Determine if a day is a business day in Python / Pandas

问题

I currently have a program setup to run two different ways. One way is to run over a specified time frame, and the other way is to run everyday. However, when I have it set to run everyday, I only want it to continue if its a business day. Now from research I've seen that you can iterate through business days using Pandas like so:

start = 2016-08-05
end = datetime.date.today().strftime("%Y-%m-%d")

for day in pd.bdate_range(start, end):
    print str(day) + " is a business Day"

And this works great when I run my program over the specified period.

But when I want to have the program ran everyday, I can't quite figure out how to test one specific day for being a business day. Basically I want to do something like this:

start = datetime.date.today().strftime("%Y-%m-%d")
end = datetime.date.today().strftime("%Y-%m-%d")

if start == end:
    if not Bdate(start)
        print "Not a Business day"

I know I could probably setup pd.bdate_range() to do what I'm looking for, but in my opinion would be sloppy and not intuitive. I feel like there must be a simpler solution to this. Any advice?

回答1:

Since len of pd.bdate_range() tells us how many business days are in the supplied range of dates, we can cast this to a bool to determine if a range of a single day is a business day:

def is_business_day(date):
    return bool(len(pd.bdate_range(date, date)))

回答2:

Using at least numpy version 1.7.0., try np.is_busday()

start = datetime.date.today().strftime("%Y-%m-%d")
end = datetime.date.today().strftime("%Y-%m-%d")

if start == end:

    # added code here
    if not np.is_busday(start):
        print("Not a Business day")

回答3:

I just found a different solution to this. This might be interesting if you want to find the next business day if your date is not a business day.

   bdays=BDay()
   def is_business_day(date):
       return date == date + 0*bdays

adding 0*bdays rolls forward on the next business day including the current one. Unfortunately, subtracting 0*bdays does not roll backwards (at least with the pandas version I was using)

回答4:

Please check this module - bdateutil

Please check the below code using above module :

from bdateutil import isbday
from datetime import datetime,date
now = datetime.now()
val = isbday(date(now.year, now.month, now.day))
print val

Please let me know if this help.

回答5:

for me I use an old trick from Excel:

from pandas.tseries.offsets import Day, BDay

def is_bday(x):
    return x == x + Day(1) - BDay(1)

回答6:

There is builtin method to do this in pandas.

For Pandas version <1.0

from pandas.tseries.offsets import Day, BDay
from datetime import date


bdays=BDay()
is_business_day = bday.onOffset(date(2020,8,20))

For Pandas version >=1.1.0 (onOffset is deprecated)

from pandas.tseries.offsets import Day, BDay
from datetime import date


bdays=BDay()
is_business_day = bday.is_on_offset(date(2020,8,20))

来源：https://stackoverflow.com/questions/39067626/determine-if-a-day-is-a-business-day-in-python-pandas

标签

python

date

datetime

pandas