dense-rank

问题 I am trying to build a dense rank kind of functionality but not exactly dense rank. I want to rank each group but within each group I want to keep the rank same for same values. I've written the following query which gives me a dense rank kind of functionality SELECT id, item_code @curRank := @curRank + 1 AS rank FROM table t, (SELECT @curRank := 0) r WHERE <several filters> Whereas, I want this The closest question I found is this one MySQL give a rank to each group Please help. 回答1: You can

来源： https://stackoverflow.com/questions/63527035/how-to-do-a-countdistinct-using-window-functions-with-a-frame-in-sql-server

来源： https://stackoverflow.com/questions/63527035/how-to-do-a-countdistinct-using-window-functions-with-a-frame-in-sql-server

问题 Coming from this answer: Rank based on two columns I've the following example: CREATE TABLE tmpPoradi (`player` int, `wins` int, `diff` int) ; INSERT INTO tmpPoradi (`player`, `wins`, `diff`) VALUES (1, 10, 12), (2, 8, 2), (3, 10, 10), (4, 8, 1), (5, 8, 7), (6, 10, 14), (8, 10, 10), (7, 12, 3) ; and the desired result must be: +--------+------+------+------+ | player | wins | diff | rank | +--------+------+------+------+ | 7 | 12 | 3 | 1 | | 6 | 10 | 14 | 2 | | 1 | 10 | 12 | 3 | | 3 | 10 | 10

问题 Coming from this answer: Rank based on two columns I've the following example: CREATE TABLE tmpPoradi (`player` int, `wins` int, `diff` int) ; INSERT INTO tmpPoradi (`player`, `wins`, `diff`) VALUES (1, 10, 12), (2, 8, 2), (3, 10, 10), (4, 8, 1), (5, 8, 7), (6, 10, 14), (8, 10, 10), (7, 12, 3) ; and the desired result must be: +--------+------+------+------+ | player | wins | diff | rank | +--------+------+------+------+ | 7 | 12 | 3 | 1 | | 6 | 10 | 14 | 2 | | 1 | 10 | 12 | 3 | | 3 | 10 | 10

问题 I have a table (called users) I need rank of users based on their score but I want rank on the bases of users max score. +-----------+------------+ | User_id | Score | +-----------+------------+ | 1 | 12258 | | 1 | 112 | | 2 | 9678 | | 5 | 9678 | | 3 | 689206 | | 3 | 1868 | Expect result +-----------+------------+---------+ | User_id | Score | Rank | +-----------+------------+---------+ | 3 | 689206 | 1 | | 1 | 12258 | 2 | | 2 | 9678 | 3 | | 5 | 9678 | 3 | 回答1: You are looking for DENSE_RANK

问题 I have a table (called users) I need rank of users based on their score but I want rank on the bases of users max score. +-----------+------------+ | User_id | Score | +-----------+------------+ | 1 | 12258 | | 1 | 112 | | 2 | 9678 | | 5 | 9678 | | 3 | 689206 | | 3 | 1868 | Expect result +-----------+------------+---------+ | User_id | Score | Rank | +-----------+------------+---------+ | 3 | 689206 | 1 | | 1 | 12258 | 2 | | 2 | 9678 | 3 | | 5 | 9678 | 3 | 回答1: You are looking for DENSE_RANK

问题 I'm using the dense_rank function in SQL to solve the leetcode 'rank scores' problem(https://leetcode.com/problems/rank-scores/description/): select Score, dense_rank() over (order by Score) Rank from Scores order by Score desc It always give me the following error: Line 2: SyntaxError: near '(order by Score) Rank from Scores order by Score desc' I wonder how to make this answer correct? Thanks a lot! Also, I realized most people use an answer without using the DENSE_RANK function, which is

问题 I'm using the dense_rank function in SQL to solve the leetcode 'rank scores' problem(https://leetcode.com/problems/rank-scores/description/): select Score, dense_rank() over (order by Score) Rank from Scores order by Score desc It always give me the following error: Line 2: SyntaxError: near '(order by Score) Rank from Scores order by Score desc' I wonder how to make this answer correct? Thanks a lot! Also, I realized most people use an answer without using the DENSE_RANK function, which is

问题 If I do a dense_rank() over (order by colname), I get the same rank for all rows with the same value in the column colname. However, I want to limit the number of rows with the same rank to @maxrows so that when @maxrows rows have the same value in colname, a new rank is assigned to the next row even if the value of colname is still the same. How can I achieve this? 回答1: You can achieve this via using several ranking functions. We use ROW_NUMBER() in the middle and another column to perform