circuit-diagram

Writing an expression using only NAND, OR, XNOR

瘦欲@ 提交于 2020-02-23 07:34:13
问题 I have a 2-1 mux and I'm trying to write z = s'd0 + sd1 using only NAND , XNOR , and OR gates (not necessarily all of them). I tried simplifying it and what I ended up with is z = NAND(NAND(s', d0), NAND(s, d1)) , but I can't use NOT ( ' ), so is there a way to write NAND(s', d0) without the NOT ? 回答1: You can build NOT from NAND: NAND(X,X) == NOT(X) 回答2: NAND gate is an universal gate; you can use it to make any other gate. s' = nand(s,s) 回答3: Initial solution Full version of the solution

Electronic cIrcuit diagram component connection algorithm [closed]

╄→尐↘猪︶ㄣ 提交于 2019-12-21 10:46:33
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 6 years ago . I am creating a web-service which is aimed to simulate how do electronic circuits work. The project is not even in the Alpha stage yet. I am stuck with some important milestone of the project: when one tries to connect one component's pin to some other pin - the connection line

Should I eliminate inputs in a logic circuit design?

空扰寡人 提交于 2019-12-11 10:16:57
问题 Recently I had an exam where we were tested on logic circuits. I encountered something on that exam that I had never encountered before. Forgive me for I do not remember the exact problem given and we have not received our grade for it; however I will describe the problem. The problem had a 3 or 4 inputs. We were told to simplify then draw a logic circuit design for that simplification. However, when I simplified, I ended up eliminating the other inputs and ended up literally with just A I

Electronic cIrcuit diagram component connection algorithm [closed]

蓝咒 提交于 2019-12-04 04:25:32
I am creating a web-service which is aimed to simulate how do electronic circuits work. The project is not even in the Alpha stage yet. I am stuck with some important milestone of the project: when one tries to connect one component's pin to some other pin - the connection line should be built. First of all, the connection line was just a straight line, without almost any way to change it. Then it became somehow bended line with the possibility to add, move and delete points, which determined how the line is bended. And now it (connection line) is created using the A* algorithm. The