button

How to get position of a button in an array on mouse clicked

岁酱吖の 提交于 2020-01-06 06:32:22
问题 I have the code that creates a grid of buttons from an array . I need to get their possitions in array on mouse clicked event . Any ideas or links to some other post/articles would be very helpful. The code for creating the grid: // Creating buttons array for 5x5 grid Button[] tiles25 = new Button[25]; // Generating 5x5 button grid void Spawn5x5Grid() { // position of the firts tile int x = 35, y = 55; // current tile index int count = 0; for (int i = 1; i < 6; i++) { for (int j = 1; j < 6; j

How to achieve same like Segemented button with toggle button(sugg) ,change to next onclicked

為{幸葍}努か 提交于 2020-01-06 06:12:26
问题 As learnt from previous question of mine(how to change segmented button to next on clicked) , I used a Segmented button to do so as: My expected results were: when Next is pressed INDICATOR2 should be active and on second press INDICATOR3 should be active. when on INDICATOR2 if Previous is pressed both INDICATOR2 and INDICATOR1 (which is current one) should be active. As I am using segmented button here, the 2) can't be achieved ,and also was suggested using a toggle button would do instead a

Getting and error I cannot fix when trying to add a button column

落爺英雄遲暮 提交于 2020-01-06 06:09:38
问题 I am having trouble fixing an error that I keep getting when I try to add a button column to my table. The error is: Argument 1: cannot convert from 'System.Windows.Forms.DataGridViewButtonColumn' to 'System.Web.UI.WebControls.DataControlField' It is basically saying that I cannot use the local variable 'btn' in the line gridViewStudent.Columns.Add(btn); in the following code: gridViewStudent.DataSource = table; gridViewStudent.DataBind(); DataGridViewButtonColumn btn = new

Why does Dreamweaver cc16, Bootstrap v3.3.6, created, hyperlinked Button work in Opera & Chrome but not IE or Firefox?

浪尽此生 提交于 2020-01-06 06:02:13
问题 Why does a Dreamweaver cc16, Bootstrap v3.3.6, created, hyperlinked Button set into a PHP 7 created html page, work in current version Opera & Chrome browsers but not in current version IE or Firefox browsers? Page in question is: https://howtoliveoffthegridnow.com/index.php The Button in question has the text: => FREE: 11 Things To Know Before Going Off The Grid The Button html code is: => `<div align="center" style="font-size: 1.5em"> <button type="button" class="btn btn-lg"> <a href="https

How do I go to another view in swiftUI programmatically using Button (action:{}) {}?

余生长醉 提交于 2020-01-06 05:25:14
问题 I am trying to programmatically change views in my macOS application. I found stuff like NavigationLink and others but I am not allowed to use them. The code to switch must be in Button's action, because this way I know that I can quickly switch from the code, even if it is not in button format. How can I do this? Button in ContentView.swift: Button(action: { //What goes here. Tried Settings(), didn't work }) { Text("Settings") }.buttonStyle(PlainButtonStyle()) Settings.swift: import SwiftUI

How to prevent cells from mirroring button pressed action in another cell?

自古美人都是妖i 提交于 2020-01-06 05:24:05
问题 I have 3 buttons in the cells of my tableview, they buttons are in a @IBAction button collection so when one is selected it turns the button color from blue to red and deselects the button previously pressed to back to blue. the code works fine when performing those actions the problem that im having is that when a button is selected in one cell, the exact same button will be selected in another cell as shown below▼ so far what ive tried isn't working and I think what might work is that I to

Python Tkinter Button with If Else statements

泪湿孤枕 提交于 2020-01-06 04:42:43
问题 I want to bind the Start_Button with 2 possible functions: If Choice_1_Button is clicked and then the Start_Button , the Start_Button should call foo1 . But when the user clicks Choice_2_Button then the same Start Button should call foo2 . Here is the code I currently have: from tkinter import * root=Tk() Choice_1_Button=Button(root, text='Choice 1', command=something) #what should it do? Choice_2_Button=Button(root, text='Choice 2', command=something_else) Start_Button=Button(root, text=

Why do i have to cast a Button?

牧云@^-^@ 提交于 2020-01-06 04:06:06
问题 This must be a really dumb question because I cant find an answer online.... I know that casting is changing one datatype to another. How is this button ever changing it's data dype? Button button = (Button)findViewById(R.Bla.Bla) Why cant we just write Button button = New Button() And then assign the xml to it another way? Please explain, I'm lost. 回答1: See In Android You can create the UI Elements in two ways: 1. create UI elements through layouts (.xml) files. And to use them in java class

The count number of pressed button

你说的曾经没有我的故事 提交于 2020-01-06 03:51:05
问题 I need that when I press the button to show me how many times was the button pressed. I use this method, but on console still show me the number 1. Here is code: button_help.setOnMousePressed(new EventHandler<MouseEvent>() { @Override public void handle(MouseEvent event) { int count = 0; count ++; System.out.println(count); } }); 回答1: Your solution doesn´t work as you are reseting the value of variable every time you click button. You have to define it once and than just increase the valu of

What is the difference between command and bind in tkinter?

醉酒当歌 提交于 2020-01-06 03:07:06
问题 I'm trying to make a button print a string when it's pressed and print another when it's released. I know about the command atribute and the bind method, but I would like to know if it's possible to accomplish it only using atributes or if I have to use methods. With this piece of code: class motor: def __init__(eleMesmo, eixo , valorZero): eleMesmo.eixo = eixo eleMesmo.zero = valorZero def aumenta(self): print(self.eixo + str(self.zero+5)) def diminui(self): print(self.eixo + str(self.zero-5