent component Dashboard passes an array of objects from its own props (after mapStateToProps) to another component Education. Trying to iterate through this array in Education component gives me the above mentioned error. Please help, the tutorial seemed to have no errors and I have followed it perfectly so why the issue? <Education education={profile.education}/> (passing the prop in Dashboard.js) education is an array of objects inside an

Efficient way to modify a dictionary while comparing its items

由 假如想象 提交于 2021-01-29 20:27:36
问题 I have a dictionary with strings as keys and sets as values. These sets contain integers, which may be common for different items of the dictionary. Indeed, my goal is to compare each item against the rest and find those common numbers in the set values. Once located a pair of items that at least share a number in their value sets (lets say, (key1, val1) and (key2, val2) ), I want to add an extra item to the dictionary whose key is the concatenation of both keys key1 and key2 (I DO NOT CARE
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