date

Pandas return the next Sunday for every row

人盡茶涼 提交于 2020-08-27 21:27:01
问题 In Pandas for Python, I have a data set that has a column of datetimes in it. I need to create a new column that has the date of the following Sunday for each row. I've tried various methods trying to use iterrows and then figure out the day of the week, and add a day until the day is 7, but it hasn't worked and I'm not even sure how I'd return the date instead of just the day number then. I also don't feel like iterrows would be the best way to do it either. What is the best way to return a

Pandas return the next Sunday for every row

时光怂恿深爱的人放手 提交于 2020-08-27 21:26:30
问题 In Pandas for Python, I have a data set that has a column of datetimes in it. I need to create a new column that has the date of the following Sunday for each row. I've tried various methods trying to use iterrows and then figure out the day of the week, and add a day until the day is 7, but it hasn't worked and I'm not even sure how I'd return the date instead of just the day number then. I also don't feel like iterrows would be the best way to do it either. What is the best way to return a

Using std::chrono / date::gps_clock for converting a double gps timestamp to utc/tai

怎甘沉沦 提交于 2020-08-27 13:26:32
问题 I get a timestamp from a GPS device in a gps_data struct as a double. I'd like to convert this GPS timestamp to UTC and TAI times, something simple as: void handle_gps_timestamp(double timestamp) { double utc = utc_from_gps(timestamp); double tai = tai_from_gps(timestamp); do_stuff(gps, utc, tai); } Luckily I found Howard Hinnant's date and timezone library (proposed for C++20) that seems to provide this exact functionality. Unfortunately, at least from what I can see, the date/tz/chrono

Split a list of dates into subsets of consecutive dates

我们两清 提交于 2020-08-27 07:16:05
问题 I've got an array of dates that can contain multiple date ranges in it. dates = [ '2020-01-01', '2020-01-02', '2020-01-03', '2020-01-06', '2020-01-07', '2020-01-08' ] In this example, the list contains 2 separate consecutive date ranges (2020-01-01 to 2020-01-03 & 2020-01-06 to 2020-01-08) I'm attempting to figure out how I would loop through this list and find all the consecutive date ranges. One of the articles I'm looking at (How to detect if dates are consecutive in Python?) seems to have

Java 8 adding days with no time segments

雨燕双飞 提交于 2020-08-26 08:21:25
问题 Java 8 here. I'm trying to take the current Date (now), add one day to it, and get a new Date instance representing tomorrow that has no time component to it (only year, month & day). My best attempt: Calendar calendar = Calendar.getInstance(); calendar.add(Calendar.DAY_OF_YEAR, 1); Date tomorrow = calendar.getTime(); But when I print tomorrow , it contains a time component (example: Sat Jun 02 14:04:59 EDT 2018 ) whereas I just want it to contain zeroed-out values for hour/month/minute/etc

Current year with 4 digits in elm 0.19.1

折月煮酒 提交于 2020-08-25 07:05:51
问题 How can I do a function to get the current year with 4 digits using ELM 0.19.1? I have read something but nothing works with 0.19.1. Signature: getCurrentYear : Int Execution: getCurrentYear => 2020 Edit: Maybe executing new Date().getFullYear() javascript code? 回答1: The simplest way would be to pass the year in via flags when you start the app, since the current year isn't likely to change in the course of the application running. In that case, you can use the snippet of JavaScript you

Compare dates in Lua

笑着哭i 提交于 2020-08-24 08:34:32
问题 I have a variable with a date table that looks like this * table: [day] * number: 15 [year] * number: 2015 [month] * number: 2 How do I get the days between the current date and the date above? Many thanks! 回答1: You can use os.time() to convert your table to seconds and get the current time and then use os.difftime() to compute the difference. see Lua Wiki for more details. reference = os.time{day=15, year=2015, month=2} daysfrom = os.difftime(os.time(), reference) / (24 * 60 * 60) -- seconds

Compare dates in Lua

只愿长相守 提交于 2020-08-24 08:31:29
问题 I have a variable with a date table that looks like this * table: [day] * number: 15 [year] * number: 2015 [month] * number: 2 How do I get the days between the current date and the date above? Many thanks! 回答1: You can use os.time() to convert your table to seconds and get the current time and then use os.difftime() to compute the difference. see Lua Wiki for more details. reference = os.time{day=15, year=2015, month=2} daysfrom = os.difftime(os.time(), reference) / (24 * 60 * 60) -- seconds

Delete expired posts in wordpress by date meta data custom field

↘锁芯ラ 提交于 2020-08-24 03:17:00
问题 ---Resolved: Code Works as shown--- I have this piece of code that I think should work, but alas... If anyone could take a peek and see if there something obvious. I have reviewed a lot of resources on the wordpress codex, but have tried all I can think of. // expired_post_delete hook fires when the Cron is executed add_action( 'expired_post_delete', 'delete_expired_posts' ); // This function will run once the 'expired_post_delete' is called function delete_expired_posts() { $todays_date =

Determine if a day is a business day in Python / Pandas

牧云@^-^@ 提交于 2020-08-22 09:47:18
问题 I currently have a program setup to run two different ways. One way is to run over a specified time frame, and the other way is to run everyday. However, when I have it set to run everyday, I only want it to continue if its a business day. Now from research I've seen that you can iterate through business days using Pandas like so: start = 2016-08-05 end = datetime.date.today().strftime("%Y-%m-%d") for day in pd.bdate_range(start, end): print str(day) + " is a business Day" And this works